छाया क्षेत्र किसी दिए गए भूकंप से १०४ से १४० डिग्री की कोणीय दूरी से पृथ्वी का वह क्षेत्र है जिसे कोई सीधी पी तरंगें प्राप्त नहीं होती हैं। छाया क्षेत्र S तरंगों के तरल कोर द्वारा पूरी तरह से बंद होने और P तरंगों के तरल कोर द्वारा मुड़े (अपवर्तित) होने के परिणामस्वरूप होता है। शैडो ज़ोन दो प्रकार के होते हैं: एक P तरंगों के लिए और दूसरा S तरंगों के लिए। पी तरंग छाया 104-140 डिग्री, दोनों तरफ; S तरंग छाया एक तरफ के 105 से दूसरी तरफ 105 तक।

Answer: A) decreases Explanation: When water freezes its density decreases. Water at ordinary temperatures contracts and increases in density as it is cooled, like most substances. But at about 4°C it reaches a maximum density and then decreases in density as it approaches the freezing point.

Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.

Answer: A) 19 Explanation: Initialy from left 7th = kumarfrom right 9th = pawanInterchange kumar = 11th from left, from right kumar = 9th;11+8 = 19;8 is 1,2,3,4,5,6,7(pawan),8,9,10,11(kumar),12,13,14,15,16,17,18,19;simply count the 9th place from right we will get total as 19.

Answer: C) 18th Explanation: Number of persons between Amrita and Mukul = 50 - (10 + 25) = 15. Since Mamta lies in middle of these 15 persons, so Mamta`s position is 8th from Amrita i.e. 18th from the front.

They walked and did this. It was never specified that the boat was at sea. Since this logic is observed by them to tackle situation.

Answer: C) 504 Explanation: (COUNTING OF LETTERS) NAMO = 14 + 1 + 13 + 15 = 43 x 4 = 172,  OM = 15 + 13 = 28 x 2 = 56, SHIVAY = 19 + 8 + 9 + 22 + 1 + 25 = 84 x 6 = 504

Answer: C) 175 Explanation: Given that,  working days = 5  working hours = 8  A man get rupess per hour is Rs.2.40  So in one day the man get total rupees is 2.40 x 8 = 19.2  So in 5 days week the man get total rupees is 19.2 x 5 = 96  So in 4 week the man get total rupees is 96 x 4 = 384  So the man worked for = 160hours in 4 weeks    But given that the man earned Rs.432    Hence remaning money is (432-384 = 48)which is earn by doing overtime work   Overtime hours  = 48/3.20 = 15 So total worked hours is = 15 + 160 = 175.