CAT Practice Question and Answer
8Q: The sum of three consecutive multiples of 3 is 72. What is the second largest number ? 2361 05b5cc6d8e4d2b4197774e7ba
5b5cc6d8e4d2b4197774e7ba- 127false
- 224true
- 321false
- 442false
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Answer : 2. "24"
Explanation :
Answer: B) 24 Explanation: Let the numbers be 3x, 3x + 3 and 3x + 6.Then,3x + (3x + 3) + (3x + 6) = 729x = 63x = 7Largest number = 3x + 6 = 27. => Second largest number = 27 - 3 = 24
Q: If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ? 2360 05b5cc73ae4d2b4197774f8a1
5b5cc73ae4d2b4197774f8a1- 131/25false
- 215/17true
- 314/25false
- 411/16false
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Answer : 2. "15/17"
Explanation :
Answer: B) 15/17 Explanation: The original fraction is 2551 × 350+100150+100 = 15/17.
Q: Find the missing number in the following Series ? 18, 97, 26, 91, ? , 83 2358 05b5cc6c2e4d2b4197774dbaf
5b5cc6c2e4d2b4197774dbaf- 132false
- 236false
- 330false
- 434true
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Answer : 4. "34"
Explanation :
Answer: D) 34 Explanation: The given series follows the pattern that, 18, 97, 26, 91, ?, 83 => 18 + 8 = 26 => 97 - 8 = 91 => 26 + 8 = 34 => 91 - 8 = 83 Hence, the missing number is 34.
Q: 88 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be ? 2355 05b5cc723e4d2b4197774f659
5b5cc723e4d2b4197774f659- 1112 mtsfalse
- 284 mtstrue
- 396 mtsfalse
- 4108 mtsfalse
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Answer : 2. "84 mts"
Explanation :
Answer: B) 84 mts Explanation: Vol of silver = πR2h = 66 C.C Given D= 1mm => R = D/2 = 1/20 cm => 227×1202×h = 66 = 66 x 400 x (7/22) = 8400 cm = 84 mtrs.
Q: What is the antonym of "Censure" ? 2353 05b5cc77fe4d2b41977750188
5b5cc77fe4d2b41977750188- 1commendfalse
- 2augmentfalse
- 3enthraltrue
- 4reformfalse
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Answer : 3. "enthral"
Explanation :
Answer: C) enthral Explanation: "Censure" means expressing formal disapproval. "Enthral" means spellbound or enchant, which is farthest in meaning to the given word.
Q: The ratio of boys and girls in a school is 9:5.If the total number of students in the school is 1050.Then number of boys is 2352 05b5cc6b8e4d2b4197774d642
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Answer :
Explanation :
Let the ratio be 'R' Total number of students = 1050 Then, 9R + 5R = 1050 14R = 1050 => R = 75 Hence, the number of boys = 9R = 9 x 75 = 675
Q: K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ? 2350 05b5cc741e4d2b4197774f9e5
5b5cc741e4d2b4197774f9e5- 112 pmtrue
- 21 pmfalse
- 311 amfalse
- 411:30 amfalse
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Answer : 1. "12 pm"
Explanation :
Answer: A) 12 pm Explanation: let 't' be the time after which they met since L starts. Given K is 50% faster than L 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that L starts So they meet at (9 + 3)hrs = 12:00 noon.
Q: A can build a wall in 16 days while B can destroy it in 8 days. A worked for 5 days. Then B joined with A for the next 2 days. Find in how many days could A build the remaining wall ? 2348 05b5cc6cee4d2b4197774e208
5b5cc6cee4d2b4197774e208- 112 daysfalse
- 214 daysfalse
- 313 daystrue
- 416 daysfalse
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Answer : 3. "13 days"
Explanation :
Answer: C) 13 days Explanation: Now, Total work = LCM(16, 8) = 48 A's one day work = + 48/16 = + 3 B's one day work = - 48/8 = -6 Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15 2days B joined with A in working = 2(3 - 6) = - 6 Remaining Work of building wall = 48 - (15 - 6) = 39 Now this remaining work will be done by A in = 39/3 = 13 days.