CAT Practice Question and Answer

Q: A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is red. 2189 0

  • 1
    23/42
    Correct
    Wrong
  • 2
    19/42
    Correct
    Wrong
  • 3
    7/32
    Correct
    Wrong
  • 4
    16/39
    Correct
    Wrong
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Answer : 2. "19/42"
Explanation :

Answer: B) 19/42 Explanation: A red ball can be drawn in two mutually exclusive ways  (i) Selecting bag I and then drawing a red ball from it.   (ii) Selecting bag II and then drawing a red ball from it.   Let E1, E2 and A denote the events defined as follows: E1 = selecting bag I, E2 = selecting bag II A = drawing a red ball Since one of the two bags is selected randomly, therefore  P(E1) = 1/2  and  P(E2) = 1/2 Now, PAE1 = Probability of drawing a red ball when the first bag has been selected = 4/7   PAE2  = Probability of drawing a red ball when the second bag has been selected = 2/6  Using the law of total probability, we have   P(red ball) = P(A) = PE1×PAE1+PE2×PAE2                              = 12×47+12×26=1942

Q: How many days in 4 years? 2188 0

  • 1
    1460
    Correct
    Wrong
  • 2
    1461
    Correct
    Wrong
  • 3
    1462
    Correct
    Wrong
  • 4
    1459
    Correct
    Wrong
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Answer : 1. "1460"
Explanation :

Answer: A) 1460 Explanation: Days in 4 years =>  Let the first year is Normal year i.e, its not Leap year. A Leap Years occurs once for every 4 years. 4 years => 365 + 365 + 365 + 366(Leap year) 4 years => 730 + 731 = 1461   Therefore, Number of Days in 4 Years = 1461 Days.

Q: The price of pulses has increased by 25%. The percentage of reduction that a family should effect in the use of pulses so as not to increase the expenditure on this account is ? 2188 0

  • 1
    16%
    Correct
    Wrong
  • 2
    20%
    Correct
    Wrong
  • 3
    84%
    Correct
    Wrong
  • 4
    72%
    Correct
    Wrong
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Answer : 2. "20%"
Explanation :

Answer: B) 20% Explanation: Reduction in consumption= P100+P X 100%= 25100+25 X 100%= 20%

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Answer : 3. "Only b follows"
Explanation :

Answer: C) Only b follows Explanation: Clearly, reducing the number of aspirants for admission to colleges or sending the students of well-to-do families to foreign countries for higher studies, is no proper solution. So, both I and III do not follow. The right solution is to increase the number of colleges so as t accommodate the increasing number of admission-seekers. So, only II follows.

Q: If 6 (P's Capital ) = 8 ( Q's Capital ) = 12 ( R's Capital ) , then out of the total profit of Rs 4650 , R will receive ? 2188 0

  • 1
    Rs. 1033.33
    Correct
    Wrong
  • 2
    Rs. 1024
    Correct
    Wrong
  • 3
    Rs. 1148.14
    Correct
    Wrong
  • 4
    Rs. 1245.32
    Correct
    Wrong
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Answer : 1. "Rs. 1033.33"
Explanation :

Answer: A) Rs. 1033.33 Explanation: Let P's capital = p, Q's capital = q and R's capital = r.Then 6p = 8q = 12r=> 3p = 4q = 6r=>q = 3p/4r = 3p/6 = p/2P : Q : R = p : 3p/4 : p/2= 4 : 3 : 2R's share = 4650 * (2/9) = 150*6 = Rs. 1033.33.

Q: Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to: 2188 0

  • 1
    596/9
    Correct
    Wrong
  • 2
    605/9
    Correct
    Wrong
  • 3
    645/9
    Correct
    Wrong
  • 4
    700/9
    Correct
    Wrong
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Answer : 4. "700/9"
Explanation :

Answer: D) 700/9 Explanation: Let Veena's weight = 1 kg Sana's weight = 2 kg Sneha's weight = 1.4 kg Rina's weight = 1.8 kg Now,according to the given data in the question, 1.8x100 = 1.4   x = 1.4 × 1001.8 = 7009 = 77 79.

Q: The shorter i am, the bigger i am. What am I? 2187 0

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Answer :
Explanation :

A Temper.

Q: Electrical Pressure is also called 2186 0

  • 1
    Current
    Correct
    Wrong
  • 2
    Voltage
    Correct
    Wrong
  • 3
    Resistance
    Correct
    Wrong
  • 4
    Power
    Correct
    Wrong
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Answer : 2. "Voltage"
Explanation :

Answer: B) Voltage Explanation: Electrical Pressure is also called as Voltage. Voltage is measured in Volts.   Volt : A unit of electrical pressure or Voltage is called Volt.   One volt is the amount of pressure required to cause one ampere of current to flow against one ohm of resistance.   Voltage is also referred to as Electromotive Force or Electrical Potential or Electrical Pressure.

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