GATE рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: Food : Stomach : : Fuel : ? 1621 05b5cc73de4d2b4197774f977
5b5cc73de4d2b4197774f977- 1truckfalse
- 2Planefalse
- 3Enginetrue
- 4Automobilefalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 3. "Engine"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) Engine Explanation: Food is processed by the stomach to provide energy for the functioning of the body.Similarly, fuel is processed by the engine to provide energy for the functioning of automobile.
рдкреНрд░: P, Q, R, S, T, U, V and W are sitting round the circle and are facing the centre:P is second to the right of T who is the neighbour of R and V.S is not the neighbour of P.V is the neighbour of U.Q is not between S and W. W is not between U and S. Then Who is sitting opposite to U ? 19680 05b5cc73de4d2b4197774f968
5b5cc73de4d2b4197774f968- 1Qfalse
- 2Ptrue
- 3Rfalse
- 4Wfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "P"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) P Explanation: From the given information, the sitting arrangement can be ┬аP-Q-W-S-U-V-T-R ┬аi.e. in circular as From the above figure it is clear that opposite to U is P.
рдкреНрд░: In a certain coding language, iF GO = 32 & SHE = 49 then SOME will be equal to ? 5964 05b5cc73de4d2b4197774f96d
5b5cc73de4d2b4197774f96d- 156true
- 258false
- 362false
- 464false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "56"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 56 Explanation: If we count letters till the end of the alphabet including that letter in reverse order then Here the values are nothing but the values corresponding to the alphabets when taken in a reverse order,i.e,A=26 ,B=25...,Z=1G = 20 and O = 12 totaling 32S = 8, H = 19 and E = 22 totaling 49 So SOME = 8 + 12 + 14 + 22 = 56.
рдкреНрд░: There are several peacocks and deers in a cage (with no other types of animals). There are 72 heads and 200 feet inside the cage. How many peacocks are there, and how many deers ? 2936 05b5cc73de4d2b4197774f95d
5b5cc73de4d2b4197774f95d- 142 & 24false
- 238 & 26false
- 336 & 24false
- 444 & 28true
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 4. "44 & 28"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 44 & 28 Explanation: Letx = peacocks y = deers 2x + 4y = 200 x + y = 72 y = 72 - x 2x + 288 - 4x = 200 x = 44 peacocks y = 28 deers
рдкреНрд░: Q's mother is sister of P and daughter of M who is brother of R. S is daughter of P and sister of T. How is M related to T ? 2008 05b5cc73de4d2b4197774f957
5b5cc73de4d2b4197774f957- 1Grand fathertrue
- 2Grand motherfalse
- 3Grand father or Grand motherfalse
- 4Can't be determinedfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 1. "Grand father"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) Grand father Explanation: Q's mother is sister of P and daughter of M => P is the child of M.S is daughter of P and sister of T, so P is parent of T too.M ----> parent --------> P ------------>parent -------------> TBut given M is brother of R => M is male. So, M is grandfather of T.
рдкреНрд░: Three taps I, J and K can fill a tank in 20,30and 40 minutes respectively. All the taps are opened simultaneously and after 5 minutes tap A was closed and then after 6 minutes tab B was closed .At the moment a leak developed which can empty the full tank in 70 minutes. What is the total time taken for the completely full ? 4585 05b5cc73de4d2b4197774f952
5b5cc73de4d2b4197774f952- 124.315 minutesfalse
- 226.166 minutestrue
- 322.154 minutesfalse
- 424 minutesfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 2. "26.166 minutes"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 26.166 minutes Explanation: Upto first 5 minutes I, J and K will fill => 5[(1/20)+(1/30)+(1/40)] = 65/120 For next 6 minutes, J and K will fill => 6[(1/30)+(1/40)] = 42/120 So tank filled upto first 11 minutes = (65/120) + (42/120) = 107/120 So remaining tank = 13/120 Now at the moment filling with C and leakage @ 1/60 per minute= (1/40) - (1/70) = 3/280.So time taken to fill remaining 13/120 tank =(13/120) /(3/280) = 91/6 minutes ┬а Hence total time taken to completely fill the tank = 5 + 6 + 91/6 = 26.16 minutes.
рдкреНрд░: The average of the ages of Sushanth, Krish and Rishi is 43 years and the average of the ages of Sushanth, Rishi and Rohit is 49 years. If Rohit is 54 years old, what is Krish's age ? 1729 05b5cc73de4d2b4197774f948
5b5cc73de4d2b4197774f948- 134 yearsfalse
- 226 yearsfalse
- 324 yearsfalse
- 436 yearstrue
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 4. "36 years"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) 36 years Explanation: Let present ages of Sushanth = w, Krish = x, Rishi = y and Rohit = z , thenw + x + y = 43 x 3 = 129 ---(i) andw + y + z = 49 x 3 = 147 ---(ii)Subtracting (i) from (ii), (w+y+z) - (w+x+y) = 147 - 129 , z - x = 18 ---(iii)Given Rohit's age=z=54, so from (iii), x = 54 - 18 = 36.Therefore, Krish age is 36 years.
рдкреНрд░: A can do a work in 9 days, B can do a work in 7 days, C can do a work in 5 days. A works on the first day, B works on the second day and C on the third day respectively that is they work on alternate days. When will they finish the work ? 1236 05b5cc73de4d2b4197774f94d
5b5cc73de4d2b4197774f94d- 1[7 + (215/345)] daysfalse
- 2[6 + (11/215)] daysfalse
- 3[6 + (261/315)] daystrue
- 4[5 + (112/351)] daysfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
- Workspace
- SingleChoice
рдЙрддреНрддрд░ : 3. "[6 + (261/315)] days"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) [6 + (261/315)] days Explanation: After day 1, A finishes 1/9 of the work. After day 2, B finishes 1/7 more of the total work. (1/9) + (1/7) is finished. After day 3, C finishes 1/5 more of total work. Total finished is 143/315. So, after day 6, total work finished is 286/315. ┬а Now remaining work =┬а 29 /315 ┬а On day 7, A will work again┬а ┬а Work will be completed on day 7 when A is working. He must finish 29/315 of total remaining work. ┬а Since he takes 9 days to finish the total task, he will need 261/315 of the day.┬а ┬а Total days required is 6 + (261/315) days.

