GATE प्रश्न और उत्तर का अभ्यास करें
8प्र: What least number must be substracted from 627349 so that the remaining number is divisible by 15 ? 1846 05b5cc754e4d2b4197774fb9a
5b5cc754e4d2b4197774fb9a- 11false
- 22false
- 33false
- 44true
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उत्तर : 4. "4"
व्याख्या :
Answer: D) 4 Explanation: On dividing 627349 by 15, we get remainder = 4.Therefore, the obtained remainder is the least number to be subtracted from the given number so that the the mnumber is divisible by 15.Here 4 is the least number to be subtracted from 627349 so that it is divisible by 15.
प्र: A farmer divides his herd of k cows among his 4 sons, so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 9 cows. Then k is equal to ? 1846 05b5cc73de4d2b4197774f92a
5b5cc73de4d2b4197774f92a- 1160false
- 2120false
- 3140false
- 4180true
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उत्तर : 4. "180"
व्याख्या :
Answer: D) 180 Explanation: Given total number of cows = kNow, 1st son share = k/22nd son share = k/43rd son share = k/54th son share = 9 (k) + (k/4) + (k/5) + 9 = k=> k - (19k/20) = 9=> (20k-19k)/20 = 9=> k = 180.
प्र: An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%? 1844 05b5cc6aee4d2b4197774d179
5b5cc6aee4d2b4197774d179- 145 gmfalse
- 250 gmtrue
- 355 gmfalse
- 460 gmfalse
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उत्तर : 2. "50 gm"
व्याख्या :
Answer: B) 50 gm Explanation: Initial quantity of copper =80100 x 50 = 40 g And that of Bronze = 50 - 40 = 10 g Let 'p' gm of copper is added to the mixture => 50 + p x 90100 = 40 + p => 45 + 0.9p = 40 + p => p = 50 g Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.
प्र: 3, 12, 5, ? 1844 05b5cc6b9e4d2b4197774d725
5b5cc6b9e4d2b4197774d725- 136false
- 226false
- 330true
- 424false
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उत्तर : 3. "30"
व्याख्या :
Answer: C) 30 Explanation: 332 + 3 = 12552 + 5 = 30
प्र: Antonym of:: Amicable 1843 05b5cc6a6e4d2b4197774cdb1
5b5cc6a6e4d2b4197774cdb1- 1Hostiletrue
- 2Loveablefalse
- 3Friendlyfalse
- 4Peacefulfalse
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उत्तर : 1. "Hostile"
व्याख्या :
Answer: A) Hostile Explanation: Amicable means Friendly or in Loveable, peaceful sense. Then Antonyms for Amicable are Opposite of Friendly => Unfriendly, Hostile, Unpeaceful, etc...
प्र: Pointing to a photograph, a woman says, "This man's son's sister is my mother-in-law." How is the woman's husband related to the man in the photograph ? 1842 05b5cc758e4d2b4197774fbea
5b5cc758e4d2b4197774fbea- 1sonfalse
- 2nephewfalse
- 3grandsontrue
- 4son-in-lawfalse
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उत्तर : 3. "grandson"
व्याख्या :
Answer: C) grandson Explanation: Man's son's sister---Man's daughter.So, the man's daughter is the mother of the woman's husband. Thus, the woman's husband is the grandson of the man in the photograph.
प्र: If 1 1 1 1 = R 2 2 2 2 = T 3 3 3 3 = E 4 4 4 4 = N Then 5 5 5 5 = ? 1841 05b5cc699e4d2b4197774c72e
5b5cc699e4d2b4197774c72e- 1Ytrue
- 2Zfalse
- 3Tfalse
- 4Xfalse
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उत्तर : 1. "Y"
व्याख्या :
Answer: A) Y Explanation: If you add all the terms of the LHS of equality, then the last letter of the sum written in words would give you the RHS. 1 + 1 + 1 + 1 = 4 = FOUR 2 + 2 + 2 + 2 = 8 = EIGHT 3 + 3 + 3 + 3 = 12 = TWELVE 4 + 4 + 4 + 4 = 16 = SIXTEEN So, following the same pattern. 5 + 5 + 5 + 5 = 20 = TWENTY That gives us our answer to 5 5 5 5 = "Y".
प्र: A container contains 120 lit of Diesel. From this container, 12 lit of Diesel was taken out and replaced by kerosene. This process was further repeated for two times. How much diesel is now there in the container ? 1838 05b5cc6c3e4d2b4197774dc86
5b5cc6c3e4d2b4197774dc86- 188.01 litfalse
- 287.48 littrue
- 387.51 litfalse
- 487.62 litfalse
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उत्तर : 2. "87.48 lit"
व्याख्या :
Answer: B) 87.48 lit Explanation: For these type of problems, Quantity of Diesel remained = q1-pqn Here p = 12 , q = 120 => 1201-121203 = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.

