IIT JEE Practice Question and Answer
8Q: Which must be true for metamorphism to occur? 2132 05b5cc666e4d2b4197774bf21
5b5cc666e4d2b4197774bf21- 1The parent rock must be in solid form.false
- 2Tons of pressure must be applied.false
- 3The process must take place underground.false
- 4All the abovetrue
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Answer : 4. "All the above"
Explanation :
Answer: D) All the above Explanation: Metamorphism is the change of minerals or geologic texture in pre-existing rocks, without the protolith melting into liquid magma. The change occurs primarily due to heat, pressure, and the introduction of chemically active fluids. The parent rock must be in solid form. Tons of pressure must be applied for metamorphism to happen. The process must take place underground.
Q: Where is glucose stored in the body? 2129 05b5cc670e4d2b4197774c025
5b5cc670e4d2b4197774c025- 1bonesfalse
- 2bloodtrue
- 3organsfalse
- 4None of the abovefalse
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Answer : 2. "blood"
Explanation :
Answer: B) blood Explanation: In human body, glucose is stored in blood stream before it is converted to glycogen. Excess glucose is stored in the form of fats. After conversion, glycogen is stored in Muscles and Liver.
Q: Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour ? 2128 05b5cc6e2e4d2b4197774ec57
5b5cc6e2e4d2b4197774ec57- 12 hrsfalse
- 220 mintrue
- 340 minfalse
- 430 minfalse
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Answer : 2. "20 min"
Explanation :
Answer: B) 20 min Explanation: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages. Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr. stoppage time = 20/60 hrs = 20 min.
Q: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most ? 2128 05b5cc6e1e4d2b4197774ebde
5b5cc6e1e4d2b4197774ebde- 1215true
- 2268false
- 3254false
- 4216false
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Answer : 1. "215"
Explanation :
Answer: A) 215 Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 x 6 x 6 = 216. Of these attempts, one of them is a successful attempt. Maximum number of unsuccessful attempts = 216 - 1 = 215.
Q: Statement : Let there be a signboard also indicating the directions and instructions. Assumptions :a) Signboard can be prepared without using any language.b) Signboard is the only effective tool to indicate directions. 2127 05b5cc72ce4d2b4197774f769
5b5cc72ce4d2b4197774f769- 1Both a and b are not sufficienttrue
- 2Only a is sufficientfalse
- 3Only b is sufficientfalse
- 4Both a and b are sufficientfalse
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Answer : 1. "Both a and b are not sufficient"
Explanation :
Answer: A) Both a and b are not sufficient Explanation: The statement doesn't give any clue to the use of language. Hence a is not implicit. b is also not implicit because in the sentence 'only' indicates false meaning.
Q: A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold? 2125 05b5cc6a7e4d2b4197774cdef
5b5cc6a7e4d2b4197774cdef- 158 lfalse
- 265 lfalse
- 350 ltrue
- 462 lfalse
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Answer : 3. "50 l"
Explanation :
Answer: C) 50 l Explanation: Let the tin contain 5x litres of liquids 5x - 45 x 455x - 45 x 15 + 45 = 25 => 5(4x - 36) = 2(x + 36) => 20x - 180 = 2x + 72 => x = 14 litres Hence, the initial quantity of mixture = 70l Quantity of liquid B = 70 - 45 x 15 + 45 = 50 litres.
Q: What is the Iupac name for the compound shown below. 2125 05b5cc662e4d2b4197774be6b
5b5cc662e4d2b4197774be6b- 11-Bromo-3-chlorocyclohexenefalse
- 22-Bromo-6-chlorocyclohex-1-enefalse
- 36-Bromo-2-chlorocyclohexenefalse
- 43-Bromo-1-chlorocyclohex-1-enetrue
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Answer : 4. "3-Bromo-1-chlorocyclohex-1-ene"
Explanation :
Answer: D) 3-Bromo-1-chlorocyclohex-1-ene Explanation: In chemical nomenclature, the IUPAC nomenclature of organic chemistry is a systematic method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).
Q: Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ? 2123 05b5cc701e4d2b4197774f170
5b5cc701e4d2b4197774f170- 1Rs. 1,24,000false
- 2Rs. 1,44,000true
- 3Rs. 1,32,000false
- 4Rs. 1,62,000false
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Answer : 2. "Rs. 1,44,000"
Explanation :
Answer: B) Rs. 1,44,000 Explanation: Value of Maruti Van, V1 = Rs. 1,96,000Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 yearsLet V2 is the value after depreciation. V2 = V11 - r100tV2 = 196001 - 10071002 V2 = 196000(6/7)(6/7) V2 = (196000x36)/49 = Rs. 1,44,000.

