CAT प्रश्न और उत्तर का अभ्यास करें
8प्र: 3131×31-27 =? 2609 05b5cc783e4d2b419777501e2
5b5cc783e4d2b419777501e2- 1961 x 861false
- 2961 x 961true
- 3961 x 2false
- 429791false
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उत्तर : 2. "961 x 961"
व्याख्या :
Answer: B) 961 x 961 Explanation: We know that am×an=am+n ∴3131-27 = 314 = 961 x 961.
प्र: They come out at night without being called and are lost in the day without being stolen. What are they? 2609 05b5cc69ce4d2b4197774c862
5b5cc69ce4d2b4197774c862- 1Lightfalse
- 2Batsfalse
- 3Starstrue
- 4Flightsfalse
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उत्तर : 3. "Stars"
व्याख्या :
Answer: C) Stars Explanation: Stars are what that come out at night without being called and are lost in the day without being stolen.
प्र: A person says that his son is 5 times as old as his daughter and his wife is 5 times older than his son and he is twice the age of his wife . The sum total of all the ages equals the age of the grand mother who celebrated her 81st birthday today. How old was his son? 2609 05b5cc715e4d2b4197774f413
5b5cc715e4d2b4197774f413- 150 yrstrue
- 225 yrsfalse
- 372 yrsfalse
- 440 yrsfalse
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उत्तर : 1. "50 yrs"
व्याख्या :
Answer: A) 50 yrs Explanation: Let the daughter age be 'x'Therefore, Son age = 5x, Mother age = 25x, Person age = 50x. Thus we get, x+5x+25x+50x = 8181x = 81x = 1 Daughter's age = 1, Son's = 5, Mother's = 25, Person's age = 50.
प्र: What is the probability that a leap year has 53 Saturdays and 52 Sundays ? 2608 05b5cc6dfe4d2b4197774eada
5b5cc6dfe4d2b4197774eada- 11/7true
- 22/7false
- 31/2false
- 43/2false
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उत्तर : 1. "1/7"
व्याख्या :
Answer: A) 1/7 Explanation: A leap year has 52 weeks and two daysTotal number of cases = 7Number of favourable cases = 1i.e., {Friday, Saturday} Required Probability = 1/7
प्र: 80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ? 2604 05b5cc6d3e4d2b4197774e4c8
5b5cc6d3e4d2b4197774e4c8- 1120 litfalse
- 2140 litfalse
- 3110 litfalse
- 4150 littrue
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उत्तर : 4. "150 lit"
व्याख्या :
Answer: D) 150 lit Explanation: To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres. => the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity. i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too. Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.
प्र: A passenger train covers the distance between station K and L, 40 minutes faster than a goods train. Find this distance between K and L if the average speed of the passenger train is 50 km/h and that of goods train is 30 km/h? 2603 05b5cc6b4e4d2b4197774d4c5
5b5cc6b4e4d2b4197774d4c5- 150 kmstrue
- 248 kmsfalse
- 346 kmsfalse
- 444 kmsfalse
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उत्तर : 1. "50 kms"
व्याख्या :
Answer: A) 50 kms Explanation: Let the distance be 'd' kms. According to the given data, d30 - d50 = 4060 hrs=> 6d = 300=> d = 50 kms.
प्र: Ravi and Ramu are partners in a business.Ravi contributes 1/6 of the capital for 16 months and Ramu received 2/3 of the profit. For how long Ramu's money was used ? 2602 05b5cc71ee4d2b4197774f590
5b5cc71ee4d2b4197774f590- 111 monthsfalse
- 210 monthsfalse
- 39 monthsfalse
- 48 monthstrue
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उत्तर : 4. "8 months"
व्याख्या :
Answer: D) 8 months Explanation: Let the total Profit be Z.Ramu's profit share is 2/3 of profit (i.e 2Z/3)Ravi's profit is (Z-2Z/3) =Z/3Hence the profit ratio is , Ravi : Ramu = Z/3 : 2Z/3 = 1:2 Let total Capital be Rs.X and Ramu has contributed for Y months.Since Ramu's profit share is 2/3, his invest share will be 2/3 in capital. Ravi's invest for 16 months / Ramu's invest for Y months = Ravi's profit share / Ramu's profit sharei.e. (X/6 x 16) / (2X/3 x Y) = 1/2 Solving the above equation, we get Y = 8.So Ramu's money has been used for 8 months.
प्र: The sum of three consecutive odd numbers is 93. What is the middle number? 2601 05b5cc6b7e4d2b4197774d5e7
5b5cc6b7e4d2b4197774d5e7- 131true
- 233false
- 329false
- 427false
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उत्तर : 1. "31"
व्याख्या :
Answer: A) 31 Explanation: Let the three consecutive odd numbers be x, x+2, x+4 Then, x + x + 2 + x + 4 = 93 => 3x + 6 = 93 => 3x = 87 => x = 29 => 29, 31, 33 are three consecutive odd numbers. Therefore, the middle number is 31.

