GATE Practice Question and Answer
8Q: असेंबली भाषा में प्रयुक्त अनुवादक कार्यक्रम 1869 05b5cc64de4d2b4197774bc75
5b5cc64de4d2b4197774bc75- 1असेंबलरtrue
- 2इंटरप्रेटरfalse
- 3कंपाइलरfalse
- 4ऑपरेटिंग सिस्टमfalse
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Answer : 1. "असेंबलर"
Explanation :
Answer: A) असेंबलर स्पष्टीकरण: असेंबलर का उपयोग निम्न-स्तरीय असेंबली भाषा में लिखे गए प्रोग्राम को मशीन कोड (ऑब्जेक्ट कोड) फ़ाइल में अनुवाद करने के लिए किया जाता है ताकि इसे कंप्यूटर द्वारा उपयोग और निष्पादित किया जा सके। इसलिए, असेंबलर असेंबली भाषा में इस्तेमाल किया जाने वाला अनुवादक प्रोग्राम है।
Q: A Bus is running at 9/10 of its own speed reached a place in 22 hours. How much time could be saved if the bus would run at its own speed ? 1868 05b5cc6dde4d2b4197774ea00
5b5cc6dde4d2b4197774ea00- 11.5 hrsfalse
- 21.7 hrsfalse
- 32.2 hrstrue
- 43.5 hrsfalse
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Answer : 3. "2.2 hrs"
Explanation :
Answer: C) 2.2 hrs Explanation: Let the original Speed be "s" kmphAnd the usual time be "t" hrsGiven that if the bus is running at 9s/10 kmph the time is 22 hrs=> [9s/10] x 22 = t x s=> 99/5 = t => t = 19.8 hrs Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.
Q: Rajitha invested 25% more than Santhosh. Santhosh invested 30% less than Raju, who invested Rs. 6,000. What is the ratio of the amount that Rajitha invested to the total amount invested by all of them together ? 1868 05b5cc736e4d2b4197774f850
5b5cc736e4d2b4197774f850- 125 : 114false
- 235 : 103true
- 315 : 108false
- 441 : 94false
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Answer : 2. "35 : 103"
Explanation :
Answer: B) 35 : 103 Explanation: Santhosh's investment = 6000 x 70/100 = Rs.4200Rajitha's investment = 4200 x 5/4 = Rs.5250Therefore, total amount invested = 6000 + 4200 + 5250 = Rs.15450.Required ratio = 5250 : 15450 = 35 : 103.
Q: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1867 05b5cc6d9e4d2b4197774e816
5b5cc6d9e4d2b4197774e816- 130false
- 236false
- 340true
- 442false
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Answer : 3. "40"
Explanation :
Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.
Q: Nine different letters of alphabet are given, words with 5 letters are formed from these given letters. Then, how many such words can be formed which have at least one letter repeated ? 1867 05b5cc6c6e4d2b4197774de0e
5b5cc6c6e4d2b4197774de0e- 143929true
- 259049false
- 315120false
- 40false
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Answer : 1. "43929"
Explanation :
Answer: A) 43929 Explanation: Number of words with 5 letters from given 9 alphabets formed = 95 Number of words with 5 letters from given 9 alphabets formed such that no letter is repeated is = 9P5 Number of words can be formed which have at least one letter repeated = 95 - 9P5 = 59049 - 15120 = 43929
Q: The length, breadth and height of a room are in the ratio 7:3:1. If the breadth and height are doubled while the length is halved, then by what percent the total area of the 4 walls of the room will be increased ? 1867 05b5cc6c6e4d2b4197774de18
5b5cc6c6e4d2b4197774de18- 190%true
- 288%false
- 385%false
- 484%false
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Answer : 1. "90%"
Explanation :
Answer: A) 90% Explanation: Let length, breadth and height of the room be 7, 3, 1 unit respectively. Area of walls = 2(l+b)xh = 2(7+3)x1 = 20 sq. unit. Now, length, breadth and height of room will become 3.5, 6 and 2 respectively. Area of walls = 2(l+b)xh = 2(3.5+6)x2 = 38 sq. unit. % Increase in the area of walls = (38-20)x100/20 = 90%.
Q: 50 men can build a tank in 40days, but though they begin the work together, 5 men quit every ten days. The time needed to build the tank is ? 1867 05b5cc76fe4d2b4197774ff71
5b5cc76fe4d2b4197774ff71- 150 daystrue
- 248 daysfalse
- 347.5 daysfalse
- 449 daysfalse
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Answer : 1. "50 days"
Explanation :
Answer: A) 50 days Explanation: 50 men can build a tank in 40 days Assume 1 man does 1 unit of work in 1 day Then the total work is 50×40 = 2000 units 50 men work in the first 10 days and completes 50×10 = 500 units of work 45 men work in the next 10 days and completes 45×10 = 450 units of work 40 men work in the next 10 days and completes 40×10 = 400 units of work 35 men work in the next 10 days and completes 35×10 = 350 units of work So far 500 + 450 + 400 + 350 = 1700 units of work is completed and Remaining work is 2000 - 1700 = 300 units 30 men work in the next 10 days. In each day, they does 30 units of work. Therefore, additional days required = 300/30 =10 Thus, total 10+10+10+10+10 = 50 days required.
Q: How many squares with sides 1/2 inch long are needed to cover a rectangle that is 4 ft long and 4 ft wide ? 1866 05b5cc74fe4d2b4197774fb49
5b5cc74fe4d2b4197774fb49- 19216true
- 210246false
- 312345false
- 47527false
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Answer : 1. "9216"
Explanation :
Answer: A) 9216 Explanation: It takes four of those little squares -- each one 1/2 inch on a side -- to cover one square inch. That's because each one is 1/2 x 1/2, or 1/4 of a square inch. In a rectangle that is 48 inches by 48 inches, there are 2304 square inches.(1 ft = 12 inches) Since it takes 4 little squares to cover 1 sq inch, then it would need 2304 x 4 squares (1/2 inch on a side each) to cover a rectangle 4 feet by 4 feet. That is 9,216 of those squares.

