GATE प्रश्न और उत्तर का अभ्यास करें
8प्र: कौन सा तत्व मैग्नीशियम की तरह सबसे अधिक व्यवहार करता है? 3508 05b5cc60ae4d2b4197774b568
5b5cc60ae4d2b4197774b568- 1सिलिकॉनfalse
- 2स्ट्रोंटियमtrue
- 3सल्फरfalse
- 4टिनfalse
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उत्तर : 2. "स्ट्रोंटियम"
व्याख्या :
Answer: B) स्ट्रोंटियम व्याख्या: हम जानते हैं कि आवर्त सारणी के एक ही समूह के तत्वों में समान विशेषताएं होती हैं। यहाँ मैग्नीशियम और स्ट्रोंटियम ने कुछ समान गुण साझा किए क्योंकि वे दोनों एक ही समूह के हैं। Sr स्ट्रोंटियम का रासायनिक प्रतीक है जो एक समूह दो तत्व है; इसका परमाणु क्रमांक 38 है।
प्र: When water freezes its density 3500 05b5cc6a1e4d2b4197774cb08
5b5cc6a1e4d2b4197774cb08- 1decreasestrue
- 2remains constantfalse
- 3increasesfalse
- 4become zerofalse
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उत्तर : 1. "decreases"
व्याख्या :
Answer: A) decreases Explanation: When water freezes its density decreases. Water at ordinary temperatures contracts and increases in density as it is cooled, like most substances. But at about 4°C it reaches a maximum density and then decreases in density as it approaches the freezing point.
प्र: If 6 engines consume 24 metric tonnes of coal, when each is working 8 hours day, how much coal will be required for 9 engines, each running 13hours a day, it being given that 2 engines of former type consume as much as 3 engines of latter type ? 3498 05b5cc723e4d2b4197774f672
5b5cc723e4d2b4197774f672- 145 metric tonnestrue
- 247 metric tonnesfalse
- 355 metric tonnesfalse
- 434 metric tonnesfalse
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उत्तर : 1. "45 metric tonnes"
व्याख्या :
Answer: A) 45 metric tonnes Explanation: 2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton i.e. 3 engines of latter type consumes 1 ton for one hour Hence 9 engines consumes 3 tons for one hour For 15 hours it is 15 x 3 = 45 metric tonnes.
प्र: A thief steals half the total number of loaves of bread plus 1/2 loaf from a bakery. A second thief steals half the remaining number of loaves plus 1/2 loaf and so on. After the 5th thief has stolen there are no more loaves left in the bakery. What was the total number of loaves did the bakery have at the beginning ? 3482 05b5cc70ee4d2b4197774f33c
5b5cc70ee4d2b4197774f33c- 121false
- 211false
- 317false
- 431true
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उत्तर : 4. "31"
व्याख्या :
Answer: D) 31 Explanation: Let y be the total number of loavesa be the remaining loaves after 1st thiefb be the remaining loaves after 2nd thiefand c, d..so on after 3 and 4 the = 0 be the remaining loaves after 5th thief a = y - (y/2 + 1/2)= y/2 - 1/2 b = a - (a/2 + 1/2)= a/2 - 1/2 c = b - (b/2 + 1/2)= b/2 - 1/2 d = c - (c/2 + 1/2)= c/2 - 1/2 e = d - (d/2 + 1/2)= d/2 - 1/2we know that, e = 0,thus by substitution, we getd = 1c = 3b = 7a = 15y = 31Therefore total number of bread loaves in bakery was 31.
प्र: Each consonant in the word TIRADES is replaced by the previous letter in the English alphabet and each vowel is replaced by the next letter in the English alphabet and the new letters are arranged alphabetically. Which of the following will be the fourth from the right end ? 3465 05b5cc736e4d2b4197774f888
5b5cc736e4d2b4197774f888- 1Sfalse
- 2Qfalse
- 3Jtrue
- 4Ufalse
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उत्तर : 3. "J"
व्याख्या :
Answer: C) J Explanation: Given word is TIRADESNow the consonants T, R, D, S are replaced by S, Q, C, RAnd Vowels are I, A, E are replaced by J, B and FThey are arranged alphabeticallyNew word is BCFJQRS The fourth letter from the right end is J.
प्र: Fumble is to Finesse as Malign is to 3459 05b5cc6a2e4d2b4197774cba8
5b5cc6a2e4d2b4197774cba8- 1Slanderfalse
- 2Extoltrue
- 3Criticizefalse
- 4Assurancefalse
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उत्तर : 2. "Extol"
व्याख्या :
Answer: B) Extol Explanation: Fumble means grope, mishandle, drop, mistake, blunder, bungle. Finesse means skill, grace, elegance, assurance, diplomacy, discretion. So, they are opposites. Similarly, Malign means slander or criticize. Extol means being kind or good-natured. A person without finesse often fumbles. A person without extol in his heart often maligns. Extol means praise or exalt, benevolence
प्र: In a queue, Amrita is 10th from the front while Mukul is 25th from behind and Mamta is just in the middle of the two. If there be 50 persons in the queue. What position does Mamta occupy from the front ? 3458 05b5cc6f8e4d2b4197774f068
5b5cc6f8e4d2b4197774f068- 114thfalse
- 216thfalse
- 318thtrue
- 420thfalse
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उत्तर : 3. "18th"
व्याख्या :
Answer: C) 18th Explanation: Number of persons between Amrita and Mukul = 50 - (10 + 25) = 15. Since Mamta lies in middle of these 15 persons, so Mamta`s position is 8th from Amrita i.e. 18th from the front.
प्र: A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ? 3450 05b5cc731e4d2b4197774f7b5
5b5cc731e4d2b4197774f7b5- 11:3false
- 22:1false
- 33:2true
- 42:3false
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उत्तर : 3. "3:2"
व्याख्या :
Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.

