GRE प्रश्न और उत्तर का अभ्यास करें

प्र: A group of men can complete a job in K hours. After every 4 hours, half the number of men working at that point of time leave the job. Continuing this way if the job is finished in 16 hours, what is the value of K ? 4326 0

  • 1
    7 hrs
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  • 2
    7.5 hrs
    सही
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  • 3
    8 hrs
    सही
    गलत
  • 4
    8.25 hrs
    सही
    गलत
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उत्तर : 2. "7.5 hrs"
व्याख्या :

Answer: B) 7.5 hrs Explanation: Let there are L men job requires LK man hours.   job completed in first 4 hrs = L x 4 = 4L job completed in next 4 hrs = 4 x L/2 = 2L job completed in next 4 hrs = 4 x L/4 = L job completed in last 4 hrs = 4 x L/8 = L/2 4L + 2L + L + L/2 = KL K = 7+1/2 = 7.5 hours.

प्र: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4319 0

  • 1
    1124
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  • 2
    1420
    सही
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  • 3
    1345
    सही
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  • 4
    1250
    सही
    गलत
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उत्तर : 4. "1250"
व्याख्या :

Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.

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उत्तर :
व्याख्या :

1. Answer (2) G 2. Answer (1) BE All other pairs are in same class. 3. Answer (3) ADF in class 9. 4. Answer (4) Linc pen.

प्र: 5 years ago Sushma was 5 times as old as her Son. 5 years hence her age will be 8 less than three times the corresponding age of her Son. Find their ages ? 4285 0

  • 1
    24 and 13 years
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  • 2
    48 and 24 years
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  • 3
    35 and 11 years
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  • 4
    33 and 15 years
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उत्तर : 3. "35 and 11 years"
व्याख्या :

Answer: C) 35 and 11 years Explanation: Let the age of sushma be x and the age of her son is yThen five years before x-5=5(y-5) ...(1)Five years hence x+5 = 3(y+5)-8 .....(2) By soving (1) & (2), we get5y - 15 = 3y + 7y = 11 => x = 35 Therefore, the age of Sushma = 35 and her son = 11.

प्र: Which alphabet replaces the question mark ? 63 O 4972 T 3796 L 1514 ? 58 4235 0

  • 1
    A
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  • 2
    B
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  • 3
    C
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  • 4
    D
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उत्तर : 3. "C"
व्याख्या :

Answer: C) C Explanation: 6-3 = 3 9-4 = 5 (3x5=15) 15=O7-2 = 5 7-3 = 4 (5x4=20) 20=T9-6 = 3 5-1 = 4 (3x4=12) 12=L Similarly, 4-1 = 3 8-5 = 1 (3x1=3) 3=C

प्र: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 4229 0

  • 1
    75 min
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  • 2
    82 min
    सही
    गलत
  • 3
    90 min
    सही
    गलत
  • 4
    101 min
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उत्तर : 3. "90 min"
व्याख्या :

Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.

प्र: Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ? 4186 0

  • 1
    7 : 12
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  • 2
    8 : 13
    सही
    गलत
  • 3
    9 : 4
    सही
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  • 4
    2 : 5
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उत्तर : 2. "8 : 13"
व्याख्या :

Answer: B) 8 : 13 Explanation: To get the solution that contains 1 part of milk and two parts of water,they must be mixed in the ratio as7x+6x/5y+11y = 1/226x = 16yx/y = 16/26x/y = 8/13

प्र: Ten years ago, Karan was thrice as old as Shiva was but 10 years hence, he will be only twice as old. Find Shiva’s present age ? 4185 0

  • 1
    70 years
    सही
    गलत
  • 2
    30 years
    सही
    गलत
  • 3
    60 years
    सही
    गलत
  • 4
    40 years
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उत्तर : 2. "30 years"
व्याख्या :

Answer: B) 30 years Explanation: Let Karan’s present age be x years and Shiva’s present age be y years.Then, according to the first condition,x - 10 = 3(y - 10) or x - 3y = - 20 ..(1) Now, Karan’s age after 10 years = (x + 10) yearsShiva’s age after 10 years = (y + 10)(x + 10) = 2 (y + 10) or x - 2y = 10 ..(2) Solving (1) and (2), we get x = 70 and y = 30Karan’s age = 70 years and Shiva’s age = 30 years.

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