CAT Practice Question and Answer
8Q: The wildcard in a WHERE clause is useful when 3385 05b5cc65ee4d2b4197774be3b
5b5cc65ee4d2b4197774be3b- 1An exact match is not possible in a SELECT statement.true
- 2An exact match is necessary in a CREATE statement.false
- 3An exact match is not possible in a CREATE statement.false
- 4An exact match is necessary in a SELECT statement.false
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Answer : 1. "An exact match is not possible in a SELECT statement."
Explanation :
Answer: A) An exact match is not possible in a SELECT statement. Explanation:
Q: What is the IUPAC name of [Co (NH₃)₄Cl₂ ]Cl? 1617 05b5cc65ee4d2b4197774be40
5b5cc65ee4d2b4197774be40- 1Tetra-ammine dichloro cobalt (III) chloridetrue
- 2Tetra-ammine trichloro cobalt (III)false
- 3Tri-ammine dichloro cobalt (III) chloridefalse
- 4Tetra-ammine dichloro cobaltfalse
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Answer : 1. "Tetra-ammine dichloro cobalt (III) chloride"
Explanation :
Answer: A) Tetra-ammine dichloro cobalt (III) chloride Explanation: The IUPAC nomenclature in organic chemistry is a systematic method that is used to name organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC). The IUPAC name of the given complex [Co (NH₃)₄Cl₂ ]Cl is - Tetra-ammine dichloro cobalt (III) chloride. The complex [Co (NH₃)₄ Cl₂ ] Cl ionizes an aqueous solution to furnish the chloride ion Cl⁻ and [Co (NH₃)₄ Cl₂ ] ⁺.
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Answer :
Explanation :
SHORT is the required five letter word, which becomes SHORTER when two letters 'ER' are added to it.
Q: What happens during the bootstrap process? 1177 05b5cc65ee4d2b4197774be2b
5b5cc65ee4d2b4197774be2b- Show AnswerHide Answer
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Answer :
Explanation :
A bootstrap is the process of starting up a computer. It also refers to the program that initializes the operating system (OS) during start-up. It referred to a bootstrap load button that was used to initiate a hardwired bootstrap program, or smaller program that executed a larger program such as the OS.
Q: Which of the following statements about monosaccharide structure is true? 1842 05b5cc65ee4d2b4197774be2c
5b5cc65ee4d2b4197774be2c- 1Aldoses and ketoses differ in the position of their hydroxyl groups.false
- 2Monosaccharides can be classified according to the spatial arrangement of their atoms.true
- 3All monosaccharides contain carbon, hydrogen, oxygen, and nitrogen atoms.false
- 4A six-carbon sugar is called a pentose.false
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Answer : 2. "Monosaccharides can be classified according to the spatial arrangement of their atoms."
Explanation :
Answer: B) Monosaccharides can be classified according to the spatial arrangement of their atoms. Explanation: Monosaccharides, also called simple sugars, are the most basic units of carbohydrates. They are fundamental units of carbohydrates and cannot be further hydrolyzed to simpler compounds. Hence, Monosaccharides can be classified according to the spatial arrangement of their atoms is true about Monosaccharides.
Q: Car is to garage as aeroplane is to 1997 05b5cc65ee4d2b4197774be20
5b5cc65ee4d2b4197774be20- 1Hangartrue
- 2Portfalse
- 3Harbourfalse
- 4Depotfalse
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Answer : 1. "Hangar"
Explanation :
Answer: A) Hangar Explanation: We park car temporarily in garrage, similarly, aeroplane is temporarily parked in hangar.
Q: The yield to maturity on a discount bond is 1459 05b5cc65ee4d2b4197774be25
5b5cc65ee4d2b4197774be25- 1equal to both the coupon rate / current yeildtrue
- 2less than the current yeild but greater than the coupon ratefalse
- 3greater than both the coupon rate / current yeildfalse
- 4equal to the current yeild but greater than the coupon ratefalse
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Answer : 1. "equal to both the coupon rate / current yeild"
Explanation :
Answer: A) equal to both the coupon rate / current yeild Explanation: Yield to maturity is a concept for fixed rate bonds and is the internal rate of return i.e. the rate at which future flows are discounted on a compound basis to give the present value of the bond including accrued interest.
Q: The modulus of elasticity for mild steel is approximately equal to 2347 05b5cc65ee4d2b4197774be16
5b5cc65ee4d2b4197774be16- 1210 kN/mm2true
- 2100 kN/mm2false
- 380 kN/mm2false
- 410 kN/mm2false
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Answer : 1. "210 kN/mm2"
Explanation :
Answer: A) 210 kN/mm2 Explanation: It is useful to have a property of a material that is independent of the size of the sample and can be use to compare its elastic properties with another - this is called the Modulus of Elasticity for the material. The modulus of elasticity is defined as: Modulus of elasticity = Stress / Strain There are three types of moduli. They are : (a) the Young Modulus - tensile and compression longitudinal stress (b) the shear modulus - a shearing stress (c) the bulk modulus - volume changes of the specimen.

