CAT प्रश्न और उत्तर का अभ्यास करें
8प्र: The sum of the two digits of a number is 8. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number ? 1298 05b5cc6f8e4d2b4197774f072
5b5cc6f8e4d2b4197774f072- 128false
- 219false
- 337false
- 417true
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उत्तर : 4. "17"
व्याख्या :
Answer: D) 17 Explanation: Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.P + Q = 8 ----- (1)(10Q + P) - (10P + Q) = 549(Q - P) = 54(Q - P) = 6 ----- (2)Solve (1) and (2) P = 1 and Q = 7The required number is = 17
प्र: If in the following set of numbers, the first and the third digits are interchanged in each number, which number will be second from the end if arranged in ascending order after interchanging the digits ? 585 546 514 404 206 369 1297 05b5cc73de4d2b4197774f92f
5b5cc73de4d2b4197774f92f- 1404false
- 2585false
- 3415true
- 4602false
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उत्तर : 3. "415"
व्याख्या :
Answer: C) 415 Explanation: Given numbers are 585 546 514 404 206 369Then interchanging the 1st and 3rd digits of the given numbers, we get585 645 415 404 602 963Now, arranging them in ascending order963 645 602 585 415 404Then the last second number is 415.
प्र: World's smallest Computer is unveiled by 1297 05b5cc6a2e4d2b4197774cb12
5b5cc6a2e4d2b4197774cb12- 1Infosysfalse
- 2Intelfalse
- 3IBMtrue
- 4Microsoftfalse
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उत्तर : 3. "IBM"
व्याख्या :
Answer: C) IBM Explanation: IBM has unveiled the world's smallest computer - a device no bigger than a grain of salt. Presented at the company's Think 2018 conference in Las Vegas, Nevada, the unit measures just 1mm by 1mm but has the same processing power as the x86 chip that ran early Nineties IBM desktop computers.
प्र: 125% as a Fraction? 1296 05b5cc6aae4d2b4197774cf7f
5b5cc6aae4d2b4197774cf7f- 11/4false
- 23/4false
- 35/4true
- 47/4false
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उत्तर : 3. "5/4"
व्याख्या :
Answer: C) 5/4 Explanation: Literally any percentage means divide by 100. So 125% = 125100. That can be reduced to 5/4. To convert to a decimal, you can do long division, dividing 5 into 4.
प्र: Ozone hole refers to 1296 05b5cc6bbe4d2b4197774d82a
5b5cc6bbe4d2b4197774d82a- 1Decrease in the thickness of ozone layer in Stratospheretrue
- 2Increase in thickness of ozone layerfalse
- 3Decrease in the ozone layer in Tropospherefalse
- 4Hole in the ozone layerfalse
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उत्तर : 1. "Decrease in the thickness of ozone layer in Stratosphere"
व्याख्या :
Answer: A) Decrease in the thickness of ozone layer in Stratosphere Explanation:
प्र: Negative plus a positive equals 1295 05b5cc6a1e4d2b4197774cac7
5b5cc6a1e4d2b4197774cac7- 1negativefalse
- 2positivefalse
- 3zerofalse
- 4Can't be determinedtrue
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उत्तर : 4. "Can't be determined"
व्याख्या :
Answer: D) Can't be determined Explanation: We know that a negative value plus a positive value always count backward and the sign depends on the bigger value sign. When you are adding a negative number to a positive number, then the value counts backward and takes the sign of the biggest number. For example:: Adding -5 and +2 -5 + 2 = -3 (big number is 5 and its sign is '-') Adding -3 and +5 +5 + (-3) = 5 - 3 = +2(big number is 5 and it has sign '+').
प्र: What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad ? 1294 05b5cc723e4d2b4197774f65e
5b5cc723e4d2b4197774f65e- 1844false
- 2814true
- 3840false
- 4820false
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उत्तर : 2. "814"
व्याख्या :
Answer: B) 814 Explanation: Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.Area of each tile = (41 x 41) sq.cm Required number of tiles =1517 x 902/(41 x 41) = 814.
प्र: A seller charges 28% more from a customer as GST on an article. If customer paid Rs. 4544, what is the cost price of the article? 1294 05b5cc6b9e4d2b4197774d70c
5b5cc6b9e4d2b4197774d70c- 1Rs. 3550true
- 2Rs. 2650false
- 3Rs. 3840false
- 4Rs. 2450false
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उत्तर : 1. "Rs. 3550"
व्याख्या :
Answer: A) Rs. 3550 Explanation: Let the cost price of the article be 'P' Then from given data, P + 28P100 = 4544=> 128P = 454400=> P = 3550 Hence, the cost price of the article = P = Rs. 3550

