GRE Practice Question and Answer
8Q: वह कंप्यूटर जो एनालॉग और डिजिटल दोनों को प्रोसेस करता है, कहलाता है 11630 15b5cc666e4d2b4197774bf0d
5b5cc666e4d2b4197774bf0d- 1हाइब्रिड कंप्यूटरtrue
- 2मेनफ़्रेम कंप्यूटरfalse
- 3डिजिटल कम्प्यूटरfalse
- 4एनालॉग कंप्यूटरfalse
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Answer : 1. "हाइब्रिड कंप्यूटर"
Explanation :
Answer: A) हाइब्रिड कंप्यूटर व्याख्या: वह कंप्यूटर जो एनालॉग और डिजिटल दोनों को प्रोसेस करता है, हाइब्रिड कंप्यूटर कहलाता है।
Q: एक पर्सनल कंप्यूटर की शब्द लंबाई है 2119 05b5cc642e4d2b4197774bb7c
5b5cc642e4d2b4197774bb7c- 132 bitfalse
- 216 bitfalse
- 38 bittrue
- 44 bitfalse
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Answer : 3. "8 bit"
Explanation :
Answer: C) 8 bit व्याख्या: शब्द की लंबाई कंप्यूटर के सीपीयू द्वारा एक बार में संसाधित बिट्स की संख्या को संदर्भित करती है। इन दिनों, आमतौर पर 32 बिट या 64 बिट का उपयोग किया जाता है। डेटा बस आकार, निर्देश आकार, पता आकार आमतौर पर शब्द आकार के गुणक होते हैं।
Q: What was the day of the week on 17th June, 1998 ? 4732 75b5cc761e4d2b4197774fd16
5b5cc761e4d2b4197774fd16- 1Mondayfalse
- 2Tuesdayfalse
- 3Wednesdaytrue
- 4Fridayfalse
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Answer : 3. "Wednesday"
Explanation :
Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.
Q: CK169JROS2419TXKM??PV 1560 05b5cc7b9e4d2b4197775097d
5b5cc7b9e4d2b4197775097d- 114,21false
- 221,14true
- 356,84false
- 484,56false
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Answer : 2. "21,14"
Explanation :
Answer: B) 21,14 Explanation: Putting A=1, B=2, C=3,..., M=13,....,X=24,Y=25, Z=26, we have : JR = J + R2 + 2 = 10 + 18 2 + 2 = 16 CK = C + K2 + 2 = 3 + 112 + 2 = 9 TX = T + X2+ 2 = 20 + 242 + 2 = 24 OS = O + S2 + 2 = 15 + 192 + 2 = 19 So, the missing numbers are : 21 and 14 Hence, the answer is (b).
Q: If A + B = 2C and C + D = 2A, then 5457 05b5cc7b9e4d2b4197775096e
5b5cc7b9e4d2b4197775096e- 1A + C = B + Dtrue
- 2A + C = 2Dfalse
- 3A + D = B + Cfalse
- 4A + C = 2Bfalse
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Answer : 1. "A + C = B + D"
Explanation :
Answer: A) A + C = B + D Explanation: Given, A + B = 2C ----(i) C + D = 2A----(ii) Adding (i) and (ii) we get : A + B + C + D = 2C + 2A => B + D = A + C
Q: Three persons P,Q and R wore shirts of White, Black and Blue colours (not necessarily in that order) and pants of Green, Red and White colours (not necessarily in that order). No persons wore shirts and pants of same colour. And further it is given that 1.A did not wear shirt of Black colour.2.B did not wear shirt of Blue colour.3.C did not wear shirt of White colour.4.A did not wear pants of Green colour.5.B wear pant of White colour. What were the colours of the pant and shirt wear by person A respectively? 2085 05b5cc777e4d2b419777500c5
5b5cc777e4d2b419777500c5- 1Green and Bluefalse
- 2White and Blackfalse
- 3Red and Whitetrue
- 4Green and Whitefalse
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Answer : 3. "Red and White"
Explanation :
Answer: C) Red and White Explanation:
Q: Out of 120 students in aschool, 5% can play all the three games Cricket, Chess and Carroms. If so happens that the number of players who can play any and only two games is 30. The number of students who can play the Cricket alone is 40. What is the total number of those who can play Chess alone or Carroms alone ? 8404 05b5cc774e4d2b4197775006b
5b5cc774e4d2b4197775006b- 145false
- 244true
- 346false
- 424false
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Answer : 2. "44"
Explanation :
Answer: B) 44 Explanation: Given U=120 5% of 120 = 6 Therefore, Students who can play Chess alone or Carroms alone = 120 - (30+40+6)= 44
Q: Bhel commissions another 600Mw thermal unit in which state ? 1286 15b5cc774e4d2b41977750061
5b5cc774e4d2b41977750061- 1Telanganatrue
- 2Andhra Pradeshfalse
- 3Chattisgarhfalse
- 4Karnatakafalse
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Answer : 1. "Telangana"
Explanation :
Answer: A) Telangana Explanation: