GATE Practice Question and Answer
8Q: K and L starts walking towards each other at 4 pm at speed of 3 km/hr and 4 km/hr respectively. They were initially 17.5 km apart. At what time do they meet ? 2557 05b5cc6c6e4d2b4197774ddfa
5b5cc6c6e4d2b4197774ddfa- 16:00 amfalse
- 26:30 pmtrue
- 35:45 amfalse
- 45:52 pmfalse
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Answer : 2. "6:30 pm"
Explanation :
Answer: B) 6:30 pm Explanation: Suppose they meet after 'h' hours Then 3h + 4h = 17.5 7h = 17.5 h = 2.5 hours So they meet at => 4 + 2.5 = 6:30 pm
Q: One girl can eat 112 chocolates in half a minute, and her boy friend can eat half as many in twice the length of time. How many chocolates can both boy and girl eat in 12 seconds ? 2556 05b5cc745e4d2b4197774fa27
5b5cc745e4d2b4197774fa27- 144false
- 232false
- 356true
- 449false
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Answer : 3. "56"
Explanation :
Answer: C) 56 Explanation: Girl eats 112 chocolates in 30 sec so she can eat in 12 sec is 12 x 112/30 = 44.8 chocolates. Her boy friend can eat one-half of 112 in twice of 30 sec so he can eat 56 in 60 sec Then he can eat in 12 sec is 56 x 12/60 = 11.2 chocolates. Hence, together they can eat = 44.8 + 11.2 =56 chocolates in 12 seconds.
Q: Oldest Oil Field in India 2553 05b5cc6b9e4d2b4197774d748
5b5cc6b9e4d2b4197774d748- 1Mumbai High, Maharashtrafalse
- 2Anleshwar, Gujaratfalse
- 3Digboi, Assamtrue
- 4Nonefalse
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Answer : 3. "Digboi, Assam"
Explanation :
Answer: C) Digboi, Assam Explanation: Digboi has the distinction of being India's oldest continuously producing oilfield. Digboi refinery, now a division of Indian Oil Corporation, had a capacity of about 0.65 MMTPA as of 2003. Digboi is now Headquarter of Assam Oil Division of Indian Oil Corporation Limited, though the crude production is not high today.
Q: Chemical name of Gold? 2551 05b5cc642e4d2b4197774bb43
5b5cc642e4d2b4197774bb43- 1Argentinumfalse
- 2Ferrusfalse
- 3Aurumtrue
- 4Seleniumfalse
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Answer : 3. "Aurum"
Explanation :
Answer: C) Aurum Explanation: The Chemical name of Gold is Aurum with symbol Au with atomic number 79 and a group 11 element. In its purest form, it is a bright, slightly reddish yellow, dense, soft, malleable, and ductile metal. Chemically, gold is a transition metal.
Q: There are six persons 1, 2, 3, 4, 5 and 6. 3 is the sister of 6. 2 is the brother of 5's husband. 4 is the father of 1 and grandfather of 6. There are two fathers, three brothers and a mother in the group. Which of the following is a group of brothers ? 2551 05b5cc76ae4d2b4197774fe56
5b5cc76ae4d2b4197774fe56- 11, 2, 3false
- 23, 2, 6false
- 31, 2, 4false
- 41, 2, 6true
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Answer : 4. "1, 2, 6"
Explanation :
Answer: D) 1, 2, 6 Explanation: 4 is father of 1 and grandfather of 6. So, 1 is father of 6. Thus, 4 and 1 are the two fathers. 3 is the sister of 6. So, 3 is the daughter of 1. Since there is only one mother, it is evident that 5 is the wife of 1 and hence the mother of 3 and 6. So, 2 is brother of 1. There are three brothers. So, 6 is the brother of 3. Hence, 2 and 1 are brothers. 6 is the brother of 3. So, three brothers are 1, 2, 6.
Q: Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ? 2549 05b5cc74fe4d2b4197774fb21
5b5cc74fe4d2b4197774fb21- 179true
- 277false
- 376false
- 473false
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Answer : 1. "79"
Explanation :
Answer: A) 79 Explanation: Assuming Sripad has scored the least marks in subject other than science,Then the marks he could secure in other two are 58 each.Since the average mark of all the 3 subject is 65.i.e (58+58+x)/3 = 65116 + x = 195x = 79 marks. Therefore, the maximum marks he can score in maths is 79.
Q: In a test, minimum passing percentage for girls and boys is 35% and 40% respectively. A boy scored 483 marks and failed by 117 marks. What is the minimum passing marks for girls ? 2548 05b5cc72ce4d2b4197774f75a
5b5cc72ce4d2b4197774f75a- 1625false
- 2525true
- 3425false
- 4325false
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Answer : 2. "525"
Explanation :
Answer: B) 525 Explanation: Given 40% minimum passing marks for boys = 483 + 117 = 600=> 1% = 600/40 => 100% = 600 x 100/40 = 1500Minimum passing marks for girls = 35% of 1500 = 35 x 1500/100 = 525.
Q: In a class there are certain no. of boys and girls. If 15 girls are absent then no. of boys will be twice that of girls. If 45 boys are absent then girls strength will be 5 times that of boys. Find number of boys actually present ? 2548 05b5cc715e4d2b4197774f41d
5b5cc715e4d2b4197774f41d- 140false
- 250true
- 355false
- 435false
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Answer : 2. "50"
Explanation :
Answer: B) 50 Explanation: 15 girls are absent => b = 2(g-15)...... eqn...(1) 45 boys are absent => g - 15 = 5(b-45).....eqn...(2) => g = 5(b-45) + 15 => b = 2((5(b-45)+15)-15) => b = 2(5b - 225 + 15 - 15) => b = 2(5b-225) => b = 10b - 450 => 9b = 450 => b = 50 so from equation(2) g - 15 = 5(b - 45) => g - 15 = 5(50-45) => g - 15 = 5(5) => g = 25 + 15 => g = 40 Therefore, the number of boys = 50 and girls = 40