GRE Practice Question and Answer
8Q: Fill in the blank with suitable preposition in the following sentence. ____ the two I prefer tea. 2847 05b5cc642e4d2b4197774bb86
5b5cc642e4d2b4197774bb86- 1Fromfalse
- 2Infalse
- 3Betweentrue
- 4Amongfalse
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Answer : 3. "Between"
Explanation :
Answer: C) Between Explanation: Between the two I prefer tea is the correct sentence with suitable preposition.
Q: What building has the most stories? 2844 05b5cc64ae4d2b4197774bbf6
5b5cc64ae4d2b4197774bbf6- Show AnswerHide Answer
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Answer :
Explanation :
A Libraury. It has more number of story books in it to read.
Q: 'A' sold an article to 'B' at a profit of 20%. 'B' sold the same article to 'C' at a loss of 25% and 'C' sold the same article to 'D' at a profit of 40%. If 'D' paid Rs 252 for the article, then find how much did 'A' pay for it? 2839 05b5cc75ee4d2b4197774fca2
5b5cc75ee4d2b4197774fca2- 1Rs.196false
- 2Rs.210false
- 3Rs.200true
- 4Rs.235false
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Answer : 3. "Rs.200"
Explanation :
Answer: C) Rs.200 Explanation: Let the article costs 'X' to ACost price of B = 1.2XCost price of C = 0.75(1.2X) = 0.9XCost price of D = 1.4(0.9X) = 1.26X = 252Amount paid by A for the article = Rs. 200.
Q: क्लिपबोर्ड 2839 15b5cc672e4d2b4197774c0aa
5b5cc672e4d2b4197774c0aa- 1एक कैश मेमोरी हैfalse
- 2एक सुविधा है जो उपयोगकर्ता की जानकारी संग्रहीत करती हैfalse
- 3अस्थायी रूप से स्टोर करने के लिए उपयोग किया जाता है, जो आइटम कट या कॉपी किए गए हैंtrue
- 4एक ऐसी सुविधा है जो फ़ाइल को अस्थायी रूप से सहेजती हैfalse
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Answer : 3. "अस्थायी रूप से स्टोर करने के लिए उपयोग किया जाता है, जो आइटम कट या कॉपी किए गए हैं"
Explanation :
Answer: C) काटे गए या कॉपी किए गए आइटम को अस्थायी रूप से स्टोर करने के लिए उपयोग किया जाता है स्पष्टीकरण: क्लिपबोर्ड उन वस्तुओं के लिए एक अस्थायी भंडारण क्षेत्र है जिसे उपयोगकर्ता एक स्थान से दूसरे स्थान पर काटना या कॉपी करना चाहता है। उदाहरण के लिए, किसी शब्द संसाधक अनुप्रयोग में, उपयोगकर्ता किसी दस्तावेज़ के एक भाग से पाठ को काटना और दस्तावेज़ के दूसरे भाग में चिपकाना चाहता है या कहीं और, यह अस्थायी रूप से क्लिपबोर्ड में संग्रहीत होता है।
Q: Find out the wrong term in the given series of numbers ?6, 15, 35, 77, 165, 221 2836 05b5cc728e4d2b4197774f6dc
5b5cc728e4d2b4197774f6dc- 135false
- 2165true
- 3221false
- 477false
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Answer : 2. "165"
Explanation :
Answer: B) 165 Explanation: The given series follow the rule that : Multiplying consecutive prime numbers2,3,5,7,11,13,17,19....2x3 = 63x5 = 155x7 = 357x11 = 7711x13 = 14313x17 = 221So, the wrong term is 165.
Q: If a Siren sounds for every 5 seconds, how many times will it sound in ¾ of an hour? 2835 05b5cc76ae4d2b4197774fea3
5b5cc76ae4d2b4197774fea3- 1541 timestrue
- 2540 timesfalse
- 3450 timesfalse
- 4275 timesfalse
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Answer : 1. "541 times"
Explanation :
Answer: A) 541 times Explanation: There are 60 minutes in an hour. In ¾ of an hour there are (60 × ¾) minutes = 45 minutes. In ¾ of an hour there are (60 × 45) seconds = 2700 seconds. Siren sounds for every 5 seconds. In 2700 seconds = 2700/5 = 540 times. The count start after the first sound, the Siren will sound 541 times in ¾ of an hour.
Q: Arrange the given words in alphabetical order and tick the one that comes in the middle ? 2835 05b5cc6fee4d2b4197774f120
5b5cc6fee4d2b4197774f120- 1Slaughtertrue
- 2Skirtfalse
- 3Straightfalse
- 4Shoutfalse
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Answer : 1. "Slaughter"
Explanation :
Answer: A) Slaughter Explanation: The arrangement in the alphabetical order is Shout, Skirt, Slaughter, Specify, Straight. The word in the middle is Slaughter.
Q: An intelligent boy is doing a jigsaw with 275 pieces. Each day that he fits pieces together there are fewer pieces left, and it is reasonable to assume that he fits more pieces each day because the number left to sort out diminishes progressively. Hence he is able to fit an extra piece as each day goes by. On the first day he fits 20 pieces. How many days does it take for him to complete the puzzle ? 2827 05b5cc71ee4d2b4197774f59a
5b5cc71ee4d2b4197774f59a- 111 daystrue
- 215 daysfalse
- 313 daysfalse
- 416 daysfalse
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Answer : 1. "11 days"
Explanation :
Answer: A) 11 days Explanation: Let 'n' number of days it take to complete. we know that sum of n number= n/2[2a+(n-1)d]where a=20,d=1;n/2[2x20+(n-1)1]=275n[n+39]=550n2 + 39n - 550 = 0 n2+ 50n - 11n - 550 = 0(n-11) (n-50) = 0n-11 = 0;n = 11(Days).