CAT Practice Question and Answer
8Q: What is the equivalent compound ratio of 5:6::7:10::6:5 ? 2003 05b5cc6e3e4d2b4197774eccf
5b5cc6e3e4d2b4197774eccf- 17 : 9false
- 29 : 7false
- 37 : 4false
- 47 : 10true
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Answer : 4. "7 : 10"
Explanation :
Answer: D) 7 : 10 Explanation: Given 5:6 :: 7:10 :: 6:5 We know that compound ratio is calculated as a:b :: c:d :: e:f(axcxe):(bxdxf) => (5x7x6):(6x10x5)=> (210):(300)= 7:10
Q: Car is to garage as aeroplane is to 2002 05b5cc65ee4d2b4197774be20
5b5cc65ee4d2b4197774be20- 1Hangartrue
- 2Portfalse
- 3Harbourfalse
- 4Depotfalse
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Answer : 1. "Hangar"
Explanation :
Answer: A) Hangar Explanation: We park car temporarily in garrage, similarly, aeroplane is temporarily parked in hangar.
Q: K and L starts walking towards each other at 4 pm at speed of 3 km/hr and 4 km/hr respectively. They were initially 17.5 km apart. At what time do they meet ? 2002 05b5cc6c6e4d2b4197774ddfa
5b5cc6c6e4d2b4197774ddfa- 16:00 amfalse
- 26:30 pmtrue
- 35:45 amfalse
- 45:52 pmfalse
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Answer : 2. "6:30 pm"
Explanation :
Answer: B) 6:30 pm Explanation: Suppose they meet after 'h' hours Then 3h + 4h = 17.5 7h = 17.5 h = 2.5 hours So they meet at => 4 + 2.5 = 6:30 pm
Q: Oldest Oil Field in India 2001 05b5cc6b9e4d2b4197774d748
5b5cc6b9e4d2b4197774d748- 1Mumbai High, Maharashtrafalse
- 2Anleshwar, Gujaratfalse
- 3Digboi, Assamtrue
- 4Nonefalse
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Answer : 3. "Digboi, Assam"
Explanation :
Answer: C) Digboi, Assam Explanation: Digboi has the distinction of being India's oldest continuously producing oilfield. Digboi refinery, now a division of Indian Oil Corporation, had a capacity of about 0.65 MMTPA as of 2003. Digboi is now Headquarter of Assam Oil Division of Indian Oil Corporation Limited, though the crude production is not high today.
Q: Q's mother is sister of P and daughter of M who is brother of R. S is daughter of P and sister of T. How is M related to T ? 2000 05b5cc73de4d2b4197774f957
5b5cc73de4d2b4197774f957- 1Grand fathertrue
- 2Grand motherfalse
- 3Grand father or Grand motherfalse
- 4Can't be determinedfalse
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Answer : 1. "Grand father"
Explanation :
Answer: A) Grand father Explanation: Q's mother is sister of P and daughter of M => P is the child of M.S is daughter of P and sister of T, so P is parent of T too.M ----> parent --------> P ------------>parent -------------> TBut given M is brother of R => M is male. So, M is grandfather of T.
Q: 7 years ago, the ratio of the ages of Anirudh to that of Bhavana, was 7:9. Chandhu is 12 years older than Anirudh and 12 years younger than Bhavana. What is Chandhu's present age? 2000 05b5cc6bbe4d2b4197774d849
5b5cc6bbe4d2b4197774d849- 191 yearsfalse
- 2115 yearsfalse
- 3103 yearstrue
- 4Can't be determinedfalse
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Answer : 3. "103 years"
Explanation :
Answer: C) 103 years Explanation: Let present Anirudh's age be 'A' and Bhavana's age be 'B' Given seven years, their ratio is 7:9 => A-7 : B-7 = 7 : 9 => 9A - 7B = 14 .......(1) And given, Chandhu is 12 years older than A nad 12 years younger than B => C = A + 12....(2) => B = C + 12 => B = A + 12 + 12 .....(From (2)) => B = A + 24 ....(3) Put (3) in (1) 9A - 7(A+24) = 14 9A - 7A - 168 = 14 2A = 182 => A = 91 years => C = A + 12 = 91 +12 = 103 years.
Q: Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ? 1999 05b5cc75ee4d2b4197774fc9d
5b5cc75ee4d2b4197774fc9d- 1Rs.2010false
- 2Rs.2200false
- 3Rs.2000true
- 4Rs.2100false
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Answer : 3. "Rs.2000"
Explanation :
Answer: C) Rs.2000 Explanation: Let money invested by Raghu = Rs. xMoney invested by Trishul = 9/10 x = 0.9xMoney invested by Vishal = 9/10x * 110/100 = 0.99xAlso, x+0.9x+0.99x = 5780= x= 5780/2.89 = 2000 Therefore, amount invested by Raghu is Rs. 2000.
Q: If sum of upstream and downstream speed of a boat is 82 kmph, and the boat travels 105 km. upstream in 3 hr, Find the time taken by boat to cover 126 km downstream. 1999 05b5cc6afe4d2b4197774d278
5b5cc6afe4d2b4197774d278- 12.8 hrsfalse
- 22.7 hrstrue
- 32.6 hrsfalse
- 42.5 hrsfalse
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Answer : 2. "2.7 hrs"
Explanation :
Answer: B) 2.7 hrs Explanation: Let Speed of boat in still water = b Let Speed of still water = w Then we know that, Speed of Upstream = U = boat - water Speed of Downstream = D = boat + water Given, U + D = 82 b - w + b + w = 82 2b = 82 => b = 41 kmph From the given data, 41 - w = 105/3 = 35 w = 6 kmph Now, b + w = 126/t => 41 + 6 = 126/t => t = 126/47 = 2.68 hrs.