CAT प्रश्न और उत्तर का अभ्यास करें
8प्र: Why ABC computer is called so ? 4803 25b5cc6cbe4d2b4197774e0e0
5b5cc6cbe4d2b4197774e0e0- 1Because it was thought to be the first computer so named with first alphabets of Englishtrue
- 2Because it was developed by Atanasoff and Berryfalse
- 3Both of above are the reason to name the computer ABCfalse
- 4None of the abovefalse
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उत्तर : 1. "Because it was thought to be the first computer so named with first alphabets of English"
व्याख्या :
Answer: A) Because it was thought to be the first computer so named with first alphabets of English Explanation:
प्र: In certain language, CHAMPION is coded as HCMAIPNO, how is NEGATIVE coded in that code ? 4797 05b5cc77fe4d2b41977750197
5b5cc77fe4d2b41977750197- 1NEAGVEITfalse
- 2ENAGITEVtrue
- 3MGAETVIEfalse
- 4EGAITEVNfalse
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उत्तर : 2. "ENAGITEV"
व्याख्या :
Answer: B) ENAGITEV Explanation: The letters of the word are reversed in order, taking two at a time, to obtain the code.
प्र: Find the odd one out ? Hawk , Parrot , Owl , Eagle 4796 05b5cc76ae4d2b4197774fe9d
5b5cc76ae4d2b4197774fe9d- 1Eaglefalse
- 2Owlfalse
- 3Parrottrue
- 4Hawkfalse
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उत्तर : 3. "Parrot"
व्याख्या :
Answer: C) Parrot Explanation: All except Parrot are birds of prey.
प्र: Marathon is to race as Hibernation is to 4775 05b5cc6b5e4d2b4197774d510
5b5cc6b5e4d2b4197774d510- 1Eatfalse
- 2Sleeptrue
- 3Winterfalse
- 4Dreamfalse
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उत्तर : 2. "Sleep"
व्याख्या :
Answer: B) Sleep Explanation: Marathon is to Race as Hibernation is to Sleep. Marathon is a long race in the similar way Hibernation refers to a long sleep.
प्र: When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died ? 4768 05b5cc745e4d2b4197774fa18
5b5cc745e4d2b4197774fa18- 150 yrsfalse
- 260 yrstrue
- 370 yrsfalse
- 465 yrsfalse
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उत्तर : 2. "60 yrs"
व्याख्या :
Answer: B) 60 yrs Explanation: Let the Father be x years when he died Average Age 10 years ago be A Total Age 10 years ago = 6*A Total Age after 10 years(Just before father's Death) = 6A + 6*10 = 6A + 60 Father Died and Baby was born => the Total number of people in the family is Same (6) Baby born today so age of baby = 0 (6A +60 - x)/6 = 6A/6 => A + 10 -(x/6) = A => x/6 = 10 => x = 60 Therefore we can conclude that the father was 60 years old when he died.
प्र: Rotate : Energy :: Stop : ? 4758 05b5cc6a7e4d2b4197774ce40
5b5cc6a7e4d2b4197774ce40- 1Spinfalse
- 2Breakfalse
- 3Inertiatrue
- 4Nonefalse
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उत्तर : 3. "Inertia"
व्याख्या :
Answer: C) Inertia Explanation: To rotate is to energy to stop is to inertia. From the definition itself we know that inertia is a property by virtue of which a body continues to be in the state of rest or in state of motion. So over here whenever energy is supplied then the body starts to move that is a displacement is there and it is rotating where as whenever the body is stopped an inertia of rest is created. So, Rotate : Energy :: Stop : Inertia.
प्र: If the positions of the first and the third digit within each number are interchanged, which of the following will be the third digit of the second lowest number ? 987, 514, 658, 487, 404, 269 4747 05b5cc6f8e4d2b4197774f01d
5b5cc6f8e4d2b4197774f01d- 18false
- 29false
- 32false
- 44true
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उत्तर : 4. "4"
व्याख्या :
Answer: D) 4 Explanation: According to the question, after the position of the first and third digit interchanged new numbers are 789, 415, 856, 784, 404, 962 962, 856, 789, 784, 404, 415Here the second lowest number is 404 and the last digit of it is '4'.
प्र: Two trains namely X & Y leave station 'A' at 6.30am and 7.40am and travel at 30km/hr and 40 km/hr respectively. How many kms from 'A' will the trains meet ? 4746 05b5cc745e4d2b4197774fa5e
5b5cc745e4d2b4197774fa5e- 1140 kmstrue
- 2120 kmsfalse
- 396 kmsfalse
- 4142 kmsfalse
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उत्तर : 1. "140 kms"
व्याख्या :
Answer: A) 140 kms Explanation: It is given train X leave station A at 6:30 am, here it is asked to calculate the distance from A when the trains meet, theDistance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours = 30 x 7/6 = 35 kmSo train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr.Hence time taken = 35/10 = 3.5 hours or 3 hours 30 minutesSo distance from A = Distance traveled by 2nd train in 3 hr. 30 min = 40 x 3.5 = 140 km.

