CAT Practice Question and Answer
8Q: In an election between two candidates K and L, the number of valid votes received by K exceeds those received by L by 15% of the total number of votes polled. If 20% of the votes polled were invalid and a total of 8720 votes were polled, then how many valid votes did L get ? 3930 05b5cc6d7e4d2b4197774e6fb
5b5cc6d7e4d2b4197774e6fb- 13241false
- 22457false
- 32642false
- 42834true
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Answer : 4. "2834"
Explanation :
Answer: D) 2834 Explanation: Let the total number of votes polled in the election be 100k.Number of valid votes = 100k - 20% (100k) = 80kLet the number of votes polled in favour of K and L be a and b respectively.a - b = 15% (100k) => a = b + 15k=> a + b = b + 15k + bNow, 2b + 15k = 80k and hence b = 32.5kIt is given that 100k = 872032.5k = 32.5k/100k x 8720 = 2834 The number of valid votes polled in favour of L is 2834.
Q: In a queue, Amrita is 10th from the front while Mukul is 25th from behind and Mamta is just in the middle of the two. If there be 50 persons in the queue. What position does Mamta occupy from the front ? 3929 05b5cc6f8e4d2b4197774f068
5b5cc6f8e4d2b4197774f068- 114thfalse
- 216thfalse
- 318thtrue
- 420thfalse
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Answer : 3. "18th"
Explanation :
Answer: C) 18th Explanation: Number of persons between Amrita and Mukul = 50 - (10 + 25) = 15. Since Mamta lies in middle of these 15 persons, so Mamta`s position is 8th from Amrita i.e. 18th from the front.
Q: Is B2+ Paramagnetic or Diamagnetic? 3926 05b5cc69ae4d2b4197774c7ac
5b5cc69ae4d2b4197774c7ac- Show AnswerHide Answer
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Answer :
Explanation :
B2+ is a Paramagnetic. The filled orbitals are σ(1s)22, σ∗(1s)22, σ(2s)22, σ∗(2s)22. The half-filled orbitals are π(2pxx) and π(2pyy). Since it posses 2 unpaired electrons, it is Paramagnetic in nature.
Q: If NAMO = 172 and OM = 56 then, SHIVAY = ? 3924 05b5cc6cee4d2b4197774e237
5b5cc6cee4d2b4197774e237- 1606false
- 2415false
- 3504true
- 4404false
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Answer : 3. "504"
Explanation :
Answer: C) 504 Explanation: (COUNTING OF LETTERS) NAMO = 14 + 1 + 13 + 15 = 43 x 4 = 172, OM = 15 + 13 = 28 x 2 = 56, SHIVAY = 19 + 8 + 9 + 22 + 1 + 25 = 84 x 6 = 504
Q: Rajitha has a calculator, which has 10 digits. She want to clean the calculator by removing all the keys and while reassembling it, she interchanged the locations of 3 pairs of keys. For example, if she placed the key ‘3’ in the place of the key ‘7’, she placed the key ‘7’ only in the place of the key ‘3’ and not any other key. All keys that were interchanged corresponded only to numbers. Later, she input some calculations and obtained outputs as provided in the table below. The input is shown in terms of the keys that Kavitapressed, while the output is the output displayed by the calculator. Output: 1. 95 + 84=1282. 128 + 64=1953. 912 + 43=9424. 178 + 19=192 Question : Which of the following pair of digits is unchanged ? 3918 05b5cc6d2e4d2b4197774e467
5b5cc6d2e4d2b4197774e467- 19, 0, 3false
- 21, 3, 8false
- 37, 0, 1true
- 42, 4, 1false
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Answer : 3. "7, 0, 1"
Explanation :
Answer: C) 7, 0, 1 Explanation: 0 1 2 3 4 5 6 7 8 9 0 1 4 8 2 6 5 7 3 9 Here pairs interchanged are 2, 4 3, 8 5, 6 Unchanged are 0, 1, 7, 9
Q: Select the correct statement about cellular respiration? 3916 05b5cc6a3e4d2b4197774cc34
5b5cc6a3e4d2b4197774cc34- 1All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide moleculetrue
- 2All the carbon atoms in glucose ultimately incorporated during cellular respiration into NADH moleculefalse
- 3All the carbon atoms in glucose ultimately incorporated during cellular respiration into ATP moleculefalse
- 4All the carbon atoms in glucose ultimately incorporated during cellular respiration into water moleculefalse
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Answer : 1. "All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule"
Explanation :
Answer: A) All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule Explanation: All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecules.
Q: The primary goal of financial management is to 3914 05b5cc6a6e4d2b4197774cd84
5b5cc6a6e4d2b4197774cd84- 1Expand their share of the marketfalse
- 2Maximize the current value per share of the existing stocktrue
- 3Examining whether costs are reasonable or unreasonablefalse
- 4All the abovefalse
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Answer : 2. "Maximize the current value per share of the existing stock"
Explanation :
Answer: B) Maximize the current value per share of the existing stock Explanation: The primary goals of financial management dwell on both short-term and long-term activities that seek to maximize value creation from scarce financial resources. And then the primary goal of financial management is to Maximize the current value per share of the existing stock. All businesses aim to maximize their profits, minimize their expenses and maximize their market share. Here is a look at each of these goals. Financial management is a process that enables a business to plan, direct, organize, monitor and control its current and future financial resources and events. It involves applying the basic principles of management in financial activities such as purchases, sales, capital expansion, inventory valuation, financial reporting, and profit distribution.
Q: Find the odd one out of the following options. 3910 05b5cc6d6e4d2b4197774e679
5b5cc6d6e4d2b4197774e679- 1Sapphirefalse
- 2Rubyfalse
- 3Topazfalse
- 4Granitetrue
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Answer : 4. "Granite"
Explanation :
Answer: D) Granite Explanation: Except Granite all other options belong to the group of precious stones.

