IIT JEE प्रश्न और उत्तर का अभ्यास करें
8प्र: Tertiary structure is NOT directly dependent on 1902 05b5cc694e4d2b4197774c4ac
5b5cc694e4d2b4197774c4ac- 1hydrogen bondsfalse
- 2ionic bondsfalse
- 3peptide bondstrue
- 4hydrophobic interactionsfalse
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उत्तर : 3. "peptide bonds"
व्याख्या :
Answer: C) peptide bonds Explanation:
प्र: Who makes it has no need of it. What is it? 1902 05b5cc655e4d2b4197774bd49
5b5cc655e4d2b4197774bd49- उत्तर देखेंउत्तर छिपाएं
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उत्तर :
व्याख्या :
A Coffin.
प्र: What kind of pet always stays on the floor? 1902 05b5cc60de4d2b4197774b631
5b5cc60de4d2b4197774b631- 1Catfalse
- 2Dogfalse
- 3Carpettrue
- 4All of the abovefalse
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उत्तर : 3. "Carpet"
व्याख्या :
Answer: C) Carpet Explanation: A Carpet is the pet which always stays on the floor.
प्र: From a group of 7 boys and 6 girls, five persons are to be selected to form a team, so that at least 3 girls are there in the team. In how many ways can it be done? 1901 05b5cc675e4d2b4197774c115
5b5cc675e4d2b4197774c115- 1427false
- 2531true
- 3651false
- 4714false
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उत्तर : 2. "531"
व्याख्या :
Answer: B) 531 Explanation: Given in the question that, there are 7 boys and 6 girls. Team members = 5 Now, required number of ways in which a team of 5 having atleast 3 girls in the team = 6C3 x 7C2 + 6C4 x 7C1 + 6C5= 6x5x43x2x1 x 7x62x1 + 6x5x4x34x3x2x1 x 7 + 6x5x4x3x25x4x3x2x1= 420 + 105 + 6= 531.
प्र: K and L start a business jointly. K invests Rs.16000 for 8 months and L remains in the business for 4 months. Out of the total profit L claims 2/7th share. How much money is contributed by L? 1900 05b5cc767e4d2b4197774fe22
5b5cc767e4d2b4197774fe22- 1Rs. 13,204false
- 2Rs. 14,521false
- 3Rs. 12,800true
- 4Rs. 15,000false
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उत्तर : 3. "Rs. 12,800"
व्याख्या :
Answer: C) Rs. 12,800 Explanation: Given share of L is 2/7 th of profit. Then, their profits are divided in to 5:2 ratio. Ratio of K and L is 16000×8x×4=52 x = Rs. 12,800.
प्र: What should come in place of the question mark(?) in the following questions ? 316 + 412 - 223 - 11112 = ? 1899 05b5cc6fbe4d2b4197774f0ec
5b5cc6fbe4d2b4197774f0ec- 11 7/12false
- 21 5/12false
- 33 7/12false
- 43 1/12true
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उत्तर : 4. "3 1/12"
व्याख्या :
Answer: D) 3 1/12 Explanation: ? = (3 + 4 - 2 - 1) + ( 1/6 + 1/2 - 2/3 - 11/12) = 4 + [(2+6-8-11)/12] = 4 - (11/12 )= 31/12.
प्र: The purpose of choke in tube light is 1899 05b5cc6a6e4d2b4197774cd28
5b5cc6a6e4d2b4197774cd28- 1Induce high voltagetrue
- 2Induce low resistancefalse
- 3Induce high resistancefalse
- 4Induce low voltagefalse
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उत्तर : 1. "Induce high voltage"
व्याख्या :
Answer: A) Induce high voltage Explanation: When the switch is ON, in a tube light choke is nothing but the coil/ballast ( inductor) which is used to induce the high voltage across it. as we know that inductor has property to induce high voltage for the brief period of time, this high voltage is required to ionize the gases in the starter. Then gas inside the starter gets ionized due to this full voltage and heats the bimetallic strip that is caused to be bent to connect to the fixed contact. Current starts flowing through the starter. Although the ionization potential of the neon is the little bit more than that of the argon but still due to small electrode gap high voltage gradient is appeared in the neon bulb and hence glow discharge is started first in a starter. As voltage gets reduced due to the current causes a voltage drop across the inductor, the strip cools and breaks away from the fixed contact. At that moment a large L di/dt voltage surge comes across the inductor at the time of breaking. This high valued surge comes across the tube light electrodes and strikes penning mixture (mixture argon gas and mercury vapor). Gas discharge process continues and current gets the path to flow through the tube light gas only due to low resistance as compared to the resistance of starter.
प्र: A man covers half of his journey by train at 60 km/hr, half of the remaining by bus at 30 km/hr and the rest by cycle at 10 km/hr. Find his average speed during the entire journey? 1898 05b5cc6ade4d2b4197774d12f
5b5cc6ade4d2b4197774d12f- 132 kmphfalse
- 220 kmphfalse
- 318 kmphfalse
- 424 kmphtrue
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उत्तर : 4. "24 kmph"
व्याख्या :
Answer: D) 24 kmph Explanation: Let the total distance of the journey of a man = d kms Now, the average speed of the entire journey = dd120 + d120 + d40 = 24 kmph.

