GATE प्रश्न और उत्तर का अभ्यास करें
8प्र: Crack the series missing Number Puzzle ? 1818 05b5cc6c0e4d2b4197774dad0
5b5cc6c0e4d2b4197774dad0- 1330false
- 2253false
- 3221false
- 4363true
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उत्तर : 4. "363"
व्याख्या :
Answer: D) 363 Explanation: The given numbers in the series follows a pattern that, 3 (3 x 3) + 3 = 12 (12 x 3) + 3 = 39 (39 x 3) + 3 = 120 (120 x 3) + 3 = 363.
प्र: How many inches is 5' 4"? 1818 05b5cc64de4d2b4197774bc6b
5b5cc64de4d2b4197774bc6b- 166false
- 264true
- 362false
- 460false
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उत्तर : 2. "64"
व्याख्या :
Answer: B) 64 Explanation: We know 1 feet = 12 inches. According to the question, 5' 4'' = 5 feet 4 inches = 12 x 5 + 4 = 64 inches. Hence, 5' 4'' = 5 feet 4 inches = 64 inches.
प्र: Albert invested Rs. 8000 in a scheme for 2 years at compound interest rate 5% p.a. How much amount will Albert get on maturity of the fixed deposit ? 1818 05b5cc6e7e4d2b4197774ed9c
5b5cc6e7e4d2b4197774ed9c- 1Rs. 8840false
- 2Rs. 8800false
- 3Rs. 8810false
- 4Nonetrue
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उत्तर : 4. "None"
व्याख्या :
Answer: D) None Explanation: Amount = 80001+51002 = 8000 x 21/20 x 21/20 = Rs. 8820
प्र: Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to: 1817 05b5cc699e4d2b4197774c750
5b5cc699e4d2b4197774c750- 1596/9false
- 2605/9false
- 3645/9false
- 4700/9true
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उत्तर : 4. "700/9"
व्याख्या :
Answer: D) 700/9 Explanation: Let Veena's weight = 1 kg Sana's weight = 2 kg Sneha's weight = 1.4 kg Rina's weight = 1.8 kg Now,according to the given data in the question, 1.8x100 = 1.4 x = 1.4 × 1001.8 = 7009 = 77 79.
प्र: A number is increased by 20% and then decreased by 20%, the final value of the number is ? 1817 05b5cc75ce4d2b4197774fc39
5b5cc75ce4d2b4197774fc39- 1increase by 2%false
- 2decrease by 3%false
- 3decrease by 4%true
- 4increase by 5%false
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उत्तर : 3. "decrease by 4%"
व्याख्या :
Answer: C) decrease by 4% Explanation: Here, x = 20 and y = - 20Therefore, the net % change in value=x + y + xy100 %= 20 + -20 + 20 × -20100% or - 4% Since the sign is negative, there is a decrease in value by 4%.
प्र: What will come in place of the question mark (?) in the following number series ? 12, 24, 26.5, 79.5, ?, 330 1815 05b5cc6c1e4d2b4197774db5f
5b5cc6c1e4d2b4197774db5f- 1211false
- 2101.5false
- 382.5true
- 499false
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उत्तर : 3. "82.5"
व्याख्या :
Answer: C) 82.5 Explanation: The given series 12 24 26.5 79.5 ? 330 follows a pattern that, 12 x 2 = 24 24 + 2.5 = 26.5 26.5 x 3 = 79.5 79.5 + 3 = 82.5 82.5 x 4 = 330 Hence, the missing number is 82.5
प्र: ANBC full form is? 1814 05b5cc6bbe4d2b4197774d862
5b5cc6bbe4d2b4197774d862- उत्तर देखेंउत्तर छिपाएं
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उत्तर :
व्याख्या :
ANBC Full Form is Adjusted Net Bank Credit. ANBC refers to Adjusted Net Bank Credit, is Net Bank Credit added to investments made by banks in non-SLR bonds (in held-to-maturity) or it is the credit equivalent of off-balance - sheet exposures, whichever is higher. Net Bank Credit = Outstanding bank credits in India (-) Bills rediscounted with RBI/approved financial institutions.
प्र: A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is red. 1813 05b5cc7d0e4d2b4197775121d
5b5cc7d0e4d2b4197775121d- 123/42false
- 219/42true
- 37/32false
- 416/39false
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उत्तर : 2. "19/42"
व्याख्या :
Answer: B) 19/42 Explanation: A red ball can be drawn in two mutually exclusive ways (i) Selecting bag I and then drawing a red ball from it. (ii) Selecting bag II and then drawing a red ball from it. Let E1, E2 and A denote the events defined as follows: E1 = selecting bag I, E2 = selecting bag II A = drawing a red ball Since one of the two bags is selected randomly, therefore P(E1) = 1/2 and P(E2) = 1/2 Now, PAE1 = Probability of drawing a red ball when the first bag has been selected = 4/7 PAE2 = Probability of drawing a red ball when the second bag has been selected = 2/6 Using the law of total probability, we have P(red ball) = P(A) = PE1×PAE1+PE2×PAE2 = 12×47+12×26=1942

