CAT प्रश्न और उत्तर का अभ्यास करें
8प्र: A boy can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is ? 6909 05b5cc6d4e4d2b4197774e5ca
5b5cc6d4e4d2b4197774e5ca- 11.8 kmphfalse
- 22 kmphfalse
- 32.2 kmphfalse
- 41.5 kmphtrue
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उत्तर : 4. "1.5 kmph"
व्याख्या :
Answer: D) 1.5 kmph Explanation: Speed of Boy is B = 4.5 kmph Let the speed of the stream is S = x kmph Then speed in Down Stream = 4.5 + x speed in Up Stream = 4.5 - x As the distance is same, => 4.5 + x = (4.5 - x)2 => 4.5 + x = 9 -2x 3x = 4.5 x = 1.5 kmph
प्र: How many such pairs of digits are there in the number 421579368 each of which has as many digits between them in the number as when they are arranged in ascending order? 6894 05b5cc7f2e4d2b41977751e93
5b5cc7f2e4d2b41977751e93- 1Nonefalse
- 2Onefalse
- 3Twofalse
- 4Threetrue
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उत्तर : 4. "Three"
व्याख्या :
Answer: D) Three Explanation: Given Number: 4 2 1 5 7 9 3 6 8 Ascending order: 1 2 3 4 5 6 7 8 9 Hence the required pairs are 12, 49, 16
प्र: A sweet seller sells 3/5th part of sweets at a profit of 10% and remaining at a loss of 5%. If the total profit is Rs 1500, then what is the total cost price of sweets ? 6892 05b5cc75ee4d2b4197774fc93
5b5cc75ee4d2b4197774fc93- 1Rs.37,500true
- 2Rs.36,400false
- 3Rs.37,415false
- 4Rs.36,500false
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उत्तर : 1. "Rs.37,500"
व्याख्या :
Answer: A) Rs.37,500 Explanation: Assume A be the cost price. Therefore,35×A×10100 - 25×A×5100 = 1500 => A = Rs 37,500.
प्र: A Shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net Profit or loss that he makes? 6886 05b5cc7bbe4d2b419777509d7
5b5cc7bbe4d2b419777509d7- 14%true
- 25%false
- 36%false
- 48%false
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उत्तर : 1. "4%"
व्याख्या :
Answer: A) 4% Explanation: SP of first article = Rs.1000 Profit = 20% CP = SP x 100100+P% = Rs. 25003 SP of Second Article = Rs.1000 Loss = 20% CP = SP x 100100-L% = Rs. 1250 So, Total SP = Rs.2000; Total CP = Rs.6250/3 As the CP is more than SP, he makes a loss. Loss = CP - SP = (6250/3) - 2000 = Rs.(250/3) So, Loss Percent = Lossx100/CP = 4%
प्र: Kempegowda Festival was organized in which city ? 6881 05b5cc6eee4d2b4197774eef5
5b5cc6eee4d2b4197774eef5- 1Hyderabadfalse
- 2Delhitrue
- 3Mumbaifalse
- 4Chennaifalse
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उत्तर : 2. "Delhi"
व्याख्या :
Answer: B) Delhi Explanation: President Pranab Mukherjee inaugurated the Kempegowda Festival in New Delhi. The festival is organised by the NadaprabhuKempegowda Foundation.
प्र: Find the next number in the series 5, 8, 16, 19, 57, 60, ..... 6854 05b5cc76fe4d2b4197774ff62
5b5cc76fe4d2b4197774ff62- 1188false
- 2256false
- 3240true
- 4180false
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उत्तर : 3. "240"
व्याख्या :
Answer: C) 240 Explanation: The pattern is x1+3, x 2, x1+3, x 3, x1+3, x 4 The next number=60x4=240
प्र: A number of cats got together and decided to kill between them 999919 rats. Every cat killed an equal number of rats. Each cat killed more rats than there were cats. How many rats do you think that each cat killed ? 6836 05b5cc731e4d2b4197774f7d8
5b5cc731e4d2b4197774f7d8- 11009true
- 2991false
- 32000false
- 41000false
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उत्तर : 1. "1009"
व्याख्या :
Answer: A) 1009 Explanation: Given total number of rats = 999919 999919 = 1000000 - 81 = 10002 - 92 = (1000+9)(1000-9) = 1009 x 991.Since there were more rats than there were cats, 991 cats killed 1009 rats each.
प्र: एक वेब पेज का उपयोग कर स्थित है 6772 05b5cc639e4d2b4197774baa5
5b5cc639e4d2b4197774baa5- 1यूनिवर्सल रिकॉर्ड लोकेटरfalse
- 2यूनिवर्सल रिसोर्स लोकेटरtrue
- 3यूनिफ़ॉर्म रिकॉर्ड लिंकिंगfalse
- 4यूनिवर्सल रिकॉर्ड लिंकिंगfalse
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उत्तर : 2. "यूनिवर्सल रिसोर्स लोकेटर"
व्याख्या :
Answer: B) यूनिवर्सल रिसोर्स लोकेटर स्पष्टीकरण: एक वेब पेज एक यूआरएल (यूनिवर्सल रिसोर्स लोकेटर) का उपयोग कर स्थित है। यूनिवर्सल रिसोर्स लोकेटर को वेब एड्रेस के रूप में भी जाना जाता है। यह मूल रूप से एक वेब संसाधन को संदर्भित करता है जो कंप्यूटर के नेटवर्क पर इसके स्थान के विनिर्देशन के लिए है। यह एक तंत्र भी है जिसके माध्यम से जानकारी प्राप्त की जा सकती है।

