A quantitative aptitude test is a systematic means of testing a job candidate's abilities to perform specific tasks and react to a range of different situations.

Practice quantitative aptitude questions with answers to solve aptitude-based problems asked in competitive exams. Quantitative aptitude questions are asked in SSC, Bank Exams, UPS Exams, RPSC Exams, Railways Exams, IAS, RAS and in approx all the Competitive exams. Keep up to date with quantitative aptitude problems with us.

Recently Added Questions in Quantitative Aptitude

Q: What was the day of the week on 17th June, 1998 ? 457 2

  • 1
    Monday
    Correct
    Incorrect
  • 2
    Tuesday
    Correct
    Incorrect
  • 3
    Wednesday
    Correct
    Incorrect
  • 4
    Friday
    Correct
    Incorrect
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Answer : 3. "Wednesday"
Explanation :

Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.

Q: 1.12.91 is the first Sunday. Which is the fourth Tuesday of December 91 ? 275 1

  • 1
    17.12.91
    Correct
    Incorrect
  • 2
    24.12.91
    Correct
    Incorrect
  • 3
    27.12.91
    Correct
    Incorrect
  • 4
    31.12.91
    Correct
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Answer : 2. "24.12.91"
Explanation :

Q: If the true discount on sum due 2 years hence at 14% per annum be Rs. 168, the sum due is ? 1.3K 2

  • 1
    Rs.948
    Correct
    Incorrect
  • 2
    Rs.876
    Correct
    Incorrect
  • 3
    Rs.768
    Correct
    Incorrect
  • 4
    Rs.658
    Correct
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Answer : 3. "Rs.768"
Explanation :

Answer: C) Rs.768 Explanation: P.W. = 100×T.DR×T = 100×16814×2 = 600. Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.

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Answer : 3. "118.08L"
Explanation :

Answer: C) 118.08L Explanation: The amount of petrol left after 4 operations   = 200 × 1-402004   = 200 × 454   = 200 × 256625   = 81.92 litres   Hence the amount of kerosene = 200 - 81.92 = 118. 08 litres

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Answer : 2. "25%"
Explanation :

Answer: B) 25% Explanation: When the water is freely available and all the water is sold at the price of the milk, then the water gives the profit on the cost of 20 litres of milk.     Since,    the profit % = ProfitCostPricex100 Therefore, profit percentage = 520x100  = 25%

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Answer : 1. "1.25 kg"
Explanation :

Answer: A) 1.25 kg Explanation: Let the initial amount of honey in the jar was k, then    512 = k1 - 154 or  512 = k454   => k = 512 × 625256  => k = 1250    Hence initially the honey in the jar = 1.25 kg

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  Report Error : What was the day of the week on 17th June, 1998 ?

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  Report Error : 1.12.91 is the first Sunday. Which is the fourth Tuesday of December 91 ?

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  Report Error : If the true discount on sum due 2 years hence at 14% per annum be Rs. 168, the sum due is ?

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  Report Error : From a tank of petrol, which contains 200 litres of petrol, the seller replaces each time with kerosene when he sells 40 litres of petrol(or its mixture). Everytime he sells out only 40 litres of petrol(pure or impure). After replacing the petrol with kerosen 4th time, the total amount of kerosene in the mixture is

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  Report Error : A milkman has 20 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk. If the cost of pure milk is Rs. 18 per litre, then the profit of the milkman, when he sells all the mixture at  cost price, is:

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  Report Error : A jar was full with honey. A person used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar solution. The initial amount of honey in the jar was:

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