GATE प्रश्न और उत्तर का अभ्यास करें
8प्र: Find the odd number in the following number series? 24, 4, 13, 41, 151, 640 8934 05b5cc6c1e4d2b4197774db73
5b5cc6c1e4d2b4197774db73- 14false
- 2640false
- 341true
- 413false
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उत्तर : 3. "41"
व्याख्या :
Answer: C) 41 Explanation: The given number series follows the pattern that, 24×0 + 4 = 4 4×1 + 9 = 13 13×2 + 16 = 42 42×3 + 25 = 151 151×4 + 36 = 640 Therefore, the odd number in the given series is 41
प्र: What will come in place of the question mark (?) in the following number series ? 12, 24, 26.5, 79.5, ?, 330 1815 05b5cc6c1e4d2b4197774db5f
5b5cc6c1e4d2b4197774db5f- 1211false
- 2101.5false
- 382.5true
- 499false
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उत्तर : 3. "82.5"
व्याख्या :
Answer: C) 82.5 Explanation: The given series 12 24 26.5 79.5 ? 330 follows a pattern that, 12 x 2 = 24 24 + 2.5 = 26.5 26.5 x 3 = 79.5 79.5 + 3 = 82.5 82.5 x 4 = 330 Hence, the missing number is 82.5
प्र: "Kalinga Prize" associated with which of the following fields ? 1433 05b5cc6c1e4d2b4197774db4b
5b5cc6c1e4d2b4197774db4b- 1Sportsfalse
- 2Journalismfalse
- 3Sciencetrue
- 4Literaturefalse
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उत्तर : 3. "Science"
व्याख्या :
Answer: C) Science Explanation:
प्र: In the following options, select the one which is different from the other three ? 2604 05b5cc6c1e4d2b4197774db32
5b5cc6c1e4d2b4197774db32- 1Concentrationfalse
- 2Concoursefalse
- 3Radiationtrue
- 4Confluencefalse
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उत्तर : 3. "Radiation"
व्याख्या :
Answer: C) Radiation Explanation: Radiation shows the property of spreading while the rest three shows concentration at a point.
प्र: What will come in place of the question mark (?) in the following question ? 52.5% of 800 + 30.5% of 2800 = ? + 87.30 1306 05b5cc6c1e4d2b4197774db2d
5b5cc6c1e4d2b4197774db2d- 11096.30false
- 21226.70false
- 31124.20false
- 41186.70true
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उत्तर : 4. "1186.70"
व्याख्या :
Answer: D) 1186.70 Explanation: 52.5% of 800 + 30.5% of 2800 = ? + 87.30 420 + 854 - 87.30 = ? 1274 - 87.30 = ? ? = 1186.70
प्र: What will come in place of question mark(?) in the following number series ? 6859 5832 ? 4096 3375 3013 05b5cc6c0e4d2b4197774db1e
5b5cc6c0e4d2b4197774db1e- 14589false
- 24913true
- 35013false
- 45169false
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उत्तर : 2. "4913"
व्याख्या :
Answer: B) 4913 Explanation: The given series follows a pattern that, 19 x 19 x 19 = 6859 18 x 18 x 18 = 5832 17 x 17 x 17 = 4913 16 x 16 x 16 = 4096 15 x 15 x 15 = 3375 So, the missing number in the given series = 4913
प्र: A can complete 9/10 part of a work in 31 days. After that, with the help of B he can complete the remaining work in 4 days. In how many days will A and B together can complete that work ? 1471 05b5cc6c0e4d2b4197774db14
5b5cc6c0e4d2b4197774db14- 136false
- 240true
- 342false
- 438false
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उत्तर : 2. "40"
व्याख्या :
Answer: B) 40 Explanation: Remaining work = 1 - 9/10 = 1/10 => A & B together completes 1/10 of work in 4 days => 1 work can completed in ------ ? days Let it be x days => 4110=x1 => x = 40 days. Hence, A & B together can complete the work in 40 days.
प्र: The area of a square is equal to the area of a rectangle. The length of the rectangle is 5 cm more than a side of the square and its breadth is 3 cm less than the side of the square. What is the perimeter of the rectangle ? 1246 05b5cc6c0e4d2b4197774db0f
5b5cc6c0e4d2b4197774db0f- 115 cmfalse
- 218 cmfalse
- 334 cmtrue
- 426 cmfalse
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उत्तर : 3. "34 cm"
व्याख्या :
Answer: C) 34 cm Explanation: Let the side of the square be 's' cm length of rectangle = (s+5) cm breadth of rectangle = (s-3)cm (s+5) (s-3) = s2 - 5s - 3s - 15 = s2 2s = 15 Perimeter of rectangle = 2(L+B) = 2(s+5 + s–3) = 2(2s + 2) = 2(15 + 2) = 34 cm