IIT JEE Practice Question and Answer

Q: Largest Mint in India is at 1942 0

  • 1
    Mumbai
    Correct
    Wrong
  • 2
    Hyderabad
    Correct
    Wrong
  • 3
    Noida
    Correct
    Wrong
  • 4
    Kolkata
    Correct
    Wrong
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Answer : 4. "Kolkata"
Explanation :

Answer: D) Kolkata Explanation: The Largest Mint in India is Kolkata Mint.   Government of India operates 4 Mints in the country for the production of Coins. They are at Hyderabad, Telangana Mumbai, Maharashtra Kolkata, West Bengal Noida, Uttar Pradesh.

Q: What animal has the highest blood pressure? 1939 0

  • 1
    Elephant
    Correct
    Wrong
  • 2
    Giraffe
    Correct
    Wrong
  • 3
    Lion
    Correct
    Wrong
  • 4
    Rabbit
    Correct
    Wrong
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Answer : 2. "Giraffe"
Explanation :

Answer: B) Giraffe Explanation: Giraffe has the highest blood pressure among animals.  This is due to the fact that there is a large pressure drop (~100 mmhg) as the blood is transported from the heart, up the neck, to the brain. This is about twice the normal blood pressure of humans (120/80 mmhg).

Q: In terms of territorial extent, the largest district of India is located in which of the following states ? 1939 0

  • 1
    Rajasthan
    Correct
    Wrong
  • 2
    Tamil Nadu
    Correct
    Wrong
  • 3
    Jammu & Kashmir
    Correct
    Wrong
  • 4
    Gujarat
    Correct
    Wrong
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Answer : 4. "Gujarat"
Explanation :

Answer: D) Gujarat Explanation: Kachchh district is the largest in India in terms of territorial extent, located in the state of Gujarat.The second largest district is Leh in Jammu & Kashmir.

Q: Khushi bought the bangles of equal number of Rs. 34 per piece, Rs. 42 per piece and Rs. 6 per piece. She spends total Rs. 1722 on all types of bangles. How many bangles did she buy of each type  ? 1938 0

  • 1
    27
    Correct
    Wrong
  • 2
    13
    Correct
    Wrong
  • 3
    17
    Correct
    Wrong
  • 4
    21
    Correct
    Wrong
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Answer : 4. "21"
Explanation :

Answer: D) 21 Explanation: Let number of bangles kushi purchase of each type = x From the given data, 34x + 42x + 6x = 1722 x = 1722/82 = 21.

Q: How are ip addresses available to the internet classified? 1938 0

  • 1
    Static
    Correct
    Wrong
  • 2
    Public
    Correct
    Wrong
  • 3
    Private
    Correct
    Wrong
  • 4
    None of the above
    Correct
    Wrong
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Answer : 2. "Public"
Explanation :

Answer: B) Public Explanation: An IP address (internet protocol address) is a numerical representation that uniquely identifies a specific interface on the network. Addresses in IPv4 are 32-bits long. This allows for a maximum of 4,294,967,296 (2^32) unique addresses. Addresses in IPv6 are 128-bits, which allows for 3.4 x 1038 (2^128) unique addresses.   IP addresses available to the internet are classified as Public.

Q: The more you take the more you leave behind. What is it? 1938 0

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Answer :
Explanation :

Footsteps.  Yes, as you walk forward, you will leave the footstep behind you.

Q: A person in a bet 40 shots taken. 50p for a hit, 10p for a miss.(he have to give). Finally he has Rs.5. How many hits he have ? 1938 0

  • 1
    15
    Correct
    Wrong
  • 2
    20
    Correct
    Wrong
  • 3
    25
    Correct
    Wrong
  • 4
    30
    Correct
    Wrong
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Answer : 1. "15"
Explanation :

Answer: A) 15 Explanation: Let number of hit shots be 'X'Let number of miss shots be 'Y'Given X + Y = 40....(1)50X - 10Y = 500.....(2)Solving 1 and 2, we getX = 15 and Y = 25Therefore, number of hits = 15

Q: It costs Rs. p each to send the first thousand messsages and Rs. q to send each subsequent one . If r is greater than 1,000, how many Rupees will it cost to send r messages ? 1938 0

  • 1
    1000 (r - p) + pq
    Correct
    Wrong
  • 2
    1000 p + qr
    Correct
    Wrong
  • 3
    1000 (r - q) + pr
    Correct
    Wrong
  • 4
    1000(p - q) + qr
    Correct
    Wrong
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Answer : 4. "1000(p - q) + qr"
Explanation :

Answer: D) 1000(p - q) + qr Explanation: We need to find the total cost to send r messsages, r > 1000. The first 1000 messsages will cost Rs.p each (Or)  The total cost of first 1000 messsages = Rs.1000p The remaining (r - 1000) messsages will cost Rs.q each (Or) The cost of the (r - 1000) = Rs.(r - 1000)y   Therefore, total cost = 1000p + rq - 1000q = 1000(p - q) + qr

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