GATE प्रश्न और उत्तर का अभ्यास करें
8प्र: Find the sum of the Arithmetic Series upto 36 terms 2, 5, 8, 11,... 2054 15b5cc6afe4d2b4197774d259
5b5cc6afe4d2b4197774d259- 13924false
- 21962true
- 31684false
- 41452false
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उत्तर : 2. "1962"
व्याख्या :
Answer: B) 1962 Explanation: Arithmetic Series :: An Arithmetic Series is a series of numbers in which each term increases by a constant amount. How to find the sum of the Arithmetic Sequence or Series for the given Series :: When the series contains a large amount of numbers, its impractical to add manually. You can quickly find the sum of any arithmetic sequence by multiplying the average of the first and last term by the number of terms in the sequence. That is given by Sn = n(a1 + an)2 Where n = number of terms, a1 = first term, an = last term Here Last term is given by an = a1 + n-1d where d = common difference Now given Arithmetic Series is 2, 5, 8, 11,... Here a1 = 2, d = 3, n = 36 Now, an= a1 + n - 1d a36= 2 + 36 - 13 = 105 + 2 = 107 Now, Sum to 36 terms is given by S36 = 36(2 + 107)2 = 36 x 1092 = 39242 = 1962 Therefore, Sum to 36 terms of the series 2, 5, 8, 11,... is 1962.
प्र: 5 + 2 x 10/2 = ? 2053 05b5cc6a6e4d2b4197774cd33
5b5cc6a6e4d2b4197774cd33- 115true
- 235false
- 310false
- 420false
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उत्तर : 1. "15"
व्याख्या :
Answer: A) 15 Explanation: Using BODMAS Rule, First solve division, mutiplication and Addition So here 10/2 = 5 Then 2 x 5 = 10 Now, 5 + 10 = 15. Hence, 5 + 2 x 10/2 = 15.
प्र: Q = mc∆T refers to 2053 05b5cc64de4d2b4197774bcb7
5b5cc64de4d2b4197774bcb7- 1Enthalpy formulafalse
- 2Heat Transfer formulafalse
- 3Specific Heat formulatrue
- 4Heat of Vaporizationfalse
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उत्तर : 3. "Specific Heat formula"
व्याख्या :
Answer: C) Specific Heat formula Explanation: Q = mc∆T refers to Specific Heat formula. When heat energy is added to a substance, the temperature will change by a certain amount. The relationship between heat energy and temperature is different for every material, and the specific heat is a value that describes how they relate. Q = mc∆T Q = heat energy (Joules, J) m = mass of a substance (kg) c = specific heat (units J/kg∙K) ∆T = change in temperature (Kelvins, K)
प्र: A man sell 35 waffers for Rs. 15 each and loses Rs. 40.4. If he sells 35 waffers for Rs. 18, how much does he loss or gain ? 2053 15b5cc74ae4d2b4197774fa95
5b5cc74ae4d2b4197774fa95- 1Rs. 64true
- 2Rs. 52false
- 3Rs. 72false
- 4Rs. 55false
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उत्तर : 1. "Rs. 64"
व्याख्या :
Answer: A) Rs. 64 Explanation: Given Loss = Rs. 40.4We know loss = cost price - selling price 40.4 = CP - 35(15)=> CP = 40.4 + 525=> CP = Rs. 565.4Now the New selling price of waffer is Rs. 18=> SP = 35(18) = 630Now Gain = SP - CP = 630 -565.4 = Rs. 64.6.
प्र: Who has become world's no.1 Junior Badminton player in 2017 ? 2052 05b5cc75ee4d2b4197774fce3
5b5cc75ee4d2b4197774fce3- 1Chia Hao Leefalse
- 2Lakshya Sentrue
- 3Chirag Senfalse
- 4Karthikey Gulshan Kumarfalse
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उत्तर : 2. "Lakshya Sen"
व्याख्या :
Answer: B) Lakshya Sen Explanation: India's Lakshya Sen has become the World No 1 Junior Badminton player. He achieved the distinction in the latest rankings of the Badminton World Federation (BWF). Fifteen-year-old is the first shuttler from Uttarakhand to attain the numero uno spot at the international level. Lakshya, who is considered as the shining future star of Indian badminton, moved ahead of Chia Hao Lee of the Chinese Taipei, to attain the top spot. According to BWF current rankings, Lakshya has 16,903 points in eight tournaments he has played in the season. Chia Hao, who is at the second spot, has 16,091 points.
प्र: If the HCF of 210 and 55 is expressible in the form of 210 x 5 + 55P, then value of P = ? 2051 05b5cc6c0e4d2b4197774dacb
5b5cc6c0e4d2b4197774dacb- 1-23false
- 227false
- 316false
- 4-19true
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उत्तर : 4. "-19"
व्याख्या :
Answer: D) -19 Explanation: HCF of 210 and 55 is 5 Now, 210x5 + 55P = 5 => 1050 + 55P = 5 => 55P = -1045 => P = -1045/55 => P = -19.
प्र: Select a suitable figure from the four alternatives that would complete the figure matrix. (1) (2) (3) (4) 2051 05b5cc76de4d2b4197774feea
5b5cc76de4d2b4197774feea- 11false
- 24false
- 33false
- 42true
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उत्तर : 4. "2"
व्याख्या :
Answer: D) 2 Explanation: One line is increasing in each subsequent figue.
प्र: What is the freezing point of water in Celsius? 2049 05b5cc6a6e4d2b4197774cda1
5b5cc6a6e4d2b4197774cda1- 10 deg Ctrue
- 232 deg Cfalse
- 3-42 deg Cfalse
- 4-32 deg Cfalse
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उत्तर : 1. "0 deg C"
व्याख्या :
Answer: A) 0 deg C Explanation: The freezing point of water and melting point is 0 °C or 32 °F. The temperature may be lower if supercooling occurs.

