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प्र: Which of the following CANNOT be considered a single phase? 2482 0

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    a heterogeneous mixture
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  • 2
    a pure solid
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  • 3
    a pure liquid
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  • 4
    a homogeneous mixture
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उत्तर : 1. "a heterogeneous mixture"
व्याख्या :

Answer: A) a heterogeneous mixture Explanation: A pure solid and a pure liquid are definitely a single phase because they are so united, or homogeneous. This leads to a homogeneous mixture also being a single phase.   Hence, the option that cannot be considered a single phase is A. a heterogeneous mixture.

प्र: A,B,C together can do a piece of work in 10 days.All the three started workingat it together and after 4 days,A left.Then,B and C together completed the work in 10 more days.In how many days can complete a work alone ? 2482 0

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    25
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  • 2
    24
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  • 3
    23
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  • 4
    21
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उत्तर : 1. "25"
व्याख्या :

Answer: A) 25 Explanation: (A+B+C) do 1 work in 10 days. So (A+B+C)'s 1 day work=1/10 and as they work together for 4 days so workdone by them in 4 days=4/10=2/5 Remaining work=1-2/5=3/5   (B+C) take 10 more days to complete 3/5 work. So( B+C)'s 1 day work=3/50 Now A'S 1 day work=(A+B+C)'s 1 day work - (B+C)'s 1 day work=1/10-3/50=1/25 A does 1/25 work in in 1 day Therefore 1 work in 25 days.

प्र: 20 men went to a restaurant. Ninteen of them paid Rs.70 each and the twentieth man paid Rs.90.25 more than the average of all the 20 men. What is the total bill ? 2482 0

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    Rs. 1495
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  • 2
    Rs. 548
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  • 3
    Rs. 850
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  • 4
    Rs. 1750
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उत्तर : 1. "Rs. 1495"
व्याख्या :

Answer: A) Rs. 1495 Explanation: Let the average bill paid by twenty members = 'x' But 19 men paid each = Rs. 70 20th man paid Rs. 90.25 more than the avg bill of 20 = x + 90.25 20x = 19(70) + x + 90.2519x = 1330 + 90.2519x = 1420.25x = 1420.25/19 = Rs. 74.75 But the total bill = 20 x 74.75 = Rs. 1495.

प्र: If sum of upstream and downstream speed of a boat is 82 kmph, and the boat travels 105 km. upstream in 3 hr, Find the time taken by boat to cover 126 km downstream. 2482 0

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    2.8 hrs
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  • 2
    2.7 hrs
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  • 3
    2.6 hrs
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  • 4
    2.5 hrs
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उत्तर : 2. "2.7 hrs"
व्याख्या :

Answer: B) 2.7 hrs Explanation: Let Speed of boat in still water = b Let Speed of still water = w Then we know that, Speed of Upstream = U = boat - water Speed of Downstream = D = boat + water Given, U + D = 82 b - w + b + w = 82 2b = 82 => b = 41 kmph From the given data, 41 - w = 105/3 = 35 w = 6 kmph Now, b + w = 126/t => 41 + 6 = 126/t => t = 126/47  = 2.68 hrs.

प्र: The missing number in the Series 114, 131, 165, 216,  ?, 369 2481 0

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    314
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  • 2
    304
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  • 3
    294
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  • 4
    284
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उत्तर : 4. "284"
व्याख्या :

Answer: D) 284 Explanation: 114       131     165     216     ?      369    +17      +34     +51     +68    +85   => The missing number in the given Number series = 216 + 68 = 284.

प्र: Three friends Rudra, Siva and Anvesh start to run around a circular stadium. They complete a revolution in 24, 36 and 30 seconds respectively. After how many minutes will they meet at the starting point ? 2479 0

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    60
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  • 2
    120
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  • 3
    360
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  • 4
    6
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उत्तर : 4. "6"
व्याख्या :

Answer: D) 6 Explanation: For this we have to find the LCM of 24, 36 and 30 LCM of 24, 36 and 30 = 360 sec 360/60 min = 6 minutes.

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उत्तर : 4. "45 kg"
व्याख्या :

Answer: D) 45 kg Explanation: Let the ratio of initial quantity of oils be 'x' => 4x, 5x & 8x.Let k be the quantity of third variety of oil in the final mixture.Let the ratio of initial quantity of oils be 'y'From given details,4x + 5 = 5y ..... (1)5x + 10 = 7y .....(2)8x + k = 9y ......(3) By solving (1) & (2), we getx = 5 & y = 5 From (3) => k = 5 Therefore, quantity of third variety of oil was 9y = 9(5) = 45kg.

प्र: A house owner wants to get his house painted. He is told that this would require 45 kg of paint allowing 6% wasting. And if the paint is available in 4 kg tins only, the number of tins required for painting the house is ? 2476 0

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    12
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  • 2
    13
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  • 3
    11
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  • 4
    10
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उत्तर : 1. "12"
व्याख्या :

Answer: A) 12 Explanation: Given 45 kg for painting  And 6% 0f 45 for wasting => 6x45/100 = 2.7 kg Now total paint required = 45+2.7 = 47.7 kgs But tins are available in only 4kgs Then, no. of tins req = 47.7/4 = 11.4 => 12 tins

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