Answer: B) 36 Explanation: Total number of students = 54 x 30When arranged in rows of 45, number of rows formed are, 54x3045 = 36.

Answer: B) 12 Explanation: Using BODMAS law, 3 x 3 + 3 - 3 + 3 = 3 x 3 = 12 = 12 + 3 - 3 + 3 =  9 + 3 = 12   Hence, 3 x 3 + 3 - 3 + 3 = 12.

Answer: A) 2000 Explanation: Let 's' be the number of small packets and 'b' the number of large packets sold on that day.   Therefore, s + b = 5000 ... eqn (1)   Each small packet was sold for Rs.150.Therefore, 's' small packets would have fetched Rs.150s.   Each large packets was sold for Rs.250.Therefore, 'b' large packets would have fetched Rs.250b.   Total value of sale = 150s + 250b = Rs. 10.5 Lakhs (Given)   Or 150s + 250b = 10,50,000 ... eqn (2)   Multiplying equation (1) by 150, we get 150s + 150b = 7,50,000 ... eqn (3)   Subtracting eqn (3) from eqn (2), we get 100b = 3,00,000Or b = 3000   We know that s + b = 5000So, s = 5000 - b = 5000 - 3000 = 2000.   2000 small packets were sold.

Answer: D) 8:3 Explanation: Let the man's rate upstream be x kmph and that downstream be y kmph. Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs. x x 8 4 = (y x 4) 5 44 x =4y 5  y = 11 x. 5  Required ratio = y + x : y - x 2 2    = 16x x 1 : 6x x 1 5 2 5 2    = 8 : 3 5 5    = 8 : 3.

Answer: D) 67500 sq.m Explanation: Let the length be 'l' and breadth be 'b'. b = l × 3/4__________(a) 2(l+b) = 1050 l+b = 525___________(b) From equations (a) and (b), l = 300m, b = 225 m Area = l × b = 300 × 225 = 67500 sq.m.

Answer: A) Rs. 704 Explanation: We know that, S.I. = PTR100⇒ P = S.I x 100T x RAnd also,C.I = P1 + R100n- 1 From given data, P = Rs. 8625 Now, C.I  = 86251+41002-1= 862526252-1= 8625676625-1= 8625 x 51625C.I = Rs. 703.80

Answer: A) 32 Explanation: Let the first number be K and second number be LThen, 2K + 3L = 100.....(1)3K + 2L = 120.......(2)solving (1)&(2), we getK = 32 and L = 12 Hence the largest number is 32.

Answer: B) CF4 Explanation: You have to consider three things. 1. First, are the bonds polar? Look at differences in electronegativity and if  it is >0.5, bonds are polar.   2. Second, does the molecule have unshared electron pairs? If so, they generally lead to a polar molecule.   3. Third, is the molecule symmetric? If so, then although the bonds may be polar, the symmetry cancels out the individual bond polarity and the molecule is non polar. CF4 follows all the rules above and has a symmetric distribution of charge, making it nonpolar. The others all have asymmetric charge distributions.   Hence, CF4 represents a Non-polar molecule.