IIT JEE Practice Question and Answer
8Q: Which property would be classified as expendable? 1907 05b5cc622e4d2b4197774b7f3
5b5cc622e4d2b4197774b7f3- 1Food given to Armyfalse
- 2Cementfalse
- 3Paintfalse
- 4All of the abovetrue
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "All of the above"
Explanation :
Answer: D) All of the above Explanation: Expendable properties are those properties that are consume in use or that lose their identity in use. It also include those properties that become an integral part of other property when put to use and those properties which have an expected service life of less than one year.
Q: Fa Hien visited india during the reign of 1906 05b5cc666e4d2b4197774bf03
5b5cc666e4d2b4197774bf03- 1Harshavardhanafalse
- 2Chandragupta Mauryafalse
- 3Ashokafalse
- 4Chandragupta Vikramadityatrue
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "Chandragupta Vikramaditya"
Explanation :
Answer: D) Chandragupta Vikramaditya Explanation: Fahien came to India during the reign of┬аChandragupta Vikramaditya.
Q: Magnetic domains normally occur in 1906 05b5cc61ee4d2b4197774b7a7
5b5cc61ee4d2b4197774b7a7- 1copperfalse
- 2silverfalse
- 3irontrue
- 4All of the abovefalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "iron"
Explanation :
Answer: C) iron Explanation: A magnetic domain is a region within a magnetic material in which the magnetization is in a uniform direction. This means that the individual magnetic moments of the atoms are aligned with one another and they point in the same direction.
Q: 1, 2, 8, 33, ? Find the next number in the given series? 1906 05b5cc6bae4d2b4197774d7e4
5b5cc6bae4d2b4197774d7e4- 1148true
- 2145false
- 3143false
- 4141false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "148"
Explanation :
Answer: A) 148 Explanation: 1 x 1 + 1 x 1 = (1 + 1) = 2 2 x 2 + 2 x 2 = (4 + 4) = 8 8 x 3 + 3 x 3 = (24 + 9) = 33 33 x 4 + 4 x 4 = (132 + 16) = 148 148 x 5 + 5 x 5 = (740 + 25) = 765.
Q: What is the name of the World's smallest republic which has an area of 21 sq.km.? 1906 05b5cc6a8e4d2b4197774ceb1
5b5cc6a8e4d2b4197774ceb1- 1Palermofalse
- 2Naurutrue
- 3Vatican Cityfalse
- 4Namurfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "Nauru"
Explanation :
Answer: B) Nauru Explanation:
Q: What are the Multiples of 6 and the Common Multiples of 4 and 6? 1906 05b5cc6b1e4d2b4197774d303
5b5cc6b1e4d2b4197774d303- 112, 34, 42false
- 212, 18, 36,true
- 36, 4, 14false
- 44, 8, 16false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "12, 18, 36,"
Explanation :
Answer: B) 12, 18, 36, Explanation: The┬аMultiples of 6 are 6, 12, 18, 24, 30, 36, 42, 48, 54, 60. The┬аMultiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60. The Common Multiples of 4 & 6 upto 60 numbers are given as 12, 24, 36, 48, 60.
Q: The price of pulses has increased by 25%. The percentage of reduction that a family should effect in the use of pulses so as not to increase the expenditure on this account is ? 1906 05b5cc75ce4d2b4197774fc3e
5b5cc75ce4d2b4197774fc3e- 116%false
- 220%true
- 384%false
- 472%false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "20%"
Explanation :
Answer: B) 20% Explanation: Reduction in consumption= P100+P┬аX 100%= 25100+25┬аX 100%= 20%
Q: If two cards are taken one after another without replacing from a pack of 52 cards. What is the probability for the two cards be Ace ? 1906 05b5cc74ae4d2b4197774fa81
5b5cc74ae4d2b4197774fa81- 151/1221false
- 242/221false
- 31/221true
- 452/1245false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "1/221"
Explanation :
Answer: C) 1/221 Explanation: Total Combination of getting a card from 52 cards =┬аC152 Because there is no replacement, so number of cards after getting first card= 51 Now, Combination of getting an another card=┬аC151 Total combination of getting 2 cards from 52 cards without replacement= (C152├ЧC151)┬а There are total 4 Ace in stack. Combination of getting 1 Ace is =┬аC14 ┬а Because there is no replacement, So number of cards after getting first Ace = 3 Combination of getting an another Ace =┬аC13 Total Combination of getting 2 Ace without replacement=C14├ЧC13 Now,Probability of getting 2 cards which are Ace =C14├ЧC13C152├ЧC151┬а= 1/221.

