CAT प्रश्न और उत्तर का अभ्यास करें
8प्र: Electrical Pressure is also called 1770 05b5cc6afe4d2b4197774d200
5b5cc6afe4d2b4197774d200- 1Currentfalse
- 2Voltagetrue
- 3Resistancefalse
- 4Powerfalse
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उत्तर : 2. "Voltage"
व्याख्या :
Answer: B) Voltage Explanation: Electrical Pressure is also called as Voltage. Voltage is measured in Volts. Volt : A unit of electrical pressure or Voltage is called Volt. One volt is the amount of pressure required to cause one ampere of current to flow against one ohm of resistance. Voltage is also referred to as Electromotive Force or Electrical Potential or Electrical Pressure.
प्र: An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ? 1770 05b5cc73de4d2b4197774f911
5b5cc73de4d2b4197774f911- 121.4 and 42.8false
- 225.2 and 50.4false
- 331.4208 and 62.8416true
- 433.12 and 66.24false
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उत्तर : 3. "31.4208 and 62.8416"
व्याख्या :
Answer: C) 31.4208 and 62.8416 Explanation: Birds speeds in mtrs/sec is 'x' and '2x' .While flying from Engine to end, relative speed = (x+10) m/secfrom end to engine, flying speed = (2x - 10) mtr/secso 1000/(x+10) + 1000/(2x-10) = 187.5 secssolving it, we getso x = 8.728 m/sec and 2x= 17.456 m/sec x = 31.4208 km/hr and 2x = 62.8416 km/hr.
प्र: What was the purpose of the double v campaign? 1769 05b5cc68be4d2b4197774c395
5b5cc68be4d2b4197774c395- उत्तर देखेंउत्तर छिपाएं
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उत्तर :
व्याख्या :
The Double V Campaign was used in World War II. The purpose of the double v campaign is to fight for victory and ending segregation at home. It was aimed at African-Americans, and it first appeared in an African-American newspaper, the Pittsburgh Courier, in 1942. The Double V Campaign worked to have a victory over racism abroad and racism in the United States.It stood so it gave a chance for Black Americans to fight in the war so they could achieve Victory at Home and Abroad- (Civil Rights then the war in the Atlantic and Pacific).
प्र: What does PMKSY stands for ? 1769 05b5cc6cae4d2b4197774dfde
5b5cc6cae4d2b4197774dfde- 1Pradhan Mantri Kaushal Sampada Yojanafalse
- 2Pradhan Mantri Kalyan Sampada Yojanafalse
- 3Pradhan Mantri Kisan Sampada Yojanatrue
- 4Pradhan Mantri Kisan Seva Yojanafalse
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उत्तर : 3. "Pradhan Mantri Kisan Sampada Yojana"
व्याख्या :
Answer: C) Pradhan Mantri Kisan Sampada Yojana Explanation:
प्र: How many squares do you see? 1769 05b5cc699e4d2b4197774c724
5b5cc699e4d2b4197774c724- 144false
- 245true
- 346false
- 450false
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उत्तर : 2. "45"
व्याख्या :
Answer: B) 45 Explanation: Number of squares in the given figure is 16 + 9 + 19 + 1 = 45.
प्र: Two pipes A and B can fill a tank in 15 min and 20 min respectively. Both the pipes are opened together but after 4 min, pipe A is turned off. What is the total time required to fill the tank ? 1769 05b5cc6e0e4d2b4197774eb48
5b5cc6e0e4d2b4197774eb48- 115 min 20 sec.false
- 216 min 40 sec.false
- 313 min 10 sec.false
- 414 min 40 sec.true
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उत्तर : 4. "14 min 40 sec."
व्याख्या :
Answer: D) 14 min 40 sec. Explanation: Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15 Remaining part = 1 - 7/15 = 8/15 Part filled by B in 1 minute = 1/20 1/20 : 8/15 :: 1 : k k = (8/15 )x 1 x 20 = 10( 2/3) min = 10 min 40 sec. The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec.
प्र: Who among the following introduced the subsidiary alliance system in India? 1769 05b5cc6bde4d2b4197774d8ed
5b5cc6bde4d2b4197774d8ed- 1Lord Cunninghamfalse
- 2Lord Clivfalse
- 3Lord Wellesleytrue
- 4Lord Canningfalse
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उत्तर : 3. "Lord Wellesley"
व्याख्या :
Answer: C) Lord Wellesley Explanation: The doctrine of the subsidiary alliance was introduced by Lord Wellesley, British Governor-General of India from 1798 to 1805. The Nizam of Hyderabad was the first to enter into such an alliance in 1798. Tipu Sultan of Mysore refused to do so, but after the British victory in the Fourth Anglo-Mysore War, Mysore was forced to become a subsidiary state in 1799. The Nawab of Awadh was the next to accept the Subsidiary Alliance, in 1801.
प्र: A problem is given to three students whose chances of solving it are 1/2, 1/3 and 1/4 respectively. What is the probability that the problem will be solved? 1769 05b5cc7d0e4d2b4197775122c
5b5cc7d0e4d2b4197775122c- 11/4false
- 21/2false
- 33/4true
- 47/12false
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उत्तर : 3. "3/4"
व्याख्या :
Answer: C) 3/4 Explanation: Let A, B, C be the respective events of solving the problem and A , B, C be the respective events of not solving the problem. Then A, B, C are independent event ∴A, B, C are independent events Now, P(A) = 1/2 , P(B) = 1/3 and P(C)=1/4 PA=12, PB=23, PC= 34 ∴ P( none solves the problem) = P(not A) and (not B) and (not C) = PA∩B∩C = PAPBPC ∵ A, B, C are Independent = 12×23×34 = 14 Hence, P(the problem will be solved) = 1 - P(none solves the problem) = 1-14= 3/4

