Answer: D) 80 Explanation: If 'k' is number of students in P and 'l' is number of students in Q, then From the given conditions, we have=> k - 10 = l + 10 .......(1)=> k + 20 = 2(l - 20) ....(2) Solving these eqns, we get k = 100 and l = 80.Therefore, number of students in class Q is 80.

Answer: B) FALSE Explanation: These two events cannot be disjoint because P(K) + P(L) > 1. P(AꓴB) = P(A) + P(B) - P(AꓵB). An event is disjoint if P(A ꓵ B) = 0. If K and L are disjoint P(K ꓴ L) = 0.8 + 0.6 = 1.4 And Since probability cannot be greater than 1, these two mentioned events cannot be disjoint.

Answer: B) 1/8 Explanation: 125 over 1000 in Simplest Form means 1251000 in its simple fraction form.   Now, to get the simplest form of 125/1000, find the HCF or GCD of both numerator and denominator i.e, 125 and 1000.   HCF of 125, 1000 = 125   Then, divide both numerator and denominator by 125 i.e, 1251251000125 = 18   Hence, 18 is the simplest form of 125 over 1000.

Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.

Answer: C) 48.4 % Explanation: Let marked price = Rs. 100. Then, C.P. = RS. 54, S.P. = Rs. 85Gain % = 31/64 x 100 = 48.4%.

Answer: C) Peso Explanation:

Answer: B) 1962 Explanation: Arithmetic Series ::   An Arithmetic Series is a series of numbers in which each term increases by a constant amount.   How to find the sum of the Arithmetic Sequence or Series for the given Series ::   When the series contains a large amount of numbers, its impractical to add manually. You can quickly find the sum of any arithmetic sequence by multiplying the average of the first and last term by the number of terms in the sequence.   That is given by Sn = n(a1 + an)2 Where n = number of terms, a1 = first term, an = last term   Here Last term is given by an = a1 + n-1d where d = common difference   Now given Arithmetic Series is    2, 5, 8, 11,...   Here a1 = 2,  d = 3, n = 36    Now, an= a1 + n - 1d a36= 2 + 36 - 13 = 105 + 2 = 107    Now, Sum to 36 terms is given by   S36 = 36(2 + 107)2 = 36 x 1092 = 39242 = 1962       Therefore, Sum to 36 terms of the series 2, 5, 8, 11,... is 1962.

Answer: A) Saudi Arabia Explanation: