GATE Practice Question and Answer
8Q: Avanthi’s age is 1/6th of her father’s age. Her father’s age will be twice of Kapil’s age after 10 years. If Kapil’s eighth birthday was celebrated two years ago, then what is Avanthi’s present age ? 1838 05b5cc754e4d2b4197774fb90
5b5cc754e4d2b4197774fb90- 16 yearsfalse
- 24 yearsfalse
- 37 yearsfalse
- 4Nonetrue
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Answer : 4. "None"
Explanation :
Answer: D) None Explanation: As given Kapil's 8th birthday was celebrated 2 years ago, Kapil’s present age = 8 + 2 = 10 years. Father's age is twice of Kapil’s age after 10 years. => F + 10 = 2 (K + 10) = 2 (10+ 10)F = 30years, Avanthi's age =1/6(F) = 30/6 = 5 years.
Q: Ajay and his wife Reshmi appear in an interview for two vaccancies in the same post. The Probability of Ajay's selection is 1/7 and that of his wife Reshmi's selection is 1/5. What is the probability that only one of them will be selected? 1838 05b5cc7d0e4d2b41977751222
5b5cc7d0e4d2b41977751222- 15/7false
- 21/5false
- 32/7true
- 42/35false
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Answer : 3. "2/7"
Explanation :
Answer: C) 2/7 Explanation: P( only one of them will be selected) = p[(E and not F) or (F and not E)] = PE∩F∪F∩E = PEPF+PFPE =17×45+15×67=27
Q: 640 ml of a mixture contains milk and water in ratio 6:2. How much of the water is to be added to get a new mixture containing half milk and half water ? 1837 05b5cc731e4d2b4197774f7e7
5b5cc731e4d2b4197774f7e7- 1360 mlfalse
- 2320 mltrue
- 3310 mlfalse
- 4330 mlfalse
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Answer : 2. "320 ml"
Explanation :
Answer: B) 320 ml Explanation: Here total parts of milk and water in the solution is 6+2 = 8 parts. 1part = 640/8 = 80 old mixture contains 6parts of milk and 2 parts of water(6:2). To get new mixture containing half milk and half water, add 4parts of water to the old mixture then 6:(2+4) to make the ratio same. i.e, 4 x 80 = 320 ml.
Q: An individual deposited 20% of 25% of 30% of what he had into his account with a bank. If he deposited Rs.750, how much was he having initially with him before depositing ? 1837 05b5cc71ee4d2b4197774f595
5b5cc71ee4d2b4197774f595- 1Rs. 38000false
- 2Rs. 47000false
- 3Rs. 50000true
- 4Rs. 35000false
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Answer : 3. "Rs. 50000"
Explanation :
Answer: C) Rs. 50000 Explanation: Let 'x' be the amount he had in the bank. => 20/100(25/100(30/100(x))) = 750 x = 750 x 8000/120 = Rs. 50000
Q: Statement: There was a spurt in criminal activities in the city during the recent festival season.Courses of action:a. The police should immediately investigate into the causes of this increase.b. In future the police should take adequate precaution to avoid recurrence of such situation during festival.c. The known criminals should be arrested before any such season. 1837 05b5cc754e4d2b4197774fbbe
5b5cc754e4d2b4197774fbbe- 1Both a and b followstrue
- 2Only c followsfalse
- 3Only a followsfalse
- 4Both b and c followsfalse
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Answer : 1. "Both a and b follows"
Explanation :
Answer: A) Both a and b follows Explanation: The police ought to find out the lackenings in existing security arrangements and make up for these inadequacies to strengthen security and thus prevent criminal activities in the forthcoming festival. So, both a and b follow. Arresting the known criminals does not ensure safety, for a novice can also indulge in crime. So, c does not follow.
Q: B3D means B is the father of D.B7D means B is the sister of D.B2D means B is the brother of D.B1D means B is the wife of D. Which of the following means F is the mother of K? 1836 05b5cc761e4d2b4197774fd25
5b5cc761e4d2b4197774fd25- 1F3M1Kfalse
- 2F9M4N3Kfalse
- 3K3M4N5Ffalse
- 4F1M3Ktrue
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Answer : 4. "F1M3K"
Explanation :
Answer: D) F1M3K Explanation: From the given information, F1M → F is the wife of MM3K → M is the father of KTherefore, F is the mother of K.
Q: One lady has 2 children, one of her child is boy, what is the probability of having both are boys ? 1834 05b5cc728e4d2b4197774f72d
5b5cc728e4d2b4197774f72d- 11/3true
- 21/2false
- 32/3false
- 42/5false
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Answer : 1. "1/3"
Explanation :
Answer: A) 1/3 Explanation: In a family with 2 children there are four possibilities:1) the first child is a boy and the second child is a boy (bb)2) the first child is a boy and the second child is a girl (bg)3) the first child is a girl and the second child is a boy (gb)4) the first child is a girl and the second child is a girl (gg) But already given that one child is boy. So we have three possibilities of (bb)(bg)(gb).n(E)= both are boys=BB=1n(S)= 3Required probability P = n(E)/n(S) = 1/3.
Q: How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated ? 1834 05b5cc774e4d2b4197775000c
5b5cc774e4d2b4197775000c- 115false
- 220true
- 35false
- 410false
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Answer : 2. "20"
Explanation :
Answer: B) 20 Explanation: Since each number to be divisible by 5, we must have 5 0r 0 at the units place. But in given digits we have only 5. So, there is one way of doing it. Tens place can be filled by any of the remaining 5 numbers.So, there are 5 ways of filling the tens place. The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it. Required number of numbers = (1 x 5 x 4) = 20.