GRE рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ

рдкреНрд░: In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by ? 1517 0

  • 1
    25 m
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    21 m
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  • 3
    22 m
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  • 4
    19 m
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  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 1. "25 m"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: A) 25 m Explanation: A:B = 200 : 169A:C = 200 : 182┬аCB┬а=┬аCA├ЧAB┬а ┬а 182200├Ч200169 ┬а => 182:169 ┬а When C covers 182 m , B Covers 169 mWhen C covers 350 m , B Covers┬а169182├Ч350=> 325 m ┬а ┬а ┬а So C beats B by (350 - 325) = 25 m.

рдкреНрд░: 'K' cycled from A to B at 10 kmph and returned at the rate of 9 kmph. 'L' cycled both ways at 12 kmph. In the whole journey 'L' took 10 minutes less than 'K'. Find the distance between A and B ? 1562 0

  • 1
    32.1 km
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  • 2
    15.23 km
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  • 3
    3.75 km
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  • 4
    32.1 m
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  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "3.75 km"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) 3.75 km Explanation: Let 'd' be the distance between A and BK -time = d/10 + d/9 = 19d/90 hoursL -time = 2d/12 = d/6 hoursWe know that, 10 min = 1/6 hoursThus, time difference between K and L is given as 10 minutes. => 19d/90 - d/6 = 1/6=> (19d-15d)/90 = 1/6=> 4d/90 = 1/6Thus,d= 15/4 km = 3.75 km. hence the distance between A and B is 3.75 km.

рдкреНрд░: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4109 0

  • 1
    1124
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  • 2
    1420
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  • 3
    1345
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    рдЧрд▓рдд
  • 4
    1250
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    рдЧрд▓рдд
  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 4. "1250"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.

рдкреНрд░: The amount of water (in ml) that should be added to reduce 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol is ? 2732 0

  • 1
    6 ml
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    11 ml
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  • 3
    15 ml
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  • 4
    9 ml
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    рдЧрд▓рдд
  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 1. "6 ml"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: A) 6 ml Explanation: Let us assume that the lotion has 50% alcohol and 50% water.ratio = 1:1As the total solution is 9mlalcohol = water = 4.5mlNow if we want the quantity of alcohol = 30%The quantity of water = 70%The new ratio = 3:7Let x ml of water be addedWe get,4.54.5+x┬а=┬а37=> x=6Hence 6ml of water is added.

рдкреНрд░: A store owner is packing books into larger boxes that measure 25 by 42 by 60 inches. If the measurement of each book is 7 by 6 by 5 inches, then how many books can be placed in the box ? 1986 0

  • 1
    175
    рд╕рд╣реА
    рдЧрд▓рдд
  • 2
    345
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  • 3
    265
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    рдЧрд▓рдд
  • 4
    300
    рд╕рд╣реА
    рдЧрд▓рдд
  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 4. "300"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: D) 300 Explanation: Number of books that can be placed in the larger box is given by Volume of Box / Volume of book.Now, n = 25 x 42 x 60 / 7 x 6 x 5 = 63000 / 210 = 300.Therefore, 300 books can be in that box.

рдкреНрд░: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats ? 2345 0

  • 1
    1 : 2 : 3
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  • 2
    2 : 3 : 4
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  • 3
    3: 4 : 5
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  • 4
    4 : 5 : 6
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  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "2 : 3 : 4"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 2 : 3 : 4 Explanation: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. Seats for Mathematics, Physics and Biology in a school are 5x, 7x and 8x. There is a proposal to increase these seats by 40%, 50% and 75% respectively. Then Seats for Mathematics, Physics and Biology in a school will be 1.4 X 5x, 1.5 X 7x and 1.75 X 8x and ratio will be 7 : 10.5 : 14 ┬а=> 2:3:4.

рдкреНрд░: A constructor estimates that 4 people can paint Mr. Karthik's house in 6 days. If he uses 5 people instead of 4, how long will they take to complete the job ? 2655 0

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    3 days
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    26/3 days
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  • 3
    13/4 days
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  • 4
    24/5 days
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  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
  • Workspace

рдЙрддреНрддрд░ : 4. "24/5 days"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: D) 24/5 days Explanation: we know that m1 x d1 = m2 x d2=> 4 x 6 = 5 x dwhere d = no. of days taken by 5 men to paintd = 24/5 days.

рдкреНрд░: If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ? 2965 1

  • 1
    Rs. 175
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  • 2
    Rs. 325
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  • 3
    Rs. 340
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  • 4
    Rs. 260
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  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "Rs. 340"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) Rs. 340 Explanation: Assume first child (the youngest) get = Rs. x According to the question ;each son having Rs. 30 more than the younger one Second child will get = Rs. x + 30 Third child will get = Rs. x + 30 + 30 = x + 60 Forth child will get = Rs. x + 30 + 30 + 30 = x + 90 Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120 Total amount they got = Rs. 2000 x + (x+30) + (x+60) + (x+90) + (x+120) = 20005x + 300 = 20005x = 1700x = Rs. 340So the youngest child will get Rs. 340.

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ