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Q: If log 64 = 1.8061, then the value of log 16 will be (approx)?

  • 1
    1.9048
  • 2
    1.2040
  • 3
    0.9840
  • 4
    1.4521
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Answer : 2. "1.2040"
Explanation :

Answer: B) 1.2040 Explanation: Given that, log 64 = 1.8061  i.e log43=1.8061  --> 3 log 4 = 1.8061 --> log 4 = 0.6020 --> 2 log 4 = 1.2040 ⇒log42=1.2040 Therefore, log 16 = 1.2040

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