IIT JEE рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ

рдкреНрд░: Can yoy guess the Age of Karthik & Kalyan ┬а? 1806 0

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    68 & 44
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    64 & 48
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    58 & 54
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    76 & 36
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  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "64 & 48"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 64 & 48 Explanation: Given Karthik + Kalyan = 112 Given that when karthik is at the age of kalyan he is twice of Kalyan's age i.e When he was 48 means Kalyan is at 24 => Present age of Kalyan is 48 And that of Karthik is 112 - 48 = 64

рдкреНрд░: Guess the Number which satisfies the Logic behind ┬а? 1774 0

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    7
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    14
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    10
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    19
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  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 3. "10"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) 10 Explanation: Adding the corresponding numbers in first and last figures gives the corresponding number in the middle figure. i.e, 4 + 3 = 7 13 + 2 = 15 2 + 4 = 6 9 + 1 = 10

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рдЙрддреНрддрд░ : 3. "7, 0, 1"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) 7, 0, 1 Explanation: 0 1 2 3 4 5 6 7 8 9 0 1 4 8 2 6 5 7 3 9 Here pairs interchanged are 2, 4┬а 3, 8 5, 6 Unchanged are 0, 1, 7, 9

  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "&N4 and @E9"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) &N4 and @E9 Explanation: plan is given in first step. Total count of letters is 4 and last letter is N and тАШpтАЩ is coded as & so Final answer will be- ┬а&N4 We have to find 'translate' code. As we can see that this word is not given in any steps but as we know the idea of that so we can solve it. Step I: first we will count the letters of that word that is 9, then we put digit 9 at the right end. Step II: we will put the last letter of that word then it will like- E9 Step III: at the last step тАШtтАЩ is coded for тАШ@тАЩ(first letter of each word is coded by a specific symbol like here тАШtтАЩ is coded for тАШ@тАЩ. We can find the first coded symbol by looking at the other given words. Answer will be - @E9

рдкреНрд░: Guess the Hiding Letter ┬а? 1871 0

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    D
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    K
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    L
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    G
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  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 4. "G"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: D) G Explanation: Starting from letter 'S' add 5 in the clock wise direction to get the next letter in English alphabets. Here S + 5 => 19 + 5 = 24 => X X + 5 = 24 + 5 = 3 => C Similarly,┬а B + 5 = G

рдкреНрд░: Now my value becomes ? 1590 0

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    5
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    10
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    15
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    12
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  • рдЙрддреНрддрд░ рджреЗрдЦреЗрдВрдЙрддреНрддрд░ рдЫрд┐рдкрд╛рдПрдВ
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рдЙрддреНрддрд░ : 2. "10"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 10 Explanation: In the first figure, number of triangles are 5. In the second, the figure becomes double then the number of triangles also doubles. i.e, 10.

рдкреНрд░: What is the value of KL ? Statement A: K2= 4.Statement B: L = 0. 1749 0

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    Only A is sufficient
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    Only B is sufficient
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    Both (A) and (B) are sufficient
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    A) and (B) are sufficient D)
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рдЙрддреНрддрд░ : 2. "Only B is sufficient"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) Only B is sufficient Explanation: From statement B,┬а As the value of L = 0, the value of KL = 0. Hence only statement B is sufficient.

рдкреНрд░: How long will it take for two pipes A and B to fill an empty cistern if they worked alternately for an hour each ? A. Working alone, Pipe A can fill the cistern in 40 hoursB. Pipe B is one third as efficient as Pipe A 1973 0

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    Only A is sufficient
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    Only B is sufficient
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    Both (A) and (B) are sufficient
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    A) and (B) are sufficient D)
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рдЙрддреНрддрд░ : 3. "Both (A) and (B) are sufficient"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) Both (A) and (B) are sufficient Explanation: From statement A, we know that Pipe A can fill the tank in 40 hours. However, this information is not sufficient as we do not have the data for Pipe B. Hence, statement A alone cannot answer the given question.From statement B, we know that Pipe B is one third as efficient as pipe A. However, we do not know the rate at which Pipe A fills the tank. Hence, we will not be able to find the rate at which Pipe B fills the cistern. Therefore, statement B alone is not sufficient to answer the question.Now, if we combine the two statements, we know that Pipe A take 40 hours to fill the cistern.Pipe B takes 120 hours to fill the cistern.If they worked alternately, then either Pipe A could have started the cycle or Pipe B could have started the cycle.If Pipe A started the sequence of filling alternately, then at the end of two hours, the two pipes together would have filled 1/40 + 1/120 = 1/30 ┬аth of the tank in an hour. Or the cistern will fill in 30 hours.If Pipe B started the sequence, then at the end of 2 hours, the two pipes together would have filled 1/120 + 1/40 = 1/30 th of the tank in an hour. Or the cistern will fill in 30 hours.As the answer obtained irrespective of which pipe started the sequence is the same, the correct answer is (3) - i.e., both the statement are sufficient to answer the question.

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

      рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

    рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
    рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ