GATE प्रश्न और उत्तर का अभ्यास करें
8प्र: After working for 8 days, Hari Ram finds that only 1/3 rd of the work has been done. He employs Satya who is 60% as efficient as Hari Ram. How many days more would Satya take to complete the work ? 1828 05b5cc6d3e4d2b4197774e4fa
5b5cc6d3e4d2b4197774e4fa- 124 1/2 daysfalse
- 225 3/2 daysfalse
- 324 2/3 daysfalse
- 426 2/3 daystrue
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उत्तर : 4. "26 2/3 days"
व्याख्या :
Answer: D) 26 2/3 days Explanation: 1/3 ---- 8 1 -------? Hari can do total work in = 24 days As satya is 60% efficient as Hari, then Satya = 1/24 x 60/100 = 1/40 => Satya can do total work in 40 days 1 ----- 40 2/3 ---- ? => 26 2/3 days.
प्र: Number Challenge 1656 05b5cc6d3e4d2b4197774e4f0
5b5cc6d3e4d2b4197774e4f0- 19false
- 211true
- 313false
- 415false
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उत्तर : 2. "11"
व्याख्या :
Answer: B) 11 Explanation: Half the Product of Number in the upper & lower box gives the number in the middle box. i.e. 18 x 4/2 = 36 15 x 6/2 = 45 In the same way 8 x N/2 = 44 => N = 11.
प्र: The first 8 alphabets are written down at random. what is the probability that the letters b,c,d,e always come together ? 2193 05b5cc6d3e4d2b4197774e4d7
5b5cc6d3e4d2b4197774e4d7- 11/7false
- 28!false
- 37!false
- 41/14true
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उत्तर : 4. "1/14"
व्याख्या :
Answer: D) 1/14 Explanation: The 8 letters can be written in 8! ways.n(S) = 8!Let E be the event that the letters b,c,d,e always come together when the first 8 alphabets are written down.Now the letters a, (bcde), f, g and h can be arranged in 5! ways.The letters b,c,d and e can be arranged themselves in 4! ways.n(E) = 5! x 4!Now, the required P(E) = n(E)/n(S) = 5! x 4!/8! = 1/14Hence the answer is 1/14.
प्र: 80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ? 2168 05b5cc6d3e4d2b4197774e4c8
5b5cc6d3e4d2b4197774e4c8- 1120 litfalse
- 2140 litfalse
- 3110 litfalse
- 4150 littrue
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उत्तर : 4. "150 lit"
व्याख्या :
Answer: D) 150 lit Explanation: To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres. => the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity. i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too. Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.
प्र: Number Challenge Puzzle ? 1280 05b5cc6d3e4d2b4197774e4be
5b5cc6d3e4d2b4197774e4be- 11true
- 24false
- 35false
- 40false
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उत्तर : 1. "1"
व्याख्या :
Answer: A) 1 Explanation: In each row, Sum of 1st two digit number + last two digit number = Middle two digit number i.e., 1st row 15 + 40 = 55 2nd row 46 + 47 = 93 Similarly, 7x + 16 = 87 => x = 1.
प्र: Math Logic Challenge 1536 05b5cc6d3e4d2b4197774e4b4
5b5cc6d3e4d2b4197774e4b4- 123false
- 226true
- 313false
- 429false
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उत्तर : 2. "26"
व्याख्या :
Answer: B) 26 Explanation: Let the integer be x. Then, x2-20x = 156 (x + 6)(x - 26) = 0 x = 26 The integer is 26.
प्र: Given that on 9th August 2016 is Saturday. What was the day on 9th August 1616 ? 2709 05b5cc6d3e4d2b4197774e4af
5b5cc6d3e4d2b4197774e4af- 1Saturdaytrue
- 2Sundayfalse
- 3Fridayfalse
- 4Mondayfalse
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उत्तर : 1. "Saturday"
व्याख्या :
Answer: A) Saturday Explanation: We know that, After every 400 years, the same day occurs.Thus, if 9th August 2016 is Saturday, before 400 years i.e., on 9th August 1616 has to be Saturday.
प्र: If the price of diesel increases by 25% and Karthik intends to spend only an additional 15% on diesel, by how much % will he reduce the quantity of diesel purchased ? 1639 05b5cc6d3e4d2b4197774e4a5
5b5cc6d3e4d2b4197774e4a5- 16.67 %false
- 28 %true
- 37.41 %false
- 49 %false
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उत्तर : 2. "8 %"
व्याख्या :
Answer: B) 8 % Explanation: Let the price of 1 litre of diesel be Rs.x and let Karthik initially buy 'y' litres of diesel. Therefore, he would have spent Rs. xy on diesel. When the price of diesel increases by 25%, the new price per litre of diesel is 1.25x. Karthik intends to increase the amount he spends on diesel by 15%.i.e., he is willing to spend xy + 15% of xy = 1.15xy Let the new quantity of diesel that he can get be 'q'.Then, 1.25x x q = 1.15xyOr q = (1.15/1.25)y = 0.92y. As the new quantity that he can buy is 0.92y, he gets 0.08y lesser than what he used to get earlier. Or a reduction of 8%.

