Answer: C) Rs.200 Explanation: Let the article costs 'X' to ACost price of B = 1.2XCost price of C = 0.75(1.2X) = 0.9XCost price of D = 1.4(0.9X) = 1.26X = 252Amount paid by A for the article = Rs. 200.

Answer: C) Deuce Explanation: When both sides have won the same number of points then: when each side has won one, or two, points, the score is described as "15-all" and "30-all" (or "15-up" and "30-up"), respectively. However, if each player has won three points, the score is called as "deuce", not "40–all". From that point on in the game, whenever the score is tied, it is described as "deuce", regardless of how many points have been played.

Answer: A) LiCH3 Explanation: The stability of the ions is determined by the energy of the lone pairs. Carbon has the least effective nuclear charge (Zeff) and so the lone pair on the CH3− ion has the highest energy, making it the least stable ion and so the strongest base. The Zeff increases as we move across the period until we get to fluorine which has the greatest Zeff and so its lone pairs have the lowest energy, making F− the least basic ion.   In order of decreasing basicity they are ranked LiCH3 > LiNH2 > LiOH > LiF. We are dealing with the ions F−, OH−, NH2− and CH3− and so the factor which influences their basicity is the stability of the ion compared to its conjugate acid.

Answer: D) Trajectory Explanation: The path traced by planet is called Orbit. Similarly, the path traced by projectile is called Trajectory.   Hence, Planet : Orbit : : Projectile : Trajectory.

Answer: D) the capacity of layers of metal ions to slide over the other Explanation:

Answer: C) 418 Explanation: Let the total book be 1 Then, in the 1st week 613th of book is read i.e remaining pages =  1-613=713 in 2nd week he read 59th of it i.e 59×713=35117Remaining pages after 2nd week = 713-35117=28117 But given remaining pages after 2nd week = 100   28x117=100 --> x = 418   The total pages in the book are 418

Answer: C) Both (A) and (B) follows Explanation:

Answer: C) 10 Explanation: Let the price of each note book be Rs.x. Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y. Hence xy = 300 => y = 300/x (x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy =>5(300/x) - 10x - 50 = 0 => -150+x2+5x multiplying both sides by -1/10x => x2+15x-10x-150=0 => x(x + 15) - 10(x + 15) = 0 => x = 10 or -15 As x>0, x = 10.