Answer: C) 60 kmph Explanation: Speed on return trip = 150% of 50 = 75 km/hr. Average speed = (2 x 50 x 75)/(50 + 75) = 60 km/hr.

Answer: D) 12 p.m. Explanation: Assume both trains meet after 'p' hours after 7 a.m.Distance covered by train starting from A in 'p' hours = 20p kmDistance covered by train starting from B in (p-1) hours = 25(p-1)Total distance = 200=> 20x + 25(x-1) = 200=> 45x = 225=> p= 5Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.

Answer: C) Dhrupad Explanation:

Answer: B) Voltage Explanation: Electrical Pressure is also called as Voltage. Voltage is measured in Volts.   Volt : A unit of electrical pressure or Voltage is called Volt.   One volt is the amount of pressure required to cause one ampere of current to flow against one ohm of resistance.   Voltage is also referred to as Electromotive Force or Electrical Potential or Electrical Pressure.

Answer: B) Rs. 11,250 Explanation: Given that SP = Rs. 12000 - 10%  = Rs. 10,800 Loss% = 4 We know that, C.P = 100/(100 - Loss%) x 100 => 100/100-4 x 10800 => 1080000/96 C.P = Rs. 11,250

Answer: A) 1/6 Explanation: K's one day's work = 1/30 L's one day's work = 1/45 (K + L)'s one day's work = 1/30 + 1/45 = 1/18 The part of the work completed in 3 days = 3 (1/18) = 1/6.

Answer: B) 19/42 Explanation: A red ball can be drawn in two mutually exclusive ways  (i) Selecting bag I and then drawing a red ball from it.   (ii) Selecting bag II and then drawing a red ball from it.   Let E1, E2 and A denote the events defined as follows: E1 = selecting bag I, E2 = selecting bag II A = drawing a red ball Since one of the two bags is selected randomly, therefore  P(E1) = 1/2  and  P(E2) = 1/2 Now, PAE1 = Probability of drawing a red ball when the first bag has been selected = 4/7   PAE2  = Probability of drawing a red ball when the second bag has been selected = 2/6  Using the law of total probability, we have   P(red ball) = P(A) = PE1×PAE1+PE2×PAE2                              = 12×47+12×26=1942

Answer: D) 120 Explanation: In given word OLIVER there are 3 vowels E, I & O. These can be arranged in only one way as dictionary order E, I & O.   There are 6 letters in thegiven word.   First arrange 3 vowels.   This can be done in 6C3 ways and that too in only one way.(dictionary order E, I & O)   Remaining 3 letters can be placed in 3 places = 3! ways   Total number of possible ways of arranging letters of OLIVER = 3! x C36 ways = 6x5x4 = 120 ways.