CAT प्रश्न और उत्तर का अभ्यास करें
8प्र: What approximate value will come in place of question mark (?) in the following question ? (49.001)2 = ? 1712 05b5cc6c7e4d2b4197774dec3
5b5cc6c7e4d2b4197774dec3- 12500false
- 22400true
- 32600false
- 42300false
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उत्तर : 2. "2400"
व्याख्या :
Answer: B) 2400 Explanation: Given (49.001)2 = ? => =~ 49 x 49 =~ 2401 =~ 2400
प्र: A word arranging device rearranges words step-by-step in a particular order according to set of rules. The device stops when the final result is obtained.Input: but going for crept te light sirStep 1: crept but going for te light sirStep 2: crept going light but for te sirStep 3: crept going light but for sir teAnd Step 3 is the last step for this input. Now, find out an appropriate step in the following question following the above rules. Question:Input: more fight cats cough sough acts ideaWhat will be the last step for this input ? 1712 05b5cc771e4d2b4197774fff8
5b5cc771e4d2b4197774fff8- 1cough fight sough acts cats idea moretrue
- 2cough fight sough acts cats more ideafalse
- 3cough more fight sough acts idea catsfalse
- 4none of thesefalse
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 1. "cough fight sough acts cats idea more"
व्याख्या :
Answer: A) cough fight sough acts cats idea more Explanation: Carefully obsrving the given arrangement, we find the following pattern:We observe that,first all the words with the highest number of letters are arranged in the alphabetical order, followed by the words with the second highest number of letters and so on.However, the position of only one word is altered at each step.Input: more fight cats cough sough acts ideaStep1: cough more fight cats sough acts ideaStep2: cough fight more cats sough acts ideaStep3: cough fight sough more cats acts ideaStep4: cough fight sough acts more cats ideaStep5: cough fight sough acts cats more ideaStep6: cough fight sough acts cats idea more Hence, the answer is A
प्र: I am the first on Earth, the second in Heaven. I appear two times in a week you can only see me once in a year. Although I am in the middle of the sea, l am not found in month, but l am in February, June, September, October, November & December. Who am I? 1712 05b5cc6a6e4d2b4197774cd27
5b5cc6a6e4d2b4197774cd27- उत्तर देखेंउत्तर छिपाएं
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उत्तर :
व्याख्या :
The letter 'E'. As of the above given data, It is in the 1st place in Earth, 2nd in Heaven and in the middle of the Sea. It appears once in a Year and twice in a Week. It is present in February, June, September, October, November & December. But not in the Month. Hence, it is the letter 'E'.
प्र: The shorter i am, the bigger i am. What am I? 1711 05b5cc68be4d2b4197774c379
5b5cc68be4d2b4197774c379- उत्तर देखेंउत्तर छिपाएं
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उत्तर :
व्याख्या :
A Temper.
प्र: 92613 x 62742241 = ? + 89 Find the value of '?' 1711 05b5cc6bae4d2b4197774d7fd
5b5cc6bae4d2b4197774d7fd- 1166251false
- 2166259false
- 3166252true
- 4166253false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 3. "166252"
व्याख्या :
Answer: C) 166252 Explanation: Given 92613 x 62742241 = ? + 89 Using unit digit method, On LHS, 1 x 1 x 1 = 1 sqrt of last digit 1 => it must end with either 9 or 1 so now 1 x 1 = 1 1 x 9 = 9 On RHS, ? + 89 => ? = ...1 - 89 = last digit is 11- 9 = 2 or => ? = ...9 - 89 = last digit is 9 - 9 = 0 Here in the options last digit 2 is option C.
प्र: Two persons K and L can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 3 days ? 1711 05b5cc6d8e4d2b4197774e7aa
5b5cc6d8e4d2b4197774e7aa- 11/6true
- 21/3false
- 32/3false
- 41/18false
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उत्तर : 1. "1/6"
व्याख्या :
Answer: A) 1/6 Explanation: K's one day's work = 1/30 L's one day's work = 1/45 (K + L)'s one day's work = 1/30 + 1/45 = 1/18 The part of the work completed in 3 days = 3 (1/18) = 1/6.
प्र: What is the gram formula mass of K2CO3? 1710 05b5cc632e4d2b4197774b9b8
5b5cc632e4d2b4197774b9b8- 1147false
- 2138true
- 3129false
- 4116false
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उत्तर : 2. "138"
व्याख्या :
Answer: B) 138 Explanation: The gram formula mass of a compound is nothing but the molar mass. The molar mass of K2CO3 (Potassium Carbonate) is given by Atomic weights of individual elements are K (Potassium) = 39 g C (Carbon) = 12 g O (Oxygen) = 16 g Hence, that of K2CO3 = 39(2) + 12 + 16(3) = 78 + 12 + 48 = 138.
प्र: A wholesale dealer allows a discount of 20 % on the marked price to the retailer. The retailer sells at 5% below the marked price. If the customer pays Rs.19 for an article, what profit is made by the retailer on it ? 1710 05b5cc72ce4d2b4197774f7ab
5b5cc72ce4d2b4197774f7ab- 1Rs. 4false
- 2Rs. 3true
- 3Rs. 5false
- 4Rs. 1false
- उत्तर देखेंउत्तर छिपाएं
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उत्तर : 2. "Rs. 3"
व्याख्या :
Answer: B) Rs. 3 Explanation: Let wholesaler dealers marked price = 100%, Retailer's C.P = 80% And the retailer sells at 5% less than the marked price => S.P = 95%If S.P of 95% of the retailer costs Rs.19 to customer,so its C.P of 80% will cost 80 x 19/95 = 16 Profit made by the retailer = 19-16 = Rs.3

