CAT Practice Question and Answer
8Q: An employee may claim Rs. 7.00 for each km when he travels by taxi and Rs. 6.00 for each km if he drives his own car. If in one week he claimed Rs. 595 for traveling 90 km. How many kms did he travel by taxi ? 2876 05b5cc736e4d2b4197774f87e
5b5cc736e4d2b4197774f87e- 155 kmstrue
- 235 kmsfalse
- 325 kmsfalse
- 465 kmsfalse
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Answer : 1. "55 kms"
Explanation :
Answer: A) 55 kms Explanation: Let x and y be the respective km's travelled by man via taxi and by his own car.Given x + y = 90 => x = 90 - yBut according to the question,7x + 6y = 5957(90-y) + 6y = 595=> 630 - 7y + 6y = 595=> y = 630 - 595 = 35=> x = 90 - 35 = 55Therefore, the distance travelled by taxi is 55 kms.
Q: How many four digit even numbers can be formed using the digits {2, 7, 5, 3, 9, 1} ? 2876 05b5cc6d7e4d2b4197774e705
5b5cc6d7e4d2b4197774e705- 159false
- 260true
- 361false
- 464false
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Answer : 2. "60"
Explanation :
Answer: B) 60 Explanation: The given digits are 1, 2, 3, 5, 7, 9 A number is even when its units digit is even. Of the given digits, two is the only even digit.Units place is filled with only '2' and the remaining three places can be filled in ⁵P₃ ways. Number of even numbers = ⁵P₃ = 60.
Q: Find the Odd One Out? 4, 6, 12, 30, 81, 315. 2875 05b5cc6aae4d2b4197774cf56
5b5cc6aae4d2b4197774cf56- 16false
- 212false
- 381true
- 4315false
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Answer : 3. "81"
Explanation :
Answer: C) 81 Explanation: Given the number series is 4, 6, 12, 30, 81, 315. Here it follows a pattern that 4 4 x 1.5 = 6 6 x 2 = 12 12 x 2.5 = 30 30 x 3 = 90 not equals to 81 90 x 3.5 = 315 Hence the odd one in the series is 81.
Q: Gujarat is noted for the cultivation of 2874 35b5cc7ece4d2b41977751c09
5b5cc7ece4d2b41977751c09- 1Cottontrue
- 2Sugarcanefalse
- 3Saffronfalse
- 4Jutefalse
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Answer : 1. "Cotton"
Explanation :
Answer: A) Cotton Explanation: Black soil coupled with favorable climatic conditions (Temperature of 21-320C and 30 -100 cm of rainfall) are responsible for cotton cultivation in Gujarat.
Q: A shop keeper sells an article at a loss of 8%, but when he increases the selling price of the article by Rs. 164 he earns a profit of 2.25% on the cost price. If he sells the same article at Rs. 1760, what is his profit percentage? 2873 05b5cc62ae4d2b4197774b89f
5b5cc62ae4d2b4197774b89f- 12.5%false
- 25%false
- 310%true
- 47.5%false
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Answer : 3. "10%"
Explanation :
Answer: C) 10% Explanation: According to the given data, Let Cost price of the article be 'cp' Then, 102.25 cp - 92 cp = 164 x 100 10.25 cp = 16400 cp = 1600 Now, if he sells at Rs. 1760 Profit = 1760 - 1600 = 160 Profit% = 160/1600 x 100 = 10%.
Q: A box contains 4 different black balls, 3 different red balls and 5 different blue balls. In how many ways can the balls be selected if every selection must have at least 1 black ball and one red ball ? 2870 05b5cc6f4e4d2b4197774f004
5b5cc6f4e4d2b4197774f004- 124 - 1false
- 22425-1false
- 3(24-1)(23-1)25true
- 4Nonefalse
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Answer : 3. "(24-1)(23-1)25"
Explanation :
Answer: C) C Explanation: It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects. Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection. Hence, we can select 1 black ball from 4 black ballsor 2 black balls from 4 black balls.or 3 black balls from 4 black balls.or 4 black balls from 4 black balls. Hence, number of ways in which we can select the black balls = 4C1 + 4C2 + 4C3 + 4C4= 24-1 ........(A) Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection. Hence, we can select 1 red ball from 3 red ballsor 2 red balls from 3 red ballsor 3 red balls from 3 red balls Hence, number of ways in which we can select the red balls= 3C1 + 3C2 + 3C3=23-1........(B) Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)or 1 blue ball from 5 blue ballsor 2 blue balls from 5 blue ballsor 3 blue balls from 5 blue ballsor 4 blue balls from 5 blue ballsor 5 blue balls from 5 blue balls. Hence, number of ways in which we can select the blue balls= 5C0 + 5C1 + 5C2 + … + 5C5= 25..............(C) From (A), (B) and (C), required number of ways= 2524-123-1
Q: How many remainders are possible if 16n is divided by 9 for any positive integral value of n ? 2870 05b5cc77ae4d2b41977750151
5b5cc77ae4d2b41977750151- 11false
- 22false
- 33true
- 44false
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Answer : 3. "3"
Explanation :
Answer: C) 3 Explanation: When 16nis divided by 9, we have 1619, remainder = 7 1629, remainder = 4 1639, remainder = 1 1649, remainder = 7 1659, remainder = 4 1669, remainder = 1 So, we have cyclicity of 3 factors i.e 7,4,1. Hence only 3 remainders are possible.
Q: Which of the following is not an aerosol? 2865 05b5cc699e4d2b4197774c691
5b5cc699e4d2b4197774c691- 1mudtrue
- 2dustfalse
- 3smokefalse
- 4fogfalse
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Answer : 1. "mud"
Explanation :
Answer: A) mud Explanation: Among the given options, mud is not an aerosol. An aerosol is a suspension of fine solid particles or liquid droplets, in the air or another gas. Aerosols can be natural or anthropogenic. Examples of natural aerosols are fog, dust, forest exudates and geyser steam. Examples of anthropogenic aerosols are haze, particulate air pollutants, and smoke.

