GATE рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ :
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
1. Answer (2) G 2. Answer (1) BE All other pairs are in same class. 3. Answer (3) ADF in class 9. 4. Answer (4) Linc pen.
рдкреНрд░: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 kmph. Then find the speed of faster train ┬а? 4375 05b5cc6dee4d2b4197774ea56
5b5cc6dee4d2b4197774ea56- 168 kmphtrue
- 252 kmphfalse
- 376 kmphfalse
- 450 kmphfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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- SingleChoice
рдЙрддреНрддрд░ : 1. "68 kmph"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 68 kmph Explanation: Let the speed of the faster train be 'X' kmph, Then their relative speed= X - 48 kmphTo cross slower train by faster train, Distance need to be cover = (400 + 600)m = 1 km. and Time required = 180 sec = 180/3600 hr = 1/20 hr.Time = Distance/Speed => 1/20 = 1/(x-48)X = 68 kmph
рдкреНрд░: In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes ┬а? 4371 05b5cc6e2e4d2b4197774ec34
5b5cc6e2e4d2b4197774ec34- 1446false
- 2415false
- 3404false
- 4430true
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 4. "430"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 430 Explanation: Let the total number of valid votes be 'V'. 70% of V = 70/100 x V = 7V/10 Number of votes secured by the other candidate = V - 7V/100 = 3V/10 Given, 7V/10 - 3V/10 = 172 => 4V/10 = 172 => 4V = 1720 => V = 430.
рдкреНрд░: 5 years ago Sushma was 5 times as old as her Son. 5 years hence her age will be 8 less than three times the corresponding age of her Son. Find their ages ? 4365 05b5cc73ae4d2b4197774f8d3
5b5cc73ae4d2b4197774f8d3- 124 and 13 yearsfalse
- 248 and 24 yearsfalse
- 335 and 11 yearstrue
- 433 and 15 yearsfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "35 and 11 years"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 35 and 11 years Explanation: Let the age of sushma be x and the age of her son is yThen five years before x-5=5(y-5) ...(1)Five years hence x+5 = 3(y+5)-8 .....(2) By soving (1) & (2), we get5y - 15 = 3y + 7y = 11 => x = 35 Therefore, the age of Sushma = 35 and her son = 11.
рдкреНрд░: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 4333 05b5cc74fe4d2b4197774fb1c
5b5cc74fe4d2b4197774fb1c- 175 minfalse
- 282 minfalse
- 390 mintrue
- 4101 minfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "90 min"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.
рдкреНрд░: Library is to Book as Book is to 4329 05b5cc6a9e4d2b4197774cf05
5b5cc6a9e4d2b4197774cf05- 1Wordsfalse
- 2Pagestrue
- 3Bindingfalse
- 4Coverfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "Pages"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) Pages Explanation: A Library consists of Books in the same way Book consists Pages. ┬а Hence,┬аLibrary : Book :: Book : Pages.
рдкреНрд░: Directions: Seven different boxes A, B, C, D, E, F and G of different colours viz., Orange, Pink, Purple, Yellow, Blue, Red and Green are arranged one above the other. The box at the bottom of arrangement is numbered 1, the above box is numbered 2 and so on. B is immediately above E. More than two boxes are above the Orange box. The Yellow box is immediately below A. Only one box is between the Orange box and F. G is immediately above the Red box. Only one box is between B and the Pink box. Only two boxes are between the Pink and the Green box. Only two boxes are between the Yellow box and the Orange box. The Purple box is neither at the top nor at the bottom of the arrangement.B is above Pink box. C is immediately above F. Neither C nor G is a Yellow box. G is not a Orange box. Question: Which combination represents the position of C and its colour? 4328 05b5cc76de4d2b4197774feb3
5b5cc76de4d2b4197774feb3- 16-Greenfalse
- 26-Redfalse
- 35-Purplefalse
- 47-Bluetrue
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 4. "7-Blue"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 7-Blue Explanation: From the given information the arrangement can be done as follows: ┬а ┬аPosition ┬аBox ┬аColour ┬а ┬а ┬а ┬а 7 ┬а ┬а ┬а ┬а C ┬а ┬а ┬а Blue ┬а ┬а ┬а 6 ┬а ┬а ┬а ┬а F ┬а ┬а ┬а Green┬а ┬а ┬а 5 ┬а ┬а ┬а ┬а B ┬а ┬а ┬а Purple┬а ┬а ┬а 4 ┬а ┬а ┬а ┬а E ┬а ┬а ┬а Orange┬а ┬а ┬а 3 ┬а ┬а ┬а ┬а G ┬а ┬а ┬а Pink┬а ┬а ┬а 2 ┬а ┬а ┬а ┬а A ┬а ┬а ┬а Red┬а ┬а ┬а 1 ┬а ┬а ┬а ┬а D ┬а ┬а ┬а Yellow
рдкреНрд░: Which alphabet replaces the question mark ? 63 O 4972 T 3796 L 1514 ? 58 4305 05b5cc70ee4d2b4197774f380
5b5cc70ee4d2b4197774f380- 1Afalse
- 2Bfalse
- 3Ctrue
- 4Dfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "C"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) C Explanation: 6-3 = 3 9-4 = 5 (3x5=15) 15=O7-2 = 5 7-3 = 4 (5x4=20) 20=T9-6 = 3 5-1 = 4 (3x4=12) 12=L Similarly, 4-1 = 3 8-5 = 1 (3x1=3) 3=C

