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प्र: 5 years ago Sushma was 5 times as old as her Son. 5 years hence her age will be 8 less than three times the corresponding age of her Son. Find their ages ? 4538 0

  • 1
    24 and 13 years
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  • 2
    48 and 24 years
    सही
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  • 3
    35 and 11 years
    सही
    गलत
  • 4
    33 and 15 years
    सही
    गलत
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उत्तर : 3. "35 and 11 years"
व्याख्या :

Answer: C) 35 and 11 years Explanation: Let the age of sushma be x and the age of her son is yThen five years before x-5=5(y-5) ...(1)Five years hence x+5 = 3(y+5)-8 .....(2) By soving (1) & (2), we get5y - 15 = 3y + 7y = 11 => x = 35 Therefore, the age of Sushma = 35 and her son = 11.

प्र: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4535 0

  • 1
    1124
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  • 2
    1420
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  • 3
    1345
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  • 4
    1250
    सही
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उत्तर : 4. "1250"
व्याख्या :

Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.

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उत्तर :
व्याख्या :

1. Answer (2) G 2. Answer (1) BE All other pairs are in same class. 3. Answer (3) ADF in class 9. 4. Answer (4) Linc pen.

प्र: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 kmph. Then find the speed of faster train  ? 4522 0

  • 1
    68 kmph
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  • 2
    52 kmph
    सही
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  • 3
    76 kmph
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  • 4
    50 kmph
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उत्तर : 1. "68 kmph"
व्याख्या :

Answer: A) 68 kmph Explanation: Let the speed of the faster train be 'X' kmph, Then their relative speed= X - 48 kmphTo cross slower train by faster train, Distance need to be cover = (400 + 600)m = 1 km. and Time required = 180 sec = 180/3600 hr = 1/20 hr.Time = Distance/Speed => 1/20 = 1/(x-48)X = 68 kmph

प्र: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 4520 0

  • 1
    75 min
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  • 2
    82 min
    सही
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  • 3
    90 min
    सही
    गलत
  • 4
    101 min
    सही
    गलत
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उत्तर : 3. "90 min"
व्याख्या :

Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.

प्र: A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is: 4502 0

  • 1
    A gain of Rs. 27
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  • 2
    A loss of Rs. 37
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  • 3
    A loss of Rs. 27
    सही
    गलत
  • 4
    A gain of Rs. 37
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उत्तर : 2. "A loss of Rs. 37"
व्याख्या :

Answer: B) A loss of Rs. 37 Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order). The overall resultant will remain same. So final amount with the person will be (in all cases): = 64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27 Hence the final result is:  64 − 27 = 37 A loss of Rs.37

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उत्तर : 2. "30 min"
व्याख्या :

Answer: B) 30 min Explanation: Distance travelled by Ramu = 45 x 4 = 180 km Somu travelled the same distance in 6 hours. His speed = 180/6 = 30 km/hr Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 30 + 10 = 40km/hr. Therefore travel time of Ramu and Somu would be 5 hours and 4.5 hours respectively. Hence difference in the time taken = 0.5 hours = 30 minutes.

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उत्तर : 2. "J, L"
व्याख्या :

Answer: B) J, L Explanation: This question concerns a committee’s decision about which five of eight areas of expenditure to reduce. The question requires you to suppose that K and N are among the areas that are to be reduced, and then to determine which pair of areas could not also be among the five areas that are reduced. The fourth condition given in the passage on which this question is based requires that exactly two of K, N, and J are reduced. Since the question asks us to suppose that both K and N are reduced, we know that J must not be reduced: Reduced         ::      K, NNot reduced   ::      J The second condition requires that if L is reduced, neither N nor O is reduced. So L and N cannot both be reduced. Here, since N is reduced, we know that L cannot be. Thus, adding this to what we’ve determined so far, we know that J and L are a pair of areas that cannot both be reduced if both K and N are reduced: Reduced        ::      K, NNot reduced  ::      J, L Answer choice (B) is therefore the correct answer.

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