Answer: D) 31 Explanation: Let y be the total number of loavesa be the remaining loaves after 1st thiefb be the remaining loaves after 2nd thiefand c, d..so on after 3 and 4 the = 0 be the remaining loaves after 5th thief a = y - (y/2 + 1/2)= y/2 - 1/2 b = a - (a/2 + 1/2)= a/2 - 1/2 c = b - (b/2 + 1/2)= b/2 - 1/2 d = c - (c/2 + 1/2)= c/2 - 1/2 e = d - (d/2 + 1/2)= d/2 - 1/2we know that, e = 0,thus by substitution, we getd = 1c = 3b = 7a = 15y = 31Therefore total number of bread loaves in bakery was 31.

Answer: A) 19 Explanation: Initialy from left 7th = kumarfrom right 9th = pawanInterchange kumar = 11th from left, from right kumar = 9th;11+8 = 19;8 is 1,2,3,4,5,6,7(pawan),8,9,10,11(kumar),12,13,14,15,16,17,18,19;simply count the 9th place from right we will get total as 19.

Answer: A) decreases Explanation: When water freezes its density decreases. Water at ordinary temperatures contracts and increases in density as it is cooled, like most substances. But at about 4°C it reaches a maximum density and then decreases in density as it approaches the freezing point.

Answer: B) Extol Explanation: Fumble means grope, mishandle, drop, mistake, blunder, bungle. Finesse means skill, grace, elegance, assurance, diplomacy, discretion. So, they are opposites.   Similarly, Malign means slander or criticize. Extol means being kind or good-natured. A person without finesse often fumbles. A person without extol in his heart often maligns. Extol means praise or exalt, benevolence

Answer: C) 18th Explanation: Number of persons between Amrita and Mukul = 50 - (10 + 25) = 15. Since Mamta lies in middle of these 15 persons, so Mamta`s position is 8th from Amrita i.e. 18th from the front.

Answer: A) 45 metric tonnes Explanation: 2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton  i.e. 3 engines of latter type consumes 1 ton for one hour Hence 9 engines consumes 3 tons for one hour For 15 hours it is 15 x 3 = 45 metric tonnes.

Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.

छाया क्षेत्र किसी दिए गए भूकंप से १०४ से १४० डिग्री की कोणीय दूरी से पृथ्वी का वह क्षेत्र है जिसे कोई सीधी पी तरंगें प्राप्त नहीं होती हैं। छाया क्षेत्र S तरंगों के तरल कोर द्वारा पूरी तरह से बंद होने और P तरंगों के तरल कोर द्वारा मुड़े (अपवर्तित) होने के परिणामस्वरूप होता है। शैडो ज़ोन दो प्रकार के होते हैं: एक P तरंगों के लिए और दूसरा S तरंगों के लिए। पी तरंग छाया 104-140 डिग्री, दोनों तरफ; S तरंग छाया एक तरफ के 105 से दूसरी तरफ 105 तक।