GATE प्रश्न और उत्तर का अभ्यास करें
8प्र: How many number of weights do you need to weight 31 kg of Rice if you have one kg of weight stone ? 3521 05b5cc736e4d2b4197774f879
5b5cc736e4d2b4197774f879- 13false
- 25true
- 37false
- 49false
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उत्तर : 2. "5"
व्याख्या :
Answer: B) 5 Explanation: There are total 5 ways.we have only one kg of weight so,2kg = 1kg + 1kg4kg = 1 + 2 + 18kg = 1 + 2 + 4 + 116kg = 1 + 2 + 4 + 8 + 131kg = 1 + 2 + 4 + 8 + 16So 5 weights are needed.
प्र: A merchant buys two items for Rs. 7500. One item he sells at a profit of 16% and the other item at 14% loss. In the deal, the merchant makes neither any profit nor any loss. What is the difference between the selling price of both the items? 3513 05b5cc69de4d2b4197774c88d
5b5cc69de4d2b4197774c88d- 1Rs. 620true
- 2Rs. 654false
- 3Rs. 725false
- 4Rs. 747false
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उत्तर : 1. "Rs. 620"
व्याख्या :
Answer: A) Rs. 620 Explanation: Let the C.P of one item is Rs. P and that of other is Rs. (7500 - P) According to the data given C.P = S.P => Px(116/100) + (7500-P)x(86/100) = 7500 => 30P = 105000 => P = 3500 Required difference between selling prices = Rs. [(3500/100) x 116] - [(4000/100) x 86] = 4060-3440 = Rs. 620
प्र: How many zeros are there from 1 to 10000 ? 3512 05b5cc741e4d2b4197774f9e0
5b5cc741e4d2b4197774f9e0- 12893true
- 24528false
- 36587false
- 44875false
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उत्तर : 1. "2893"
व्याख्या :
Answer: A) 2893 Explanation: For solving this problem first we would break the whole range in 5 sections 1) From 1 to 9Total number of zero in this range = 0 2) From 10 to 99Total possibilities = 9*1 = 9 ( here 9 is used for the possibilities of a non zero integer) 3) From 100 to 999 - three type of numbers are there in this range a) x00 b) x0x c) xx0 (here x represents a non zero number)Total possibilities for x00 = 9*1*1 = 9, hence total zeros = 9*2 = 18for x0x = 9*1*9 = 81, hence total zeros = 81similarly for xx0 = 81 total zeros in three digit numbers = 18 + 81 +81 = 180 4) From 1000 to 9999 - seven type of numbers are there in this rangea)x000 b)xx00 c)x0x0 d)x00x e)xxx0 f)xx0x g)x0xxTotal possibilities for x000 = 9*1*1*1 = 9, hence total zeros = 9*3 = 27 for xx00 = 9*9*1*1 = 81, hence total zeros = 81*2 = 162 for x0x0 = 9*1*9*1 = 81, hence total zeros = 81*2 = 162for x00x = 9*1*1*9 = 81, hence total zeros = 81*2 = 162 for xxx0 = 9*9*9*1 = 729, hence total zeros = 729*1 = 729for xx0x = 9*9*1*9 = 729, hence total zeros = 729*1 = 729for x0xx = 9*1*9*9 = 729, hence total zeros = 729*1 = 729total zeros in four digit numbers = 27 + 3*162 + 3*729 = 2700thus total zeros will be 0+9+180+2700+4 (last 4 is for 4 zeros of 10000)= 2893
प्र: कौन सी इकाई अस्थायी रूप से डेटा रखती है? 3510 05b5cc64de4d2b4197774bcb2
5b5cc64de4d2b4197774bcb2- 1सैकेंडरी स्टोरेज यूनिटfalse
- 2आउटपुट यूनिटfalse
- 3प्राइमरी मेमोरी यूनिटtrue
- 4इनपुट यूनिटfalse
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उत्तर : 3. "प्राइमरी मेमोरी यूनिट"
व्याख्या :
Answer: C) प्राथमिक मेमोरी यूनिट स्पष्टीकरण: मेमोरी कंप्यूटर का वह भाग है जो ALU द्वारा संसाधित किए जाने से पहले और बाद में अस्थायी रूप से डेटा और निर्देश रखता है। मेमोरी को प्राइमरी स्टोरेज, प्राइमरी मेमोरी, मेन स्टोरेज, इंटरनल स्टोरेज और मेन मेमोरी के रूप में भी जाना जाता है। निर्माता अक्सर RAM शब्द का उपयोग करते हैं, जिसका अर्थ है रैंडम-एक्सेस मेमोरी।
प्र: What Does My Name Mean, If my Mother is a Mathematician, and my Father is a Chemist. And they gave a Code to My Name as "Iron59". Crack my Name? 3509 05b5cc6ace4d2b4197774d07c
5b5cc6ace4d2b4197774d07c- 1Elixfalse
- 2Alexfalse
- 3Selixfalse
- 4Felixtrue
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उत्तर : 4. "Felix"
व्याख्या :
Answer: D) Felix Explanation: Here my name "Iron59" means Felix. Since my father is a chemist he gave code Iron for Fe as chemical symbol for Iron is Fe and my mother is a mathematician she gave 59 for Lix as Roman word for 59 is Lix. Hence my name is FELIX.
प्र: In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ? 3506 05b5cc74ae4d2b4197774fa9a
5b5cc74ae4d2b4197774fa9a- 118false
- 214true
- 322false
- 424false
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उत्तर : 2. "14"
व्याख्या :
Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14
प्र: Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest ? 3505 05b5cc6ebe4d2b4197774eeb9
5b5cc6ebe4d2b4197774eeb9- 120% p.atrue
- 215% p.afalse
- 318% p.afalse
- 424% p.afalse
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उत्तर : 1. "20% p.a"
व्याख्या :
Answer: A) 20% p.a Explanation: Rs.1440 - 1200 = Rs.240 is the interest on Rs.1200 for one year. Rate of interest = (100 x 240) / (1200) = 20% p.a
प्र: If 10 men take 15 days to complete a work. In how many days will 37 men complete the work? 3504 05b5cc6bfe4d2b4197774da3d
5b5cc6bfe4d2b4197774da3d- 13 daysfalse
- 24 daystrue
- 35 daysfalse
- 46 daysfalse
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उत्तर : 2. "4 days"
व्याख्या :
Answer: B) 4 days Explanation: Given 10 men take 15 days to complete a work => Total mandays = 15 x 10 = 150 Let the work be 150 mandays. => Now 37 men can do 150 mandays in 150/37 =~ 4 days

