IIT JEE प्रश्न और उत्तर का अभ्यास करें
8प्र: Two dice are rolled simultaneously. Find the probability of getting the sum of numbers on the on the two faces divisible by 3 or 4? 1259 05b5cc6bbe4d2b4197774d811
5b5cc6bbe4d2b4197774d811- 13/7false
- 27/11false
- 35/9true
- 46/13false
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उत्तर : 3. "5/9"
व्याख्या :
Answer: C) 5/9 Explanation: Here n(S) = 6 x 6 = 36 E={(1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3) ,(6,6),(1,3),(2,2),(2,6),(3,1),(3,5), (4,4),(5,3),(6,2)} => n(E)=20 Required Probability n(P) = n(E)/n(S) = 20/36 = 5/9.
प्र: 5% of a number is 25% more than another number. The difference between the numbers is 96. Then find the value of the numbers? 2324 05b5cc6bbe4d2b4197774d80c
5b5cc6bbe4d2b4197774d80c- 1102 & 6false
- 299 & 3false
- 3104 & 8false
- 4100 & 4true
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उत्तर : 4. "100 & 4"
व्याख्या :
Answer: D) 100 & 4 Explanation: Let the first number be x and the second number be y. Given 5% of x = (25% of y) + y => 5x/100 = 5y/4 => x = 25y ......(1) and also given that, x - y = 96 => x = 96 + y .....(2) From (1)&(2) 25y = 96 + y => 24y = 96 => y = 4 From (1) x = 96 + 4 = 100 Hence, the numbers are 100 & 4.
प्र: 6, 3, 3, 6, 24, ? Find the next number in the given number series? 8102 05b5cc6bbe4d2b4197774d807
5b5cc6bbe4d2b4197774d807- 1192true
- 2186false
- 3182false
- 4194false
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उत्तर : 1. "192"
व्याख्या :
Answer: A) 192 Explanation: Given 6 3 3 6 24 ? Here 6 6 x 0.5 = 3 3 x 1 = 3 3 x 2 = 6 6 x 4 = 24 24 x 8 = 192 The next number in the given series is 192.
प्र: Two pipes A and B can fill a tank in 16 hrs and 12 hrs respectively. The capacity of the tank is 240 liters. Both the pipes are opened simultaneously and closed after 2 hrs. How much more water need to fill the tank? 2288 05b5cc6bbe4d2b4197774d802
5b5cc6bbe4d2b4197774d802- 170 litfalse
- 2170 littrue
- 390 litfalse
- 4190 litfalse
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उत्तर : 2. "170 lit"
व्याख्या :
Answer: B) 170 lit Explanation: Given A alone can fill the tank of capacity 240 lit in 16 hrs. => A can fill in 1 hr = 240/16 = 15 lit => B alone can fill the tank of capacity 240 lit in 12 hrs. => B can fill in 1 hr = 240/12 = 20 lit Now, (A + B) in 1 hr = 15 + 20 = 35 lit But they are opened for 2 hrs => 2 x 35 = 70 lit rae filled Remaining water to be filled in tank of 240 lit = 240 - 70 = 170 lit.
प्र: 92613 x 62742241 = ? + 89 Find the value of '?' 1700 05b5cc6bae4d2b4197774d7fd
5b5cc6bae4d2b4197774d7fd- 1166251false
- 2166259false
- 3166252true
- 4166253false
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उत्तर : 3. "166252"
व्याख्या :
Answer: C) 166252 Explanation: Given 92613 x 62742241 = ? + 89 Using unit digit method, On LHS, 1 x 1 x 1 = 1 sqrt of last digit 1 => it must end with either 9 or 1 so now 1 x 1 = 1 1 x 9 = 9 On RHS, ? + 89 => ? = ...1 - 89 = last digit is 11- 9 = 2 or => ? = ...9 - 89 = last digit is 9 - 9 = 0 Here in the options last digit 2 is option C.
प्र: 56% of 225 + 20% of 150 = ? - 109 Find the value of '?' in the above equation 5358 05b5cc6bae4d2b4197774d7f8
5b5cc6bae4d2b4197774d7f8- 1264true
- 2220false
- 3241false
- 4Nonefalse
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उत्तर : 1. "264"
व्याख्या :
Answer: A) 264 Explanation: Given 56% of 225 + 20% of 150 = ? - 109 we know that a% of b = b% of a Now, 225% of 56 + 20% of 150 = ? - 109 200% of 56 + 25% of 56 + 20% of 150 = ? - 109 112 + 14 + 30 = ? - 109 ? = 112 + 14 + 30 + 109 ? = 264
प्र: On the eve of Christmas, all the things are kept in apple-pie order. 1575 05b5cc6bae4d2b4197774d7ee
5b5cc6bae4d2b4197774d7ee- 1with neatnessfalse
- 2in perfect orderfalse
- 3in jumbled orderfalse
- 4Both A & Btrue
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उत्तर : 4. "Both A & B"
व्याख्या :
Answer: D) Both A & B Explanation:
प्र: A man spend 20% of his monthly salary on his children's education and 50% of his salary on food and transport. After Paying the rent of Rs.1000, he is left with Rs.2000. What is his monthly salary? 1222 05b5cc6bae4d2b4197774d7e9
5b5cc6bae4d2b4197774d7e9- 17000false
- 210000true
- 314000false
- 420000false
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उत्तर : 2. "10000"
व्याख्या :
Answer: B) 10000 Explanation: Let his monthly salary be 'P' 20% on children's education = 20P100 = P5 50% on food and transport = 50P100 = P2 1000 on rent => P - P5 - P2 - 1000 = 2000=> 3P = 30000=> P = 10000 Therefore, his monthly salary = Rs. 10,000

