Answer: C) 60 days Explanation: In this problem , it has considered that 65 mins = 1hr So mins has increased by 5 mins so multiply 5 x 24 = 120 mins extra ,That is now per day it adds 2hr extra, so divide 1440/26 = 59.384 days =~ 60 days.

Answer: D) 31st October Explanation:

Answer: A) Thursday Explanation: Given monday population = 3000Per day 20% increase in population. Tuesday population = 3000 + 3000x20/100 = 3000 + 600 = 3600 Wednesday population =3600 + 3600x20/100 = 3600 + 720 = 4320 Thursday population = 4320 + 4320x20/100 = 4320 + 864 = 5184 So that day is Thursday.

Answer: C) 36 Explanation: Required Number of ways = 4C2 × 3C2 × 2C1 = 36 = 36

Answer: D) XZV Explanation: In the given series, each letter moves seven letters forward to obtain the next.So, XZV replaces ? in the series.

Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a)   2(3b + 2g) = 7 6b + 4g = 7 ........(b)   Solving (a) & (b), we get b = 1, g = 1/4   Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2.   Hence, number of girls required = 2

Answer: D) 25 Explanation: We know that, to be in the form that the number of rows and the number of columns to be equal the number should be a perfect square (a2). Given number is 1200 The perfect number which is above and near to 1200 is 1225 which is 35  35. Therefore, The minimum number of coins he need is 25.

Answer: B) Rs. 11,500 Explanation: Manager's monthly salary = Rs. (1900 x 25 - 1500 x 24) = Rs. 11,500