GATE प्रश्न और उत्तर का अभ्यास करें
8प्र: Eighteen years ago, a mother was three times as old as her daughter. Now the mother is only twice as old as her daughter. Then the sum of the present ages of daughter and the mother is ? 1987 05b5cc6f8e4d2b4197774f06d
5b5cc6f8e4d2b4197774f06d- 184 yrsfalse
- 296 yrsfalse
- 3116 yrsfalse
- 4108 yrstrue
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उत्तर : 4. "108 yrs"
व्याख्या :
Answer: D) 108 yrs Explanation: Let the present ages of the mother and daughter be 2x and x years respectively. Then, (2x - 18) = 3(x - 18) => x = 36 Required sum = (2x + x) = 108 years.
प्र: The marked price of a Watch is Rs.8400. It is to be sold at Rs.6896 at two successive discounts. If the first discount is 12%, the second discount is ? 1986 05b5cc720e4d2b4197774f627
5b5cc720e4d2b4197774f627- 17.2 %false
- 29.14 %false
- 37.13 %false
- 46.709 %true
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उत्तर : 4. "6.709 %"
व्याख्या :
Answer: D) 6.709 % Explanation: (100-x)% of 88% of 8400 = 6896 => 100-x10088100x8400 = 6896 => x = 6.709%
प्र: Ram sell his goods 25% cheaper than Shyam and 25% dearer than Bram. How much % is Bram's good cheaper than Shyam ? 1986 05b5cc70be4d2b4197774f2f6
5b5cc70be4d2b4197774f2f6- 160%false
- 240%true
- 350%false
- 430%false
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उत्तर : 2. "40%"
व्याख्या :
Answer: B) 40% Explanation: Lets say shyam sells at 100, Since Ram sells 25% cheaper than Shyam, Therefor Ram sells at less than 25% of100 or 75 rs. Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or 125% of x (say x price of bram )=75rs.or 100% of x =60rs.hence price of bram is 60rs. now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%. Hence Brams Good is 40% cheaper than that of Shyam's good.
प्र: Which of the following is the most stable carbocation? 1984 05b5cc69ee4d2b4197774c9a9
5b5cc69ee4d2b4197774c9a9- 14false
- 23false
- 32true
- 41false
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उत्तर : 3. "2"
व्याख्या :
Answer: C) 2 Explanation: Here the most stable carbocation is the option (2). Carbocations are always hungry for electrons. The stability of carbocations increases from primary to secondary to tertiary. Here, option (c) shows the most stable carbocation because it can easily withdraw electrons from two other carbon atoms and the more electronegative oxygen atom. Carbocation stability depends on hyperconjugation. The tertiary carbocation is stabilized by electron releasing inductive effect.
प्र: Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour ? 1984 05b5cc6e2e4d2b4197774ec57
5b5cc6e2e4d2b4197774ec57- 12 hrsfalse
- 220 mintrue
- 340 minfalse
- 430 minfalse
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उत्तर : 2. "20 min"
व्याख्या :
Answer: B) 20 min Explanation: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages. Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr. stoppage time = 20/60 hrs = 20 min.
प्र: A sum is divided among K, L and M in such a way that for each rupee K gets, L gets 45 paisa and M gets 30 paisa. If the share of L is Rs. 27, what is the total amount ? 1982 05b5cc6e0e4d2b4197774eb66
5b5cc6e0e4d2b4197774eb66- 1Rs. 159false
- 2Rs. 96false
- 3Rs. 147false
- 4Rs. 105true
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उत्तर : 4. "Rs. 105"
व्याख्या :
Answer: D) Rs. 105 Explanation: K : L : M = 100 : 45 : 30 = 20 : 9 : 6 Given L share is 27 => 9 ------ 27 35 ------ ? => 105
प्र: What is always coming but never arrives? 1981 05b5cc68be4d2b4197774c3b5
5b5cc68be4d2b4197774c3b5- उत्तर देखेंउत्तर छिपाएं
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उत्तर :
व्याख्या :
It is Tomorrow. It always be tomorrow which represents coming but never arrives.
प्र: Find the odd man out of the following number sequence? 3, 5, 13, 43, 167 1980 05b5cc622e4d2b4197774b820
5b5cc622e4d2b4197774b820- 1167true
- 243false
- 313false
- 45false
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उत्तर : 1. "167"
व्याख्या :
Answer: A) 167 Explanation: The given number series is 3, 5, 13, 43, 167 3 3 x 1 + 2 = 5 5 x 2 + 3 = 13 13 x 3 + 4 = 43 43 x 4 + 5 = 177 (not equal to 167) Hence, the odd number in the given number sequence is 167.

