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प्र: The term biodiversity refers to 1917 0

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    Range of genetic variation within a population
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  • 2
    Total number of different species within a habitat
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    Both A & B
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  • 4
    None of the above
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उत्तर : 3. "Both A & B"
व्याख्या :

Answer: C) Both A & B Explanation: The term biodiversity refers to the variety of life on Earth at all its levels, from genes to ecosystems, and the ecological and evolutionary processes that sustain it.

प्र: In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm) 1917 0

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    80%
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    70%
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    75%
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    62%
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उत्तर : 1. "80%"
व्याख्या :

Answer: A) 80% Explanation: Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm.   After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.   So % of water = 100 x 60/75 = 80%.

प्र: Looking at a portrait of a man, Akhil said, "His mother is the wife of my father's son. Brothers and sisters I have none." At whose portrait was Akhil looking ? 1917 0

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    His uncle
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    His nephew
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    His cousin
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    His son
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उत्तर : 4. "His son"
व्याख्या :

Answer: D) His son Explanation: Since Akhil has no brother or sister, so he is his father's only son.So wife of Akhil's father's son---Akhil's wife.Thus, Akhil's wife is the man's mother or the man is Akhil's son.

प्र: A motorboat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the motorboat and speed of the water current respectively? 1916 0

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    3:7
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    7:9
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    5:4
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    8:3
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उत्तर : 4. "8:3"
व्याख्या :

Answer: D) 8:3 Explanation: Let the man's rate upstream be x kmph and that downstream be y kmph. Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs. x x 8 4 = (y x 4) 5 44 x =4y 5  y = 11 x. 5  Required ratio = y + x : y - x 2 2    = 16x x 1 : 6x x 1 5 2 5 2    = 8 : 3 5 5    = 8 : 3.

प्र: If x = 2 + 223 + 213 then find the value of x3-6x2+6x ? 1916 0

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    1
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    2
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    3
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    4
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उत्तर : 2. "2"
व्याख्या :

Answer: B) 2 Explanation: Given that x = 2+ 223 + 213   So x - 2 = 223 + 213   Now cubing on both sides, we get     => x3-8-6x2+12x = 4 + 2 + 6(x-2)   Therefore, x3-6x2+6x = -6 + 8 = 2

प्र: A woman fills a bucket in 6 minutes. 1845 buckets have to be filled from 8 am. to 9:30 am. How many woman employees should be employed for this task? 1915 0

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    111
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    117
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    123
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    139
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उत्तर : 3. "123"
व्याख्या :

Answer: C) 123 Explanation: We know that, M1 × D1W1 = M2 × D2W2 Here M1 = 1, D1 = 6 min, W1 = 1 and M2 = M, D2 = 90 min, W2 = 1845   1 × 61 = M × 901845  => M = 123

प्र: Which formula represents a nonpolar molecule? 1914 0

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    H2O
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    CF4
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    HCl
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    H2S
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उत्तर : 2. "CF4"
व्याख्या :

Answer: B) CF4 Explanation: You have to consider three things. 1. First, are the bonds polar? Look at differences in electronegativity and if  it is >0.5, bonds are polar.   2. Second, does the molecule have unshared electron pairs? If so, they generally lead to a polar molecule.   3. Third, is the molecule symmetric? If so, then although the bonds may be polar, the symmetry cancels out the individual bond polarity and the molecule is non polar. CF4 follows all the rules above and has a symmetric distribution of charge, making it nonpolar. The others all have asymmetric charge distributions.   Hence, CF4 represents a Non-polar molecule.

प्र: If in an A.P series 18th term is 29 and 29th term is 18. Then find the 49th term ? 1914 0

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    -3
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    -2
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    0
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  • 4
    1
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उत्तर : 2. "-2"
व्याख्या :

Answer: B) -2 Explanation: We know that in A.P series18th term = a + 17d29th term = a + 28dBut given a + 17d = 29..........(i)a + 28d = 18......... (ii)Solving equation (i) and (ii), we getd = -1put d = -1 in any of the above equations and we get, a = 46Now, we know 49th term can be written as, a + 48d putting the value of a and d in the above equation,a + 48d = 46 + 48(-1) = 46 - 48 = -2 Hence, the 49th term is -2.

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