CAT प्रश्न और उत्तर का अभ्यास करें
8प्र: Largest Mint in India is at 1861 05b5cc6b7e4d2b4197774d5d3
5b5cc6b7e4d2b4197774d5d3- 1Mumbaifalse
- 2Hyderabadfalse
- 3Noidafalse
- 4Kolkatatrue
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उत्तर : 4. "Kolkata"
व्याख्या :
Answer: D) Kolkata Explanation: The Largest Mint in India is Kolkata Mint. Government of India operates 4 Mints in the country for the production of Coins. They are at Hyderabad, Telangana Mumbai, Maharashtra Kolkata, West Bengal Noida, Uttar Pradesh.
प्र: Doctor : Nurse :: ? : Follower 1861 05b5cc69ae4d2b4197774c77d
5b5cc69ae4d2b4197774c77d- 1Managerfalse
- 2Employerfalse
- 3Workerfalse
- 4Leadertrue
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उत्तर : 4. "Leader"
व्याख्या :
Answer: D) Leader Explanation: Here the second one follows the first one. That is a nurse follows a doctor and similarly, a follower follows a leader. Hence, Doctor : Nurse :: Leader : Follower.
प्र: At what temperature do the Fahrenheit and celcius scales give the same reading? 1861 05b5cc7b6e4d2b4197775090a
5b5cc7b6e4d2b4197775090a- 1212 degreesfalse
- 232 degreeesfalse
- 3-40 degreeestrue
- 40 degreeesfalse
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उत्तर : 3. "-40 degreees"
व्याख्या :
Answer: C) -40 degreees Explanation: We want the temperature when F=C. We know that, F = C x 95 + 32 So substituting C For F, we have C = -40o Therefore, C = -40. Thus when C = -40, we have C = F
प्र: It costs Rs. p each to send the first thousand messsages and Rs. q to send each subsequent one . If r is greater than 1,000, how many Rupees will it cost to send r messages ? 1861 05b5cc6cfe4d2b4197774e2ef
5b5cc6cfe4d2b4197774e2ef- 11000 (r - p) + pqfalse
- 21000 p + qrfalse
- 31000 (r - q) + prfalse
- 41000(p - q) + qrtrue
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उत्तर : 4. "1000(p - q) + qr"
व्याख्या :
Answer: D) 1000(p - q) + qr Explanation: We need to find the total cost to send r messsages, r > 1000. The first 1000 messsages will cost Rs.p each (Or) The total cost of first 1000 messsages = Rs.1000p The remaining (r - 1000) messsages will cost Rs.q each (Or) The cost of the (r - 1000) = Rs.(r - 1000)y Therefore, total cost = 1000p + rq - 1000q = 1000(p - q) + qr
प्र: Carbon monoxide is a common atmospheric pollutant. 1860 05b5cc695e4d2b4197774c539
5b5cc695e4d2b4197774c539- 1TRUEtrue
- 2FALSE Answer & Explanation Answer:false
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उत्तर : 1. "TRUE"
व्याख्या :
Answer: A) TRUE Explanation: Carbon monoxide is one of the major pollutant present in the world. The six most common pollutants include ozone, carbon monoxide, sulfur dioxide, lead, nitrogen oxides, and particulate matter. Carbon monoxide is a common atmospheric pollutant. It is produced largely in combustion processes like in industries and in vehicles. It is a gas that cannot be seen nor smelled.
प्र: Raghu can complete a work in 12days working 9 hours a day. Arun can complete the same work in 8 days working 11 hours a day. If both Raghu and Arun work together, working 12 hours a day, in how many days can they complete the work ? 1860 05b5cc774e4d2b41977750034
5b5cc774e4d2b41977750034- 13449 daysfalse
- 212449 daysfalse
- 34349 daystrue
- 441249 daysfalse
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उत्तर : 3. "4349 days"
व्याख्या :
Answer: C) Option C Explanation: Raghu can complete the work in (12 x 9)hrs = 108 hrs. Arun can complete the work in (8 x 11)hrs = 88 hrs. Raghu's 1 hrs work = 1/108 and Arun's 1 hrs work = 1/88 (Raghu + Arun)'s 1 hrs work = 1108+188=492376 So, both Raghu and Arun will finish the work in 237649 hrs Number of days of 12 hours each=237649×112 = 19849=4349 days
प्र: K can finish the work in 18 days and L can do the same work in 15 days. L worked for 10 days and left the job. In how many days, K alone can finish the remaining work ? 1860 05b5cc774e4d2b4197775002f
5b5cc774e4d2b4197775002f- 15.5 daysfalse
- 26 daystrue
- 34.2 daysfalse
- 45 daysfalse
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उत्तर : 2. "6 days"
व्याख्या :
Answer: B) 6 days Explanation: L's 10 days work = 115×10=23 Remaining work = 1-23=13 Now, work is done by K in one day = 1/18 1/3 work is done by K in 18×13 = 6 days
प्र: How many minutes is it until 6 o'clock if 50 minutes ago it was 4 times as many minutes past 3 o'clock ? 1859 05b5cc711e4d2b4197774f3d2
5b5cc711e4d2b4197774f3d2- 126 mintrue
- 224 minfalse
- 322 minfalse
- 420 minfalse
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उत्तर : 1. "26 min"
व्याख्या :
Answer: A) 26 min Explanation: Let the required number of minutes = MTotal minutes between 3o'clock and 6o' clock = 180 minutesM + 50 + 4M = 1805M + 50 = 1805M = 130M = 26 minutes.

