Aptitude Questions Practice Question and Answer
8Q: If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ? 2211 15b5cc74ae4d2b4197774fabd
5b5cc74ae4d2b4197774fabd- 1Rs. 175false
- 2Rs. 325false
- 3Rs. 340true
- 4Rs. 260false
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Answer : 3. "Rs. 340"
Explanation :
Answer: C) Rs. 340 Explanation: Assume first child (the youngest) get = Rs. x According to the question ;each son having Rs. 30 more than the younger one Second child will get = Rs. x + 30 Third child will get = Rs. x + 30 + 30 = x + 60 Forth child will get = Rs. x + 30 + 30 + 30 = x + 90 Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120 Total amount they got = Rs. 2000 x + (x+30) + (x+60) + (x+90) + (x+120) = 20005x + 300 = 20005x = 1700x = Rs. 340So the youngest child will get Rs. 340.
Q: The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ? 1481 15b5cc72ce4d2b4197774f79c
5b5cc72ce4d2b4197774f79c- 142.2 mtsfalse
- 233.45 mtsfalse
- 366.6 mtstrue
- 458.78 mtsfalse
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Answer : 3. "66.6 mts"
Explanation :
Answer: C) 66.6 mts Explanation: From above diagramAC represents the hill and DE represents the tower Given that AC = 100 m angleXAD = angleADB = 30° (∵ AX || BD ) angleXAE = angleAEC = 60° (∵ AX || CE) Let DE = h Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1) tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)∵ BD = CE and Substitute the value of CE from equation 1 100/√3 = 100−h(√3) => h = 66.66 mts The height of the tower = 66.66 mts.
Q: If a quarter kg of carrots costs 60 paise, how many paise will 200 gms cost ? 1622 05b5cc6d7e4d2b4197774e70a
5b5cc6d7e4d2b4197774e70a- 178 paisefalse
- 248 paisetrue
- 354 paisefalse
- 462 paisefalse
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Answer : 2. "48 paise"
Explanation :
Answer: B) 48 paise Explanation: Quarter of Kg means 250 gm Less weight, less price (Direct Proportion) So, 250 : 200 :: 60 : x => x = 48 So 200 gm will cost 48 paise.
Q: A flagstaff 17.5 m high casts a shadow of length 40.25 m. What will be the height of a building, which casts a shadow of length 28.75 m under similar conditions ? 1098 15b5cc6f4e4d2b4197774f013
5b5cc6f4e4d2b4197774f013- 114 cmfalse
- 213.5 cmfalse
- 312.5 cmtrue
- 411.4 cmfalse
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Answer : 3. "12.5 cm"
Explanation :
Answer: C) 12.5 cm Explanation: Let the required height of the building be x meter More shadow length, More height(direct proportion) Hence we can write as (shadow length) 40.25 : 28.75 :: 17.5 : x⇒ 40.25 × x = 28.75 × 17.5⇒ x = 28.75 × 17.5/40.25= 2875 × 175/40250= 2875 × 7/1610= 2875/230= 575/46= 12.5 cm
Q: The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ? 1588 15b5cc73ae4d2b4197774f8bf
5b5cc73ae4d2b4197774f8bf- 114th elementfalse
- 29th elementfalse
- 312th elementtrue
- 47th elementfalse
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Answer : 3. "12th element"
Explanation :
Answer: C) 12th element Explanation: If we consider the third term to be ‘x”The 15th term will be (x + 12d)6th term will be (x + 3d)11th term will be (x + 8d) and 13th term will be (x + 10d).Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.x + 9d will be the 12th term. Thus, 12th term of the A.P will be zero.
Q: A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ? 3128 05b5cc6cde4d2b4197774e1c2
5b5cc6cde4d2b4197774e1c2- 11080 cmfalse
- 2180 mfalse
- 3108 mtrue
- 4118 cmfalse
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Answer : 3. "108 m"
Explanation :
Answer: C) 108 m Explanation: We know the rule that, At particular time for all object , ratio of height and shadow are same. Let the height of the pole be 'H' Then 188=H48 => H = 108 m.
Q: Solve the equation 122x+1 = 1 ? 3824 05b5cc6f4e4d2b4197774efd7
5b5cc6f4e4d2b4197774efd7- 1-1/2true
- 21/2false
- 31false
- 4-1false
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Answer : 1. "-1/2"
Explanation :
Answer: A) -1/2 Explanation: Rewrite equation as 122x+1 = 120 Leads to 2x + 1 = 0 Solve for x : x = -1/2
Q: In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ? 2151 05b5cc74ae4d2b4197774fa9a
5b5cc74ae4d2b4197774fa9a- 118false
- 214true
- 322false
- 424false
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Answer : 2. "14"
Explanation :
Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14