Answer: D) Donald Trump Explanation: Donald John Trump (born June 14, 1946) is an American businessman, television personality, politician, and the 45th President of the United States.

Answer: B) only B alone is sufficient Explanation: For the given problem there are three possiblities.Father's age can be = 36, 31, 29Mother's age = 32, 27, 25Son's age = 8, 3, 1. By using only B it can be calculated.

Answer: B) 1/2 Explanation: Multiples of 3 below 20 are 3, 6, 9, 12, 15, 18 Multiples of 5 below 20 are 5, 10, 15, 20 Required number of possibilities = 10Total number of possibilities = 20Required probability = 10/20 = 1/2.

Answer: B) Both b & c follows Explanation: Clearly, People cannot be deprived of enjoying the festival for lack of arrangements. Also, it becomes necessary to deploy police to regulate big crowds and avert any mishap in public gatherings. Further, it costs nothing but might prove useful to put hospitals on alert to be ready to provide quick medical aid to patients in case of any eventuality. So, both b and c follow.

Answer: B) 41 Explanation: Given P = 54 and M = 80 According to the question, Let ‘A’ years ago, M = 3P => M - A/P - A = 3 => 80 - A = 3(54 - A) => 80 - A = 162 - 3A => 2A = 82 => A = 41 Therefore, A = 41 years ago Sweety’s mother was 3 times of Sweety’s age. Hence, at the age S = 13 and M = 39.

Answer: B) 26 Explanation: The total cards in the deck are 52. These 52 cards are divided into 4 suits of 13 cards in each suit. Two Red suits and Two black suits. Red suits :: Heart suit and Diamond suit = 26 Black suits :: Spade suit and Club suit = 26.

Answer: D) Both a and b sufficient Explanation: Let the sum be Rs. x a. gives, S.I = Rs. 9000 and time = 9 years. b. gives, Sum + S.I for 6 years = 2 x Sum --> Sum = S.I for 6 years. Now, S.I for 9 years = Rs. 9000 S.I for 1 year = Rs. 9000/9 = Rs. 1000. S.I for 6 years = Rs. (1000 x 6)= Rs. 6000. --> x = Rs. 6000 Thus, both a and b are necessary to answer the question.

Out of 4 fruits, any 3 are chosen by 4 families.So the combinations areApple - A Cherries - C Banana - B Grapes - G1) ACB2) ACG3) BCG4) GAB By 2nd condition, Miller family uses either i)ACB or ii)ACGNow we have Robin, Mandy and Miller who uses apples (ACB,ACG,GAB)while Miller and Mandy both uses A and C. That leaves GAB for Robin. By 3rd condition Flure uses either C or G. So if we leave out the terms containing both C and G, we are left with ACB and GAB Now, for the time being let's suppose Robin is not a Flure.So ACB is taken by Flure. So ACG has to be Miller and that leaves BCG to be Clark. So we get Robin - Jacob(GAB). By 4th and 2nd conditions Erica and Mandy belong to the first two. That leaves Stacy - Clark(BCG). By 2nd condition Mandy is not a Miller, so we get Mandy - Flure(ACB) and that leaves Erica - Miller(ACG).