CAT Practice Question and Answer
8Q: 9 tens 10 ones equals 2659 05b5cc626e4d2b4197774b83c
5b5cc626e4d2b4197774b83c- 1910false
- 290false
- 391false
- 4100true
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Answer : 4. "100"
Explanation :
Answer: D) 100 Explanation: 9 tens 10 ones equals => 9 x 10 + 10 x 1 => 90 + 10 => 100.
Q: An employee may claim Rs. 7.00 for each km when he travels by taxi and Rs. 6.00 for each km if he drives his own car. If in one week he claimed Rs. 595 for traveling 90 km. How many kms did he travel by taxi ? 2658 05b5cc736e4d2b4197774f87e
5b5cc736e4d2b4197774f87e- 155 kmstrue
- 235 kmsfalse
- 325 kmsfalse
- 465 kmsfalse
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Answer : 1. "55 kms"
Explanation :
Answer: A) 55 kms Explanation: Let x and y be the respective km's travelled by man via taxi and by his own car.Given x + y = 90 => x = 90 - yBut according to the question,7x + 6y = 5957(90-y) + 6y = 595=> 630 - 7y + 6y = 595=> y = 630 - 595 = 35=> x = 90 - 35 = 55Therefore, the distance travelled by taxi is 55 kms.
Q: A contractor undertook to complete a piece of work in 120 Days and employed 140 men upon it. At the end of 66 days only half of the work was done,so he put on 25 extra men. By how much time did he exceed the specific time ? 2657 05b5cc709e4d2b4197774f2ad
5b5cc709e4d2b4197774f2ad- 12 daystrue
- 23 daysfalse
- 34 daysfalse
- 45 daysfalse
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Answer : 1. "2 days"
Explanation :
Answer: A) 2 days Explanation: work done=total number of person x number of days;half of work done = 140 x 66;For half of remaining work 25 extra men are added.Therefore, total men for half work remaining = 140 + 25 = 165;Let 2nd half work will be completed in K days;140 x 66 = 165 x KK = 122;Hence, extra days => 122-120 = 2days.
Q: Find the missing number in the given number series? 514, 470, ?, 415, 404 2656 05b5cc6a9e4d2b4197774cf19
5b5cc6a9e4d2b4197774cf19- 1441false
- 2437true
- 3426false
- 4420false
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Answer : 2. "437"
Explanation :
Answer: B) 437 Explanation: Given number series is 514 470 ? 415 404 Here the pattern it follows is 514 514 - 44 = 470 470 - 33 = 437 437 - 22 = 415 415 - 11 = 404 Hence, the missing number in the given number series is 437.
Q: Rajesh rows in still water with a speed of 4.5 kmph to go to a certain place and comes back. Find his average speed for the whole journey, if the river is flowing with a speed of 1.5 kmph? 2653 05b5cc67ee4d2b4197774c245
5b5cc67ee4d2b4197774c245- 12 kmphfalse
- 24 kmphtrue
- 36 kmphfalse
- 48 kmphfalse
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Answer : 2. "4 kmph"
Explanation :
Answer: B) 4 kmph Explanation: Let the distance in one direction = k kms Speed in still water = 4.5 kmph Speed of river = 1.5 Hence, speed in upstream = 4.5 - 1.5 = 3 kmph Speed in downstream = 4.5 + 1.5 = 6 kmph Time taken by Rajesh to row upwards = k/3 hrs Time taken by Rajesh to row downwards = k/6 hrs Now, required Average speed =Total distanceTotal speed = 2kk3 + k6 = 2k x 186k + 3k = 4 kmph Therefore, the average speed of the whole journey = 4kmph.
Q: The Famous 'Golconda Fort' is located in which state ? 2653 05b5cc788e4d2b419777502c7
5b5cc788e4d2b419777502c7- 1Punjabfalse
- 2Telanganatrue
- 3Goafalse
- 4Andhra Pradeshfalse
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Answer : 2. "Telangana"
Explanation :
Answer: B) Telangana Explanation:
Q: How many 6-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that the digits should not repeat and the second last digit is even ? 2650 05b5cc731e4d2b4197774f7bf
5b5cc731e4d2b4197774f7bf- 1521false
- 2720true
- 3420false
- 4225false
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Answer : 2. "720"
Explanation :
Answer: B) 720 Explanation: Let last digit is 2when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways.so for last digit = 2, total numbers=240 Similarly for 4 and 6When last digit = 4, total no. of ways =240and last digit = 6, total no. of ways =240so total of 720 even numbers are possible.
Q: One paper is equally folded 35 times, then what is the new thickness of the paper ? 2649 05b5cc74ae4d2b4197774fa8b
5b5cc74ae4d2b4197774fa8b- 1T(2^50)true
- 250Tfalse
- 32 x 50 Tfalse
- 4T/50false
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Answer : 1. "T(2^50)"
Explanation :
Answer: A) T(2^50) Explanation: Let initial thickness of the paper be 'T'after first fold it will be '2T' = 21Tafter second fold it will be '4T' = 22T after 50th fold it will be T x (250T)