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प्र: The age of Sohail, Afzal and Bilal are 17,16 and 12 respectively. If the age of Aslam also included the average of the ages is increased by 5. What is the age of Aslam? 3926 0

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    32
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    33
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    34
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    35
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उत्तर : 4. "35"
व्याख्या :

Answer: D) 35 Explanation: Given S = 17 yrs A = 16 yrs B = 12 yrs Average = 17 + 16 + 12/3 = 15 yrs Given if Aslam added to them, their average increases by 5 => Average of 4 members = 20 Let the age of Aslam be 'x' Then,  17 + 16 + 12 + x /4 = 20 => x = 80 - 45 => x = 35.    Hence, the age of Aslam is 35 yrs.

प्र: Is B2+ Paramagnetic or Diamagnetic? 3926 0

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उत्तर :
व्याख्या :

B2+ is a Paramagnetic.  The filled orbitals are σ(1s)22, σ∗(1s)22, σ(2s)22, σ∗(2s)22. The half-filled orbitals are π(2pxx) and π(2pyy). Since it posses 2 unpaired electrons, it is Paramagnetic in nature.

प्र: If NAMO = 172 and OM = 56  then, SHIVAY = ? 3922 0

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    606
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    415
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    504
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    404
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उत्तर : 3. "504"
व्याख्या :

Answer: C) 504 Explanation: (COUNTING OF LETTERS) NAMO = 14 + 1 + 13 + 15 = 43 x 4 = 172,  OM = 15 + 13 = 28 x 2 = 56, SHIVAY = 19 + 8 + 9 + 22 + 1 + 25 = 84 x 6 = 504

प्र: Select the correct statement about cellular respiration? 3916 0

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    All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule
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    All the carbon atoms in glucose ultimately incorporated during cellular respiration into NADH molecule
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    All the carbon atoms in glucose ultimately incorporated during cellular respiration into ATP molecule
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    All the carbon atoms in glucose ultimately incorporated during cellular respiration into water molecule
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उत्तर : 1. "All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule"
व्याख्या :

Answer: A) All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule Explanation: All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecules.

प्र: A batsman in his 17th innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17th innings ? 3903 0

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    34
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    36
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    35
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    37
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उत्तर : 4. "37"
व्याख्या :

Answer: D) 37 Explanation: 16x + 85 = 17(x + 3) x = 34 + 3 = 37

प्र: A 300m race is held between two players running 3m/s and 5m/s in swimming pool of 50m long. how many times the two player meet in opposite direction till the faster one completes the race ? 3900 0

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    3 times
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    4 times
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    5 times
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    2 times
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उत्तर : 1. "3 times"
व्याख्या :

Answer: A) 3 times Explanation: Let us assume A is the faster and B is slower, A takes 10s to finish a lap of 50 m, B takes 17s(approx) to finish a lap of 50 m.So at 11th sec A starts his 2nd lap by the time B will be in between so that is the first time they will meet each other, at 21st sec A starts his 3rd lap by the time B will be coming back to finish his 2nd lap. So that is the second time they meet in opposite. Then at 31st sec A will start his 4th lap by the time B would not even finish 2nd lap as he take 34(2*17) sec to finish 2 laps. So at 35th sec B will start his 3rd lap by the time A will be coming back to finish his 4th lap in the half way so they will meet 3rd time. At 41st sec A will start its fifth lap by the time B will be going to finish 3rd lap in same direction. At 50th second both will complete A's 5th lap and B's 3rd lap. So they will start next lap(A's 6th and B's 4th) from the same point in same direction. And A will finish the race after completing 300m(6*50) total distance and then they wont meet opposite to each other. So totally they met 3 times in opposite direction.

प्र: If 6 engines consume 24 metric tonnes of coal, when each is working 8 hours day, how much coal will be required for 9 engines, each running 13hours a day, it being given that 2 engines of former type consume as much as 3 engines of latter type ? 3880 0

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    45 metric tonnes
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    47 metric tonnes
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    55 metric tonnes
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    34 metric tonnes
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उत्तर : 1. "45 metric tonnes"
व्याख्या :

Answer: A) 45 metric tonnes Explanation: 2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton  i.e. 3 engines of latter type consumes 1 ton for one hour Hence 9 engines consumes 3 tons for one hour For 15 hours it is 15 x 3 = 45 metric tonnes.

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